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login box shows up again after logging in 2nd login works

Posted on 16th Feb 2014 07:03 pm by admin

Hello,

I am having trouble on my site Lockerz.rack111.com where when you login the login box when you hit submit clears and then when you type your info in again then the login box works.

here is the code:

Code: <?php

if(isset($_SESSION['username'])) {
$username = $_SESSION['username'];
$query = mysql_query("SELECT id FROM `members` WHERE `username` = '$username'") or die(mysql_error());
$results = mysql_num_rows($query);
$id = $results['id'];

echo "welcome <font color='lightblue'>$username</font>,
&nbsp; &nbsp; &nbsp;<a href='./profile.php?id=$userID '>Profile</a> - <a href='./logout.php'>Logout</a>";

} else {

$final_report = "-";
if(isset($_POST['login'])){
$username= trim($_POST['username']);
$password = trim($_POST['password']);
if($username == NULL OR $password == NULL){
$final_report = "Please complete all the fields below..";
}else{
$check_user_data = mysql_query("SELECT * FROM `members` WHERE `username` = '$username'") or die(mysql_error());
if(mysql_num_rows($check_user_data) == 0){
$final_report = "This username does not exist..";
}else{
$get_user_data = mysql_fetch_array($check_user_data);
if($get_user_data['password'] == $password){

$start_idsess = $_SESSION['username'] = "".$get_user_data['username']."";
$start_passsess = $_SESSION['password'] = "".$get_user_data['password']."";
?>
<?php
}}}}
?>
<font color="white">
<form action="" method="post">
<table width="312" align="center">
<tr>
<?php echo "<font color='white' size='1'>$final_report </font>"; ?><td width="120"><font color="white">Username:</font></td>
<td width="180"><input type="text" name="username" size="30" maxlength="25" STYLE="font-size: xx-small;"></td>
</tr>
<tr>
<td><font color="white">Password:</font></td>
<td><input type="password" name="password" size="30" maxlength="25" STYLE="font-size: xx-small;"></td>
</tr>
<tr>
<td>&nbsp;</td>
<td><input type="submit" name="login" value="Login" STYLE="font-size: xx-small;"></td>
</tr>
</table>
</font>
</form>
<?php
}
?>

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Code:    $num = 250;
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