Quick fix: Conditional statement with an array


Posted on 16th Feb 2014 07:03 pm by admin

Hi, I'm getting the temperature value off of the Environment Canada website along with the icon filename, so I can display my own icons and temperature on my site. All this works and I can display the temperature but my conditional statements aren't working to display my icons. I'm new to PHP and I don't see why this is a problem:
Code: <?php
$url = "http://www.weatheroffice.gc.ca/city/pages/on-69_metric_e.html";
$ch = curl_init();//Initialise CURL
Did you know?Explore Trending and Topic pages for more stories like this.
curl_setopt($ch, CURLOPT_URL, $url);//Set the url
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);//We want it to return data
curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, 100);//Of course, we don't want your script to run forever, so set a timeout
$text = curl_exec($ch);//Execute and get the page

$exploded = explode('<p class="temperature">',$text);//Make an array of the part before and after the <title> tag
$result = explode('<sup>',$exploded[1]);//Grab the part after the <title> tag, and split that too

$exploded2 = explode('<img id="currentimg" src="/weathericons/',$text);//Make an array of the part before and after the <title> tag
$result2 = explode('.gif"',$exploded2[1]);//Grab the part after the <title> tag, and split that too

curl_close($ch);//Close cURL

if($result2[0] < "02"){
echo "<img src="images/weather/00.gif" alt="Sunny">";
}
if(($result2[0] > "01") && ($result2[0] < "09")) {
echo "<img src="images/weather/01.gif" alt="Cloudy with chance of showers">";
}
if($result2[0] == "09" || $result2[0] == "19" || $result2[0] == "39") {
echo "<img src="images/weather/03.gif" alt="Storm">";
}
if(($result2[0] > "9" && $result2[0] < "9") || ($result2[0] > "19" && $result2[0] < "25") || ($result2[0] > "26" && $result2[0] < "30") || ($result2[0] > "31" && $result2[0] < "39")) {
echo "<img src="images/weather/02.gif" alt="Cloudy with chance of showers">";
}
if(($result2[0] > "24" && $result2[0] < "27") || ($result2[0] > "29" && $result2[0] < "32") || ($result2[0] > "39") {
echo "";
}
else{
echo "";
}
echo $result[0];//Echo the result
?>
No comments posted yet

Your Answer:

Login to answer
212 Like 7 Dislike
Previous forums Next forums
Other forums

data type in column definition
Hi,
I create a table with column called "Direction of Travel code ".
The travel codes in t

Problem with array max size.
Hi to everyone,
I've got a homework about filling a bidimensional array un spiral shape, I alre

PHP switch function help
Hi, I am trying to create a search function for a directory website. On the search function on html

Shopping Cart
Can anyone direct me to a Simple, Basic structure of a shopping cart.
New to classes. I want to s

Help with looping
I have a comma separated list of colors taken from a database ($ICo) and a directory of images named

Cache PHP Objects/Classes?
Does anyone have ideas about caching PHP objects using something like: http://memcached.org/

Help please - How to validate from 2 possible answers
Hi

I hope somebody can help me with what will probably be really simple, I'm pulling my hair

Help adding strtolower( to my in_array
strtolower i need to add it to this to work, iuno how.

Code: $moderators = array('Admin', 'ba

'210010106140040100' == '210010106140040101'
Debugging this simple line of a PHP script

Code: if($a == $b){ }
I've found that with val

PHP Display Telephone Number On Referrer
I have used the php below to show a different telephone number in the header of the site depending u

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash