A Few Questions
Posted on
16th Feb 2014 07:03 pm by
admin
Hi, I want to ask a few questions that I can't seem to find..
1) I'm creating a "shortcut" system on my website, where users can add shortcuts from pages by clicking the link and it will write the URL and the users ID into the database, the only problem I don't know how PHP can grab the URL of the page?
2) I can't seem to get cookies working on my site:
Code: //get the posted values
$email1=($_POST['user_name']);
$email=htmlspecialchars($_POST['user_name'],ENT_QUOTES);
$pass=sha1($_POST['password']);
$post_autologin=($_POST['checkbox']);
//MYSQL
$abc = mysql_query("SELECT * FROM accounts WHERE email='".$email1."'") or die(mysql_error());
$a = mysql_fetch_array($abc);
//Select whatever..
$sql="SELECT user_id, email, password FROM accounts WHERE email='".$email."'";
$result=mysql_query($sql);
$row=mysql_fetch_array($result);
$userid = $a['user_id'];
$displayname = $a['display_name'];
$_SESSION['user_id']=$userid;
$_SESSION['email']=$email;
//if username exists
if(mysql_num_rows($result)>0)
{
//compare the password
if(strcmp($row['password'],$pass)==0)
{
echo "yes";
if($post_autologin == YES)
{
$password_hash = sha1($pass); // will result in a 32 characters hash
setcookie ($cookie_name, 'usr='.$email.'&hash='.$pass, time() + $cookie_time);
}
$_SESSION['user_id']=$userid;
$_SESSION['email']=$email;
$_SESSION['dname']=$displayname;
}
else
echo "no";
}
else
echo "no"; //Invalid Login
?>
Is this correct? Its a Ajax login I found but when I check the checkbox and close the browser it logs me out.. I use $_SESSION['user_id] in places where I want stuff to show for logged in users, where do I put $_COOKIE['user_id']???
http://mymediaupload.com/media.php?v=130 if you look on this page and click "More by Cheryl Cole" it shows the current song, how would I get it to view the rest of the songs by that artist and not the one thats playing?
This is what I have..
Code: if($_GET['morelikethis'])
{
$name2 = mysql_real_escape_string($_GET['morelikethis']);
$s = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC LIMIT 0,6") or die(mysql_error());
$t = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC") or die(mysql_error());
$u = mysql_query("SELECT * FROM music WHERE musicartist LIKE '".$name2."%' ORDER BY `musicartist` ASC LIMIT 1,5") or die(mysql_error());
$len = 19;
while($x = mysql_fetch_array($s))
{
$q3 = mysql_query("SELECT * FROM accounts WHERE user_id = ".$x['musicuploaderid']."") or die(mysql_error());
$q4 = mysql_fetch_array($q3);
echo "<table border="0" width="100%" cellspacing="0" cellpadding="0">
<tr>
<td width="40"><img src="".$x['musicalbumart']."" height="40" width="40"></td><td width="5"></td>";
echo "<td align="left" valign="top"><a target="_top" title="".$x['musictitle']." - ".$x['musicartist']."" href="media.php?v=".$x['musicid']."">";
echo (strlen($x['musictitle']) > $len ? substr($x['musictitle'], 0, $len).".." : $x['musictitle']);
echo "
";
echo (strlen($x['musicartist']) > $len ? substr($x['musicartist'], 0, $len).".." : $x['musicartist']);
echo "</a>
<a target="_top" title="Click here to go to ".$q4['display_name']."'s Station" href="stations.php?s=".$q4['user_id']."">".$q4['display_name']."</a>";
echo "</div></td>
</tr>
</table>";
echo "
<hr noshade color="#c0c0c0">
";
}
if(mysql_num_rows($t)<=0)
{
echo "<div id="content">There is no results</div>";
}
if(mysql_num_rows($t)>=6)
{
echo "<table width="90%" align="center"><tr><td><div id="sub4">More..</div></td></tr></table>";
}
}
Thanks
No comments posted yet
Your Answer:
Login to answer
124
24
Other forums
Querying info from one table based on info in another
Hi, I am currently trying to make a part for my user driven website where one user can subscribe to
Company Code for Vendors created through Business Partners
Hi, experts!
I'm trying to set up the integration between Business Partner (BP) and Vendo
BB_Code error
I'm having a problem with a custom built function and keep getting this error:
Warning: M
Display the user's weight lost in the past week
Hello everyone,
I am working on a weight loss app for my site, and I want to display the user
There was a problem with the request. (Code: 0)
Any Idea what could cause this? I get it randomly at best. But with both IE and FF. It derives from
Multiple Options for a Single Page
For this example I want to use the Handlers option which is under Fed Admin and all the related codi
Greek characters in php
Hi,
I'm making a script and I m using for first time greek characters.
I started to write
Why do I get this error
Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home/a5488351/public_html/b
"SEO" URLs
Hey, I'm wondering how to go about creating and using these types of URLs. I'm presuming it's PHP th
Echo-ing MySQL content and Keep Formatting?
I have data in my MySQL such as:
QuoteBlah blah
Blah blah
etc
but when i ech