A Few Questions

Posted on 16th Feb 2014 07:03 pm by admin

Hi, I want to ask a few questions that I can't seem to find..

1) I'm creating a "shortcut" system on my website, where users can add shortcuts from pages by clicking the link and it will write the URL and the users ID into the database, the only problem I don't know how PHP can grab the URL of the page?

2) I can't seem to get cookies working on my site:

Code: //get the posted values
$email1=($_POST['user_name']);
$email=htmlspecialchars($_POST['user_name'],ENT_QUOTES);
$pass=sha1($_POST['password']);
$post_autologin=($_POST['checkbox']);

//MYSQL
$abc = mysql_query("SELECT * FROM accounts WHERE email='".$email1."'") or die(mysql_error());
$a = mysql_fetch_array($abc);

//Select whatever..
$sql="SELECT user_id, email, password FROM accounts WHERE email='".$email."'";
$result=mysql_query($sql);
$row=mysql_fetch_array($result);

$userid = $a['user_id'];
$displayname = $a['display_name'];

$_SESSION['user_id']=$userid;
$_SESSION['email']=$email;

//if username exists
if(mysql_num_rows($result)>0)
{
//compare the password
if(strcmp($row['password'],$pass)==0)
{
echo "yes";
if($post_autologin == YES)
{
$password_hash = sha1($pass); // will result in a 32 characters hash

setcookie ($cookie_name, 'usr='.$email.'&hash='.$pass, time() + $cookie_time);
}
$_SESSION['user_id']=$userid;
$_SESSION['email']=$email;
$_SESSION['dname']=$displayname;

}
else
echo "no";
}
else
echo "no"; //Invalid Login


?>
Is this correct? Its a Ajax login I found but when I check the checkbox and close the browser it logs me out.. I use $_SESSION['user_id] in places where I want stuff to show for logged in users, where do I put $_COOKIE['user_id']???

http://mymediaupload.com/media.php?v=130 if you look on this page and click "More by Cheryl Cole" it shows the current song, how would I get it to view the rest of the songs by that artist and not the one thats playing?

This is what I have..

Code: if($_GET['morelikethis'])
{
$name2 = mysql_real_escape_string($_GET['morelikethis']);
$s = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC LIMIT 0,6") or die(mysql_error());
$t = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC") or die(mysql_error());
$u = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC LIMIT 1,5") or die(mysql_error());
$len = 19;

while($x = mysql_fetch_array($s))
{
$q3 = mysql_query("SELECT * FROM accounts WHERE user_id = ".$x['musicuploaderid']."") or die(mysql_error());
$q4 = mysql_fetch_array($q3);
echo "<table border="0" width="100%" cellspacing="0" cellpadding="0">
<tr>
<td width="40"><img src="".$x['musicalbumart']."" height="40" width="40"></td><td width="5"></td>";
echo "<td align="left" valign="top"><a target="_top" title="".$x['musictitle']." - ".$x['musicartist']."" href="media.php?v=".$x['musicid']."">";
echo (strlen($x['musictitle']) > $len ? substr($x['musictitle'], 0, $len).".." : $x['musictitle']);
echo "
";
echo (strlen($x['musicartist']) > $len ? substr($x['musicartist'], 0, $len).".." : $x['musicartist']);
echo "</a>
<a target="_top" title="Click here to go to ".$q4['display_name']."'s Station" href="stations.php?s=".$q4['user_id']."">".$q4['display_name']."</a>";
echo "</div></td>
</tr>
</table>";
echo "
<hr noshade color="#c0c0c0">
";
}
if(mysql_num_rows($t)<=0)
{

echo "<div id="content">There is no results</div>";

}
if(mysql_num_rows($t)>=6)
{
echo "<table width="90%" align="center"><tr><td><div id="sub4">More..</div></td></tr></table>";
}
}
Thanks

Your Answer:

Login to answer

Other forums

Linkage between two scripts
Okay say I have this for a link in a script:

Code: <li><a href="#&q

Blocking video streaming
Hello everyone,

I post a message here because i didn't find any solution yet.
I just finis

php email checker
I am having alot of trouble finding info on how to do these email things. I need to do the following

Preventing SQL Injection
I have a question about SQL Injection, In some of our code we use this: view plaincopy to clipboa

max() problem
I have a while loop to get image names.
Code: $imagequery = mysql_query("SELECT * FROM ad_i

Download Image from URL and Upload it
Ok, I have been googling for the last 1/2 hour trying to figure this out, Most likely I'm just not s

matching numbers inside ( )
I know I can match numbers by just [0-9]+, so I thought matching numbers inside ( ) would be somethi

contact form - output to page and email
I have the following in my controller:

$message['name'] = htmlentities(strip_tags(trim($_POST

$get problem
Hi Guys ...

can you please tell me what i am doing wrong here
Code: <?php

images aren't rendering
I'm trying to call a JPG file from within PHP (in an effort to hide the actual JPG folder). The imag