Sql and php order list script problems


Posted on 16th Feb 2014 01:33 pm by admin

Hi im having a few problems with trying to get the coding right on a orders list ive done (or trying to do) for a custom shopping cart im making... For some reason it comes up with all the orders in stead of 1. i.e. If there i start from scratch ill have order number 1 which will have the order in but if i create another order it displays order number 2 twice with both the customers details on...

Heres the code:
Code: <?php
include ('../includes/db.php');
include('search.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Orders</title>
</head>


<body>

<a href="orders.php">Refresh</a> || <a href="admin.php">Back to Admin</a> <br/><br/>

<form method="GET" action="<?php echo $_SERVER['PHP_SELF'];?>" name="searchForm">
<input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" />
<input type="submit" name="submit" value="Search!" /> ||
First Name: <input type="checkbox" name="firstname" value="on" <?php echo isset($_GET['firstname'])?"checked":''; ?> /> ||
Last Name: <input type="checkbox" name="lastname" value="on" <?php echo isset($_GET['lastname'])?"checked":''; ?> /> ||
House Name: <input type="checkbox" name="address1" value="on" <?php echo isset($_GET['address1'])?"checked":''; ?> /> ||
Post Code: <input type="checkbox" name="zip" value="on" <?php echo isset($_GET['zip'])?"checked":''; ?> />
</form>
<br />
<?php echo (count($error) > 0)?"The following had errors:<br /><span id="error">" . implode("<br />", $error) . "</span><br /><br />":""; ?>
<?php echo (count($results) > 0)?"Your search for '{$searchTerms}' returned:<br /><br />" . implode("", $results):""; ?>
<?php

$result = mysql_query("SELECT * FROM customers INNER JOIN order_detail ORDER BY orderid DESC");

echo "<table border='1'>
<tr>
<th>Order Number</th>
<th>Firstname</th>
<th>Lastname</th>
<th>Address 1</th>
<th>Address 2</th>
<th>City</th>
<th>State</th>
<th>Post Code</th>
<th>Phone</th>
<th>Payment</th>
<th>Price</th>
<th>Total</th>
<th>Payed</th>
</tr>";

while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['orderid'] . "</td>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['address1'] . "</td>";
echo "<td>" . $row['address2'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['state'] . "</td>";
echo "<td>" . $row['zip'] . "</td>";
echo "<td>" . $row['phone'] . "</td>";
echo "<td>" . $row['payment'] . "</td>";
echo "<td>£" . $row['price'] . "</td>";
echo "<td>£" . $row['total'] . "</td>";
echo "<td>" . $row['payed'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close();
?>
</body>
</html>
Im completely stuck on this as im no php or mysql gurru...
so any help or info would be greatfull..

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