Help with ORDER BY


Posted on 16th Feb 2014 07:03 pm by admin

Hello. I would like to order by ascending States, then Cities, then Gyms in the following code, but I can't figure it out. If anyone could help, I would truly appreciated it!

if(isset($countryid))
{
$sql = "Select * from ".TBGYM." G LEFT JOIN ".TBCITIES." CT ON G.cityid= CT.id LEFT JOIN ".TBSTATES." S ON CT.sid=S.id LEFT JOIN ".TBCOUNTRY." C ON S.cid=C.countries_id WHERE G.countryid=".$countryid;
}
if(isset($stateid))
{
$sql = "Select * from ".TBGYM." G LEFT JOIN ".TBCITIES." CT ON G.cityid= CT.id LEFT JOIN ".TBSTATES." S ON CT.sid=S.id LEFT JOIN ".TBCOUNTRY." C ON S.cid=C.countries_id WHERE G.stateid=".$stateid;
}
if(isset($cityid))
{
$sql = "Select * from ".TBGYM." G LEFT JOIN ".TBCITIES." CT ON G.cityid= CT.id LEFT JOIN ".TBSTATES." S ON CT.sid=S.id LEFT JOIN ".TBCOUNTRY." C ON S.cid=C.countries_id WHERE G.cityid=".$cityid;
}

$pager = new PS_Pagination($db, $sql, $noofrecords,$noofnavigators, "param1=valu1&param2=value2");

$pager->setDebug(true);

$rs = $pager->paginate();
if(!$rs) die(mysql_error());

while($row = mysql_fetch_assoc($rs)) {
$arr_result [] = $row;
}

No comments posted yet

Your Answer:

Login to answer
233 Like 17 Dislike
Previous forums Next forums
Other forums

PHP, Arrays & A Lot Of Confusion
I've been doing basic PHP work on sites for a few years now, but I've never been tempted to learn ho

Inter Company -- Resources Related Billing (Services Industry)
Hello,

My company has a scenario where:
Company A bills Company C for INTER (cross

Form Help
Here is the form:

Line number On/Off | Expand/Contract<? include("../include/sess

Google Map
I have done Google Map Integration for one my project. But for that we need the "latitude and l

Need help to identify this error please
:confused:Can anyone help me tell what this error message means? Maybe tell me where to look to fix

php libs/ browsercap.in
ok i have a host that refuses to stay current. they control my php settings and libs. is there a way

Buggy registration system
Hey, I just started scripting in PHP, and I ran into a few problems.
Code: <?php
includ

split string
Hi all

i have some names (imploded by comma):
Code: toronto,paris,madrid
Now, i would

whats wrong with my code please help!!!
this is the error


Warning: mysql_close(): supplied argument is not a valid MySQL-Link res

2 decima places & How to reload my page
Hello There,

How do i put full-stop (.) after second figure from behind? ie if i have 123456

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash