MYSQL gen help


Posted on 16th Feb 2014 07:03 pm by admin

This is my Mysql gen. can anyone tell me why this echos

MID(networkset.networkid, 3, 3) AS "MNC" SELECT FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid

Did you know?Explore Trending and Topic pages for more stories like this.
and not

SELECT MID(networkset.networkid, 3, 3) AS "MNC" FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid

heres the code:

$arr = array($date,$time,$latandlong,$satdata,$MCC,$MNC,$MCCMNC,$name,$callid,$lac,$bsic,$arfcn,$relvl,$c1,$c2,$rxq,$timing,$numres,$audio,$video,$image);

function select($arr){


foreach ($arr as $key => $value) {
if (is_null($value)) {
unset($arr[$key]);
}
}
$last_item = end($arr);
$last_item = each($arr);
reset($arr);
foreach($arr as $key => $value){
if($value == $last_item['value'] && $key == $last_item['key']){
echo ',';
}
print $value;
}
}

//echo '
';

/* FROM */
$fromdefault1=" scan JOIN gps ON scan.gpsid = gps.gpsid";
$fromdefault2=" JOIN gsmscanset ON scan.scanid = gsmscanset.scanid";
$fromdefault3="JOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid";
/* WHERE */
$wheredefault="scan.typeid = 4 AND
gsmcell.cellid = gsmcell.servingcellid";
if (isset($datebetween, $dateand)){$datesearch=' AND DATE(gps.date) BETWEEN '.$datebetween.' AND '.$dateand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($lat, $long)){$latandlongsearch=' AND DATE(gps.time) BETWEEN '.$lat.' AND '.$long.'';}


/* Query */
$query = "
SELECT ".select($arr)."
FROM ".$fromdefault1.$namefrom.$fromdefault2.$fromdefault3.$numresform1.$numresform2.$audiofrom.$videofrom.$imagefrom."
WHERE ".$wheredefault.$datesearch.$timesearch.$latandlongsearch . "
";
echo $query;
}

Thank
No comments posted yet

Your Answer:

Login to answer
204 Like 14 Dislike
Previous forums Next forums
Other forums

$variable $variables type question
I need to be able to designate an array element dynamically, so I thought to use a variable variable

Create a form of 2 numbers input and find the greatest.
Hi, everybody.

I have a homework in my training of php, which ask you to make a form that ask

Read from a text file after a specific word
Hi all.

I have a text file that looks like the one below.
I know how to open the text fi

modifying query string with no page refresh
Hi everybody,
I've tried to get info about my problem all over the internet but i didn't find out

There was a problem with the request. (Code: 0)
Any Idea what could cause this? I get it randomly at best. But with both IE and FF. It derives from

Stopping page post back
I have few literal contriols in my page and a repeater too. But inspite of using update panel, postb

Array help
Hello i got this code to fetch data from database but it is not working it displays
7
Array

Snapshot from video
anyone knw how to make a snapshot maker from avi n mkv format.
for example if i give a direct lin

array_diff weirdness
I'm using the following bit of code

$diff = array_diff($pids, $pidlist);
$diff = array_va

Warning: session_start() [function.session-start]: Cann.....
hi, can someone help me with this? I keep getting this error....

Warning: session_start() [fu

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash