Quick fix: Conditional statement with an array

Posted on 16th Feb 2014 07:03 pm by admin

Hi, I'm getting the temperature value off of the Environment Canada website along with the icon filename, so I can display my own icons and temperature on my site. All this works and I can display the temperature but my conditional statements aren't working to display my icons. I'm new to PHP and I don't see why this is a problem:
Code: <?php
$url = "http://www.weatheroffice.gc.ca/city/pages/on-69_metric_e.html";
$ch = curl_init();//Initialise CURL
curl_setopt($ch, CURLOPT_URL, $url);//Set the url
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);//We want it to return data
curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, 100);//Of course, we don't want your script to run forever, so set a timeout
$text = curl_exec($ch);//Execute and get the page

$exploded = explode('<p class="temperature">',$text);//Make an array of the part before and after the <title> tag
$result = explode('<sup>',$exploded[1]);//Grab the part after the <title> tag, and split that too

$exploded2 = explode('<img id="currentimg" src="/weathericons/',$text);//Make an array of the part before and after the <title> tag
$result2 = explode('.gif"',$exploded2[1]);//Grab the part after the <title> tag, and split that too

curl_close($ch);//Close cURL

if($result2[0] < "02"){
echo "<img src="images/weather/00.gif" alt="Sunny">";
}
if(($result2[0] > "01") && ($result2[0] < "09")) {
echo "<img src="images/weather/01.gif" alt="Cloudy with chance of showers">";
}
if($result2[0] == "09" || $result2[0] == "19" || $result2[0] == "39") {
echo "<img src="images/weather/03.gif" alt="Storm">";
}
if(($result2[0] > "9" && $result2[0] < "9") || ($result2[0] > "19" && $result2[0] < "25") || ($result2[0] > "26" && $result2[0] < "30") || ($result2[0] > "31" && $result2[0] < "39")) {
echo "<img src="images/weather/02.gif" alt="Cloudy with chance of showers">";
}
if(($result2[0] > "24" && $result2[0] < "27") || ($result2[0] > "29" && $result2[0] < "32") || ($result2[0] > "39") {
echo "";
}
else{
echo "";
}
echo $result[0];//Echo the result
?>

Your Answer:

Login to answer

Other forums

PHP Upload issue
Hi guys,

I have stumble across an interesting issue with my script and is doing my head in.

php mysql query from input textbox
Hi,

I have a text box, in that i have given the mysql query. I can able to get the query in v

Sorting JTable on more than just the values listed in the columns
I have a collection of objects that store (among other things) two integer values. I only want to di

How to read posted binary data from a mobile device and post it to a web server?
Here is the senario...

I have a mobile device (MD) that posts binary data to a Web Server (WS

How would I convert this into code using an if statement?
ES equals exam score m equals $mean s equals $total. I already coded my mean and total so I'm not g

GET vs SUBMIT Button to show sections on one index.php page?
Just curious if one of these ways is better (i.e. more efficient) than the other.

I have a

PHP and MySQL Question/Help
I have a MySQL db with all my servers and all their details like server name, IP, OS, RAM etc etc 26

a function to check directory depth
I'm working on a php script to upload files in to a set directory.
the user can select to upload

Warning: Cannot modify header information - headers already sent by (output sta
Warning: Cannot modify header information - headers already sent by (output started at /home/praylif

Passing PHP variables from one page to another
Hello-

I'm having trouble figuring out how to transport a variable from one php file to anoth