Quick fix: Conditional statement with an array


Posted on 16th Feb 2014 07:03 pm by admin

Hi, I'm getting the temperature value off of the Environment Canada website along with the icon filename, so I can display my own icons and temperature on my site. All this works and I can display the temperature but my conditional statements aren't working to display my icons. I'm new to PHP and I don't see why this is a problem:
Code: <?php
$url = "http://www.weatheroffice.gc.ca/city/pages/on-69_metric_e.html";
$ch = curl_init();//Initialise CURL
curl_setopt($ch, CURLOPT_URL, $url);//Set the url
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);//We want it to return data
curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, 100);//Of course, we don't want your script to run forever, so set a timeout
$text = curl_exec($ch);//Execute and get the page

$exploded = explode('<p class="temperature">',$text);//Make an array of the part before and after the <title> tag
$result = explode('<sup>',$exploded[1]);//Grab the part after the <title> tag, and split that too

$exploded2 = explode('<img id="currentimg" src="/weathericons/',$text);//Make an array of the part before and after the <title> tag
$result2 = explode('.gif"',$exploded2[1]);//Grab the part after the <title> tag, and split that too

curl_close($ch);//Close cURL

if($result2[0] < "02"){
echo "<img src="images/weather/00.gif" alt="Sunny">";
}
if(($result2[0] > "01") && ($result2[0] < "09")) {
echo "<img src="images/weather/01.gif" alt="Cloudy with chance of showers">";
}
if($result2[0] == "09" || $result2[0] == "19" || $result2[0] == "39") {
echo "<img src="images/weather/03.gif" alt="Storm">";
}
if(($result2[0] > "9" && $result2[0] < "9") || ($result2[0] > "19" && $result2[0] < "25") || ($result2[0] > "26" && $result2[0] < "30") || ($result2[0] > "31" && $result2[0] < "39")) {
echo "<img src="images/weather/02.gif" alt="Cloudy with chance of showers">";
}
if(($result2[0] > "24" && $result2[0] < "27") || ($result2[0] > "29" && $result2[0] < "32") || ($result2[0] > "39") {
echo "";
}
else{
echo "";
}
echo $result[0];//Echo the result
?>

No comments posted yet

Your Answer:

Login to answer
212 Like 7 Dislike
Previous forums Next forums
Other forums

onClick='location.href=index.htm'> not working
Below is my code:

echo "<input type='button' value='redirect' onClick='location.h

problem getting my contact form working
Yeah I know this is a pretty basic problem, but it's been a while since I've worked with PHP and I'm

Reditecting pages based on logic
Newbie here, apologies in advance!

I am trying to use the header function to forward one of a

what are '%S%', '%E%'
for example when i see Code: [Select]printf("Hello %srn", $name);
what does %s means

PHP, jAVASCRIPT setting input values, why isn't it working?
Hi:

I am calling this javascript:
<script language="javascript">

Empty text file when there is over XXXX lines of text.

define("RANDOM_FILE","/public_html/random.txt");
$randomEntry = "

noob cURL help
I have a pretty basic form that I need to cURL post to a file in my includes folder (includes/login.

CHMOD script
Hi,

I need a script to read all files in a folder and set to 777.

Can anyone help out

shift numbers with paging
Hi

How would i be able to display 10 numbers 1 2 3 4 5 6 7 8 9 10
and when I click next

help, header() is not working!
Hello, I have this code:


<?php

/**
* @author samoi
* @copyright 200

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash