How to display value in drop down list after form has been reloaded
Posted on
16th Feb 2014 07:03 pm by
admin
Please bear with me as I am very new to php and html.
I have a form with several drop down menus, the one at the top shows a list that when an item is selected fills in the form below including the other drop downs. So when an item is selected the form gets info from a mysql database and then fills in the form. At this point the user can further modify the form and re-submit it to update the database. This means that the drop downs in the form not only need to display the relavent options from the database to reflect the existing choice but also when clicked on show a list to allow the user the change the selection from the list.
This means that the dropdown needs to:
show the words 'select item' when the form is first loaded and the form is empty
show the current selection when the defined by a selection in the top drodown
show all the available items when the list is dropped down
Curently my drop down does only this:
shows the nothing when the form is first loaded and the form is empty
shows the current selection when defined by a selection in the top drodown
show all the available items when the list is dropped down plus the one that was there before it was clicked on, therefore doubing the option up showing the same option twice
The form is here if you would like to see it in action: http://www.spencercarpenter.co.uk/portfolioAppFiles/simpleForm.php
And a snippet of code from one of th drop downs is here:
Code: <select name="img01" onChange="updateImg(this, 'thumbImg01')">
<option value=-"-1" ><?php echo $row_chosen_pItem['img01']; ?></option>
<?php buildFileList5('uploaded');?>
</select>
the code inside the 'buildFileList5' looks like this:
Code: <?php
function buildFileList5($theFolder)
{
// Execute code if the folder can be opened, or fail silently
if ($contents = @ scandir($theFolder))
{
// initialize an array for matching files
$found = array();
// Create an array of file types
$fileTypes = array('jpg','jpeg','gif','png');
// Traverse the folder, and add filename to $found array if type matches
$found = array();
foreach ($contents as $item)
{
$fileInfo = pathinfo($item);
if (array_key_exists('extension', $fileInfo) && in_array($fileInfo['extension'],$fileTypes))
{
$found[] = $item;
}
}
// Check the $found array is not empty
if ($found)
{
// Sort in natural, case-insensitive order, and populate menu
natcasesort($found);
$selectedImage = ""; //default image
foreach ($found as $filename)
{
if(!empty($_POST['img01']) && $_POST['img01'] == $filename)
{
$sel = "SELECTED";
$selectedImage = $filename;
}
echo "<option value='$filename' $sel>$filename</option>n";
}
}
}
}
?>
I hope that is enough info to explain it.
If anyone could tell how to get the dropdown working properly I would be very gratefull.
Thanks a lot
No comments posted yet
Your Answer:
Login to answer
241
49
Other forums
registration form
first time posting. did some searches but didnt find exactly what i am looking for. dont flame cause
Multidimensional array problems in $_POST
I'm having trouble with a three-dimensional $_POST array. It starts as a two-dimensional array on th
comparing tables across databases sql refinement ideas required
Hi all
Via pl/sql I need to ensure that data between tables in different databases match
insert quotes
Hi,
I have an output like this:
Code: john,18,Cancer
How can I change this to
Code:
Remove directories not empty
hi,
i have an array that contains some names (1,4,6,56...). Every integer is a name of a folder.<
Chat Box in PHP
I was thinking in doing a Chat Box in PHP. For that I would use a form with two fields, Nick and Mes
list files from folder, only one for each date
I have many files in a folder and wish to only list one of each date
these are the file names
check if value exists
I have googled this for a while and I am getting lots of different results. Is there a standard meth
Multiple Do / While Statements?
I'm still very new to PHP, and running in to a problem when trying to execute a do/while loop inside
How to secure my login data to my database?
Hi there,
It may be a stupid question but I don't know how to secure my login data to my data