using variables in another page


Posted on 16th Feb 2014 07:03 pm by admin

I have a test database set up on localhost. I have a form that I can type a name into, hit the button and it puts the name into the database and into a list on my page. it works fine. Now, I wanted to make a drop down list with all the names so that you could select one to remove that name from the database. So I did this

Code: [Select]<form>
<select>
<option><?php echo $name ?></option>
</select>
</form>

What that did was list the very last name in the list. What I thought it would do was list all the names based on the loop that I have set up to read all the names from the database. which is this

Code: [Select]$mysql = new mysqli('localhost', 'myusername', 'mypass', 'mydatabase') or die('not working');

$result = $mysql->query("SELECT * FROM myTable") or die($mysql->error);

if($result)
{
while($row = $result->fetch_object())
{
$name = $row->names;
echo $name . "<br />";
}
}

Now the while loop is in a file I called results and it is included in the index page with an include. I thought this would give me access to the $name variable and allow me to use it the same way it's being used in the loop. of course I was wrong, so how do I use it the same way?

No comments posted yet

Your Answer:

Login to answer
232 Like 38 Dislike
Previous forums Next forums
Other forums

Is there a quick way to do this?
Hi all,

I need to create a mysql table from php that goes a little something like this

Will this protect from mysql injection?
I do not want anything like DROP TABLE to work or any type of coding..

Heres my code.. is it

reading xml faster than DB call?
I am trying to optimize a high traffic website, and I enabled a feature where there are three photos

Price in PR
Dear Experts,
Why we have to enter the price in the PR, and why there is no free goods indicato

MySQL noob question
hi guys

I have a simple mysql table set up, along the lines of

Col 1 - Col 2 - Date_l

Problems with returning true or false in eval()'d code
Hi guys,

Would appreciate some help with a problem when running eval() on a function that sho

rookie looking for help coding a CSS form with PHP
I'm trying to figure out how to add PHP code to my xhtml form so that it is a working form embedded

how to get values from $_Post with onchange="form.submit();"?
Hi, I have a form that submit to itself with a file upload field and two other hidden field values.<

Take info from one coloum and move to another
Hi all,

I have this:
Code: [Select]$array = "SELECT stock_id FROM stocks WHERE stock_

Fatal error: Call to a member function fetchrow() on a non-object in C:xamppht
okay i have this query and everytime i add `item_id`=? to it... it gives me the error in the title..

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash