user validation always displaying invalid ? please help
Posted on
16th Feb 2014 07:03 pm by
admin
Hello,
I have 2 accounts and there is a field in mysql called validated it can be either "true" or "false"
I tried writing a code so when the user logs in if the user is validated meaning
$username = $_POST['username'];
$validated = true
$validation = a mysql query that selects validated from members where username = $username
$validated == $validation
and I have to accounts made
1 account username is "google" its validation is set to false
2nd account username is "jaydesigns" its validation is set to true
but when I login both come up as not validated
here is the page code:
Code: <?
include_once"config.php";
$final_report = "Please complete all the fields below..";
if(isset($_POST['login'])){
$username= trim($_POST['username']);
$password = trim($_POST['password']);
if($username == NULL OR $password == NULL){
$final_report = "Please complete all the fields below..";
}else{
$check_user_data = mysql_query("SELECT * FROM `members` WHERE `username` = '$username'") or die(mysql_error());
if(mysql_num_rows($check_user_data) == 0){
$final_report = "This username does not exist..";
}else{
$get_user_data = mysql_fetch_array($check_user_data);
if($get_user_data['password'] == $password){
$start_idsess = $_SESSION['username'] = "".$get_user_data['username']."";
$start_passsess = $_SESSION['password'] = "".$get_user_data['password']."";
$validation = mysql_query("SELECT validated FROM `members` WHERE `username` = '$username'") or die(mysql_error());
$validated = "true";
if($validation == $validated) {
$final_report ="You are now logged in $start_idsess ";
} else {
$final_report ="Your account is not validated $start_idsess,
Please Activate your account from the email you recieved from us.
If you did not recieve an email click <a href='./activate-send.php'>here</a> to resend the email
You will be logged out Now";
session_unset('username');
session_unset('password');
}
?>
<meta http-equiv="Refresh" content="0; URL=./members.php">
<?php
}}}}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Funky Vision Membership Script</title>
</head>
<body><form action="" method="post">
<table width="312" align="center">
<tr><td colspan='2'><?php echo "$final_report" ?></td></tr><tr>
<tr>
<td width="120">Username:</td>
<td width="180"><input type="text" name="username" size="30" maxlength="25"></td>
</tr>
<tr>
<td>Password:</td>
<td><input type="password" name="password" size="30" maxlength="25"></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="login" value="Login" /></td>
</tr>
</table>
</form>
</body>
</html>
No comments posted yet
Your Answer:
Login to answer
209 
12 
Other forums
InternetOpenUrl() Invalid cert
Hi all,
Does anyone know how to prevent calls to InternetOpenUrl() from failing with erro
Match stored value with the current value in a loop
Hello,
I have a MySQL db were I store articles in.
I have a form to fill these article
AUTONUMBER PROBLEM
Hello Everyone,
My name is Jones and i am new to this forum and to oracle. I am using ora
query based on 2 conditions
I want to select if the doc_type is either s OR f but this doesn't work:
Code: [Select]$query
Why do I get this error?
Error:
Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or
Ajax not working on IE 6 for Windows CE
I've created a webpage which uses the classis Ajax in following format:view plaincopy to clipboardpr
switch not getting value
what am i doing wrong?
i want to populate the country list according to the category
i want to
Business Health Check
Hello
I need to create an online business health check for a client it will be multiple choi
How to show a complete textarea ??
I enter Client Case Notes notes in a textarea field on a PHP form. The field is 5 rows deep and 70 c
Not adding to db
Hi, I can't figure out why it won't add the record to the database. It's just a simple form to get
