Javascript using window.location seems to lose state

Posted on 16th Feb 2014 07:03 pm by admin

Not sure what forum so let me know if I'm in the wrong place. I have a main window with a ajax grid that has a column of links that uses javascript and window.location to go to another page to show check stub information. When I use the backbutton on the browser everything persists on main window. Ok so far. If I navigate to the window with the show check stub information, there is a 'Print' button that again thru javascripts prints the grid with the check info on it. (Code I got of the internet with some minor changes I made).view plaincopy to clipboardprint?function Print() { var curVisible = true; var grid_obj = document.getElementById('<%= grdVoucherDetail.ClientID %>'); for (var i = 1; i < grid_obj.rows.length-1; i++) { grid_obj.rows[i].cells[8].style.display = curVisible ? "none" : "inline"; grid_obj.rows[i].cells[9].style.display = curVisible ? "none" : "inline"; } if (grid_obj != null) { var new_window = window.open('print.html'); //print.html is just a dummy page with no content in it. new_window.document.write(grid_obj.outerHTML); new_window.document.close(); new_window.focus(); new_window.print(); new_window.close(); } curVisible = false; for (var i = 1; i < grid_obj.rows.length-1; i++) { grid_obj.rows[i].cells[8].style.display = curVisible ? "none" : "inline"; grid_obj.rows[i].cells[9].style.display = curVisible ? "none" : "inline"; } } function Print() { var curVisible = true; var grid_obj = document.getElementById('<%= grdVoucherDetail.ClientID %>'); for (var i = 1; i < grid_obj.rows.length-1; i++) { grid_obj.rows[i].cells[8].style.display = curVisible ? "none" : "inline"; grid_obj.rows[i].cells[9].style.display = curVisible ? "none" : "inline"; } if (grid_obj != null) { var new_window = window.open('print.html'); //print.html is just a dummy page with no content in it. new_window.document.write(grid_obj.outerHTML); new_window.document.close(); new_window.focus(); new_window.print(); new_window.close(); } curVisible = false; for (var i = 1; i < grid_obj.rows.length-1; i++) { grid_obj.rows[i].cells[8].style.display = curVisible ? "none" : "inline"; grid_obj.rows[i].cells[9].style.display = curVisible ? "none" : "inline"; } }
Now after the print and closing that popup I click the backbutton again and things don't seem to persist. I did notice that the pageload of the main window (one I'm going back to) gets triggered after the printing of the grid where if I don't click the print button and go back the pageload does not get triggered. Any ideas would be appreciated. I have searched and searched for an answer and am getting nowhere. When this happens I usually feel that I've done something stupid. Oh well Thanks for any help that you can give me

Your Answer:

Login to answer

Other forums

Form submissing with PHP and JQuery/Ajax
I have searched everywhere, but cannot find a solution for this... I have worked all day trying to g

Displaying image from database
Hi,

I've got a site where that's got a database behind it. Currently it has loads of items in

Trouble with a select list
Hello All!
I was wondering if any of you guys could help me with a small problem I'm having!

PHP hyperlinks generator - HELP plz
Hi

I need some help to get this done using php:


1 - I have few hyperlinks say 500

Array help
Hello i got this code to fetch data from database but it is not working it displays
7
Array

Pipe email to PHP - get mail adress from MySQL - send?
Hi all,

this is the challenge:

1) Our faculty at the college where I'm employed includ

The IE or FF detector
Hello Friends,

Problem of today ( we seek for php help ) as following ,

we know all th

Access website from only 1 computer...?
One of my customers wants his website to only be accessed by people in which they bought the website

PHP loop
Okay so I have several "articles" stored in a mysql database and am attempting to echo tho

PHP error. Need help urgently
Hi,

I am programming a php site and have a problem that i just cant find out how to fix. When