Staff Induction System - No idea where to go from here!!!

Posted on 16th Feb 2014 07:03 pm by admin

Hi there, I'm pretty new to PHP and Mysql so could really do with being pointed in the right direction with this problem I have.

I am trying to set up a system induct new members of staff onto their training programme.

First I have created a table 'induction_course_dates' of all the course dates and induction_course_titles of all the different courses.

These are the 2 queries I have made on the database


///////////////////////// Make the course title query //////////////////////////////
$q_courses = "SELECT * FROM induction_course_titles";
$result_courses = mysqli_query($dbc, $q_courses);
$row_courses = mysqli_fetch_array($result_courses);


///////////////////////// Make the course date query //////////////////////////////
$q_date = "SELECT * FROM induction_course_dates WHERE DATE(course_date)>='$today' AND course='$courseID' ORDER BY course_date ASC LIMIT 4";
$result_date = mysqli_query($dbc, $q_date);
$row_date = mysqli_fetch_array($result_date);

Obviously in the second query '$courseID' does not have a value so won't actually return anything but I don't know how to loop it through all of the induction_course_titles id's.

For example if it the query read...

///////////////////////// Make the course date query //////////////////////////////
$q_date = "SELECT * FROM induction_course_dates WHERE DATE(course_date)>='$today' AND course='2' ORDER BY course_date ASC LIMIT 4";
$result_date = mysqli_query($dbc, $q_date);
$row_date = mysqli_fetch_array($result_date);

...then this would return the results I'm looking for but there are 25 different courses.


I want the final output to appear as below

The user will select a date from the next four available

<table border="0" cellpadding="0" cellspacing="0">
<tr>
<td>Course 1</td>
<td>
<select name="select" id="select">
<option value="date1">Date 1</option>
<option value="date2">Date 2</option>
<option value="date3">Date 3</option>
<option value="date4">Date 4</option>
</select>
</td>
</tr>
<tr>
<td>Course 2</td>
<td><select name="select2" id="select2">
<option value="date1">Date 1</option>
<option value="date2">Date 2</option>
<option value="date3">Date 3</option>
<option value="date4">Date 4</option>
</select></td>
</tr>
<tr>
<td>Course 3</td>
<td><select name="select3" id="select3">
<option value="date1">Date 1</option>
<option value="date2">Date 2</option>
<option value="date3">Date 3</option>
<option value="date4">Date 4</option>
</select></td>
</tr>
<tr>
<td>&nbsp;</td>
<td><input type="submit" name="button" id="button" value="Submit" /></td>
</tr>
</table>

Can anybody help?!!!! PLEASE!!!!!

Your Answer:

Login to answer

Other forums

Change log of Cost centre change in Plant maintenance order
Hi,
How to view Change log of Cost centre in Plant maintenance order. Not visible thru 'Docume

array_map() probably obvious mistake
The code below is part of a class to escape strings, but should also accept an array, using array_ma

some questions
Hello,

I am looking for the answers for following questions:

1) Does PHP support overl

Detail Expenses Report by Cost Center
I would like to obtain a report out of SAP that shows a list of expenses by cost center that shows t

Array becomes unset by itself?
Hi,

I have a bit of experience with PHP but not extensive. It seems I cannot store any items

help with email script...
hey

I need help with my mail script

when the form on http://www.mcgdesignstudio.com/c

urldecode question
How would I format this line of code properly?

<?php echo urldecode($_GET['Title']); ?

Help building / using array
First - this is a cross-posting, if this is wrong I apologise! What started out as a MySQL query que

My XSRF Prevention code isn't working
First of all, thanks for the generous help you guys have given me in the past on this forum.
Seco

mysql_real_escape_string making variable equal nothing
i post a form and i post the variable:
Code: $var = $_POST[variable];then i echo $var its what i