MYSQL gen help

Posted on 16th Feb 2014 07:03 pm by admin

This is my Mysql gen. can anyone tell me why this echos

MID(networkset.networkid, 3, 3) AS "MNC" SELECT FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid

and not

SELECT MID(networkset.networkid, 3, 3) AS "MNC" FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid

heres the code:

$arr = array($date,$time,$latandlong,$satdata,$MCC,$MNC,$MCCMNC,$name,$callid,$lac,$bsic,$arfcn,$relvl,$c1,$c2,$rxq,$timing,$numres,$audio,$video,$image);

function select($arr){


foreach ($arr as $key => $value) {
if (is_null($value)) {
unset($arr[$key]);
}
}
$last_item = end($arr);
$last_item = each($arr);
reset($arr);
foreach($arr as $key => $value){
if($value == $last_item['value'] && $key == $last_item['key']){
echo ',';
}
print $value;
}
}

//echo '
';

/* FROM */
$fromdefault1=" scan JOIN gps ON scan.gpsid = gps.gpsid";
$fromdefault2=" JOIN gsmscanset ON scan.scanid = gsmscanset.scanid";
$fromdefault3="JOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid";
/* WHERE */
$wheredefault="scan.typeid = 4 AND
gsmcell.cellid = gsmcell.servingcellid";
if (isset($datebetween, $dateand)){$datesearch=' AND DATE(gps.date) BETWEEN '.$datebetween.' AND '.$dateand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($lat, $long)){$latandlongsearch=' AND DATE(gps.time) BETWEEN '.$lat.' AND '.$long.'';}


/* Query */
$query = "
SELECT ".select($arr)."
FROM ".$fromdefault1.$namefrom.$fromdefault2.$fromdefault3.$numresform1.$numresform2.$audiofrom.$videofrom.$imagefrom."
WHERE ".$wheredefault.$datesearch.$timesearch.$latandlongsearch . "
";
echo $query;
}

Thank

Your Answer:

Login to answer

Other forums

LinkedList help
Ok so I just learned quickly about lists, so I have a not too hard project I think, but am having a

PHP Surveys
I really would like some advice.

If you have a client come to you asking for a survey to be d

Edit MySQL Row Using PHP and HTML Form
Hello,

Here's what I'm trying to do. Build a page where a user enters a MySQL row number in.

problems with contact forms that are only protected against SQL injections
What could be a potential problem with contact forms that are only protected against SQL injections

whats wrong with my code please help!!!
this is the error


Warning: mysql_close(): supplied argument is not a valid MySQL-Link res

Code clarification
Hi

In the following code what could be the "search_print()" and where it could be

Nested (echoed) php running wrong script
Got a problem with a php website I'm creating.

In a nutshell, the first page is entirely html

PHP submit form script causing blank page
Im trying to submit a form using this script, however nothing shows up on the page, does anyone know

GMail like Chat in ASP.NET
Hi,Can anyone suggest me, how to incorporate GMail like chat in my existing ASP.Net application.I wa

How to assign a textbox value to PHP variable??
Hi ! Can any one help me out as quickly as possible. As I m new to PHP.
Plz tell me how to assign