MYSQL gen help


Posted on 16th Feb 2014 07:03 pm by admin

This is my Mysql gen. can anyone tell me why this echos

MID(networkset.networkid, 3, 3) AS "MNC" SELECT FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid

and not

SELECT MID(networkset.networkid, 3, 3) AS "MNC" FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid

heres the code:

$arr = array($date,$time,$latandlong,$satdata,$MCC,$MNC,$MCCMNC,$name,$callid,$lac,$bsic,$arfcn,$relvl,$c1,$c2,$rxq,$timing,$numres,$audio,$video,$image);

function select($arr){


foreach ($arr as $key => $value) {
if (is_null($value)) {
unset($arr[$key]);
}
}
$last_item = end($arr);
$last_item = each($arr);
reset($arr);
foreach($arr as $key => $value){
if($value == $last_item['value'] && $key == $last_item['key']){
echo ',';
}
print $value;
}
}

//echo '
';

/* FROM */
$fromdefault1=" scan JOIN gps ON scan.gpsid = gps.gpsid";
$fromdefault2=" JOIN gsmscanset ON scan.scanid = gsmscanset.scanid";
$fromdefault3="JOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid";
/* WHERE */
$wheredefault="scan.typeid = 4 AND
gsmcell.cellid = gsmcell.servingcellid";
if (isset($datebetween, $dateand)){$datesearch=' AND DATE(gps.date) BETWEEN '.$datebetween.' AND '.$dateand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($lat, $long)){$latandlongsearch=' AND DATE(gps.time) BETWEEN '.$lat.' AND '.$long.'';}


/* Query */
$query = "
SELECT ".select($arr)."
FROM ".$fromdefault1.$namefrom.$fromdefault2.$fromdefault3.$numresform1.$numresform2.$audiofrom.$videofrom.$imagefrom."
WHERE ".$wheredefault.$datesearch.$timesearch.$latandlongsearch . "
";
echo $query;
}

Thank

No comments posted yet

Your Answer:

Login to answer
204 Like 14 Dislike
Previous forums Next forums
Other forums

Taxonomy? Classification? Categorisation?
Not sure if there is a way around this classification problem
I have a supplier who produces

Remove values in array2 from array1
I have two arrays.

Array 1 is where the array key holds various different numbers. For exampl

Select all entries from database that include a phrase
I have a database of clubs - one of the categories is meeting time and place
I would like to have

PHP error. Need help urgently
Hi,

I am programming a php site and have a problem that i just cant find out how to fix. When

[PHP HELP] Php order form.
Hello to everyone @ phpfreaks. Im new to this site and hope to learn lots of things here.

Fir

Using CSS to format MySQL query
Hi,

If i want to have a news page on my site, which displays all records of a table in descen

The repetition structure: the while statement not working
New programming student, have assignment as follows:
A restaurant has 4 lunch combos for custom

question about stripslashes and real_escape_string
im cleaning up an old app that I wrote fixing some of the vulernabilities from attacks.

I hav

IP Logger for Voting Script
Can anybody help me place an IP logger into my voting script?
I know that maybe it is not as secu

[newb] Image hosting help.
Hey there, I'm new to php, I know some basics and i can code PWN, I'm only 14 but I'm interested in

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash