A Few Questions


Posted on 16th Feb 2014 07:03 pm by admin

Hi, I want to ask a few questions that I can't seem to find..

1) I'm creating a "shortcut" system on my website, where users can add shortcuts from pages by clicking the link and it will write the URL and the users ID into the database, the only problem I don't know how PHP can grab the URL of the page?

2) I can't seem to get cookies working on my site:

Code: //get the posted values
$email1=($_POST['user_name']);
$email=htmlspecialchars($_POST['user_name'],ENT_QUOTES);
$pass=sha1($_POST['password']);
$post_autologin=($_POST['checkbox']);

//MYSQL
$abc = mysql_query("SELECT * FROM accounts WHERE email='".$email1."'") or die(mysql_error());
$a = mysql_fetch_array($abc);

//Select whatever..
$sql="SELECT user_id, email, password FROM accounts WHERE email='".$email."'";
$result=mysql_query($sql);
$row=mysql_fetch_array($result);

$userid = $a['user_id'];
$displayname = $a['display_name'];

$_SESSION['user_id']=$userid;
$_SESSION['email']=$email;

//if username exists
if(mysql_num_rows($result)>0)
{
//compare the password
if(strcmp($row['password'],$pass)==0)
{
echo "yes";
if($post_autologin == YES)
{
$password_hash = sha1($pass); // will result in a 32 characters hash

setcookie ($cookie_name, 'usr='.$email.'&hash='.$pass, time() + $cookie_time);
}
$_SESSION['user_id']=$userid;
$_SESSION['email']=$email;
$_SESSION['dname']=$displayname;

}
else
echo "no";
}
else
echo "no"; //Invalid Login


?>
Is this correct? Its a Ajax login I found but when I check the checkbox and close the browser it logs me out.. I use $_SESSION['user_id] in places where I want stuff to show for logged in users, where do I put $_COOKIE['user_id']???

http://mymediaupload.com/media.php?v=130 if you look on this page and click "More by Cheryl Cole" it shows the current song, how would I get it to view the rest of the songs by that artist and not the one thats playing?

This is what I have..

Code: if($_GET['morelikethis'])
{
$name2 = mysql_real_escape_string($_GET['morelikethis']);
$s = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC LIMIT 0,6") or die(mysql_error());
$t = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC") or die(mysql_error());
$u = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC LIMIT 1,5") or die(mysql_error());
$len = 19;

while($x = mysql_fetch_array($s))
{
$q3 = mysql_query("SELECT * FROM accounts WHERE user_id = ".$x['musicuploaderid']."") or die(mysql_error());
$q4 = mysql_fetch_array($q3);
echo "<table border="0" width="100%" cellspacing="0" cellpadding="0">
<tr>
<td width="40"><img src="".$x['musicalbumart']."" height="40" width="40"></td><td width="5"></td>";
echo "<td align="left" valign="top"><a target="_top" title="".$x['musictitle']." - ".$x['musicartist']."" href="media.php?v=".$x['musicid']."">";
echo (strlen($x['musictitle']) > $len ? substr($x['musictitle'], 0, $len).".." : $x['musictitle']);
echo "
";
echo (strlen($x['musicartist']) > $len ? substr($x['musicartist'], 0, $len).".." : $x['musicartist']);
echo "</a>
<a target="_top" title="Click here to go to ".$q4['display_name']."'s Station" href="stations.php?s=".$q4['user_id']."">".$q4['display_name']."</a>";
echo "</div></td>
</tr>
</table>";
echo "
<hr noshade color="#c0c0c0">
";
}
if(mysql_num_rows($t)<=0)
{

echo "<div id="content">There is no results</div>";

}
if(mysql_num_rows($t)>=6)
{
echo "<table width="90%" align="center"><tr><td><div id="sub4">More..</div></td></tr></table>";
}
}
Thanks

No comments posted yet

Your Answer:

Login to answer
124 Like 24 Dislike
Previous forums Next forums
Other forums

how can we add data from dynamic fields to mysql db in php
i have a script which i found on the internet. i modify that script according to my needs. what is i

 formating when pulling data from a mysql database 
Ok so Im not to sure if this is the right thread to post in but here is my catch 22 issue.

I

script and html conflict in trying to create a header.
I have an error is occurring because of an html webpage with a "php require" at the top of

Count
Getting the same count everytime

Code:
$visitquery = mysql_query("SELECT COUNT(*) FR

ALV List Display to point to another report on Double Click
Hi,

I want my ALV List Display to point to another report on Double Click on its line ite

Multiple forms on the same page (safari)
Hello everyone,

I have 3 forms on the same page, that opens in a new window and submits to a

=> and <=
So I was digging through some code when I came across the <= operator. This is the first tim

Floating Point Precision Loss
I'm writing a program to draw a three-dimensional cube (with a corner cut off) without using any 3D

Grids not displaying decimals, and behaving differently on different PCs?
Hello,

I coded a relatively simple MII application that allows data from a form to be add

natcasesort works on one server but not on another
Hi

I have a problem that I was hoping that someone can help me with.

I'm trying to use

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash