Quick fix: Conditional statement with an array


Posted on 16th Feb 2014 07:03 pm by admin

Hi, I'm getting the temperature value off of the Environment Canada website along with the icon filename, so I can display my own icons and temperature on my site. All this works and I can display the temperature but my conditional statements aren't working to display my icons. I'm new to PHP and I don't see why this is a problem:
Code: <?php
$url = "http://www.weatheroffice.gc.ca/city/pages/on-69_metric_e.html";
$ch = curl_init();//Initialise CURL
Did you know?Explore Trending and Topic pages for more stories like this.
curl_setopt($ch, CURLOPT_URL, $url);//Set the url
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);//We want it to return data
curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, 100);//Of course, we don't want your script to run forever, so set a timeout
$text = curl_exec($ch);//Execute and get the page

$exploded = explode('<p class="temperature">',$text);//Make an array of the part before and after the <title> tag
$result = explode('<sup>',$exploded[1]);//Grab the part after the <title> tag, and split that too

$exploded2 = explode('<img id="currentimg" src="/weathericons/',$text);//Make an array of the part before and after the <title> tag
$result2 = explode('.gif"',$exploded2[1]);//Grab the part after the <title> tag, and split that too

curl_close($ch);//Close cURL

if($result2[0] < "02"){
echo "<img src="images/weather/00.gif" alt="Sunny">";
}
if(($result2[0] > "01") && ($result2[0] < "09")) {
echo "<img src="images/weather/01.gif" alt="Cloudy with chance of showers">";
}
if($result2[0] == "09" || $result2[0] == "19" || $result2[0] == "39") {
echo "<img src="images/weather/03.gif" alt="Storm">";
}
if(($result2[0] > "9" && $result2[0] < "9") || ($result2[0] > "19" && $result2[0] < "25") || ($result2[0] > "26" && $result2[0] < "30") || ($result2[0] > "31" && $result2[0] < "39")) {
echo "<img src="images/weather/02.gif" alt="Cloudy with chance of showers">";
}
if(($result2[0] > "24" && $result2[0] < "27") || ($result2[0] > "29" && $result2[0] < "32") || ($result2[0] > "39") {
echo "";
}
else{
echo "";
}
echo $result[0];//Echo the result
?>
No comments posted yet

Your Answer:

Login to answer
212 Like 7 Dislike
Previous forums Next forums
Other forums

HELP with mysql_real_escape_string
I'm looking to remove apostrophes completely when someone enters lyrics but don't have a clue how to

User registration and login
I don't know whether this is the correct forum, if not i apologise but am pretty desperate at the mo

Estimations and Effort
HI Gurus,

Would like to know whether SAP have a provision for carrying out the Project es

Help with forum quoting?
Hi im working on a forum and I have alomost finished it but i want a user quote system like twitter

PHP Include w/If IE Condition Statement?
I was having a problem with Internet Exploder (big surprise, right?) displaying my drop down menus i

Help with form post data and arrays
Hi all,

I am new to this forum... It has been awhile since i have worked with arrays, and i a

Need help PLEASE
ok i have this warning showing up

Warning: in_array() [function.in-array]: Wrong datatype for

why aint this working?
i have this code:

Code: $num = 250;
$count = ($num - $rcount);

echo $rc

CHECK A STRING FOR ' " ' (DOUBLE QUOTES)
I am checking for delimiter (.!?) and if there is a " after a sentence then it should neglect a

Warehouse Management
Hi,

On our system, we have two storage locations ( A and B ) where A is the main factory

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash