login box shows up again after logging in 2nd login works


Posted on 16th Feb 2014 07:03 pm by admin

Hello,

I am having trouble on my site Lockerz.rack111.com where when you login the login box when you hit submit clears and then when you type your info in again then the login box works.

here is the code:

Code: <?php

if(isset($_SESSION['username'])) {
$username = $_SESSION['username'];
$query = mysql_query("SELECT id FROM `members` WHERE `username` = '$username'") or die(mysql_error());
$results = mysql_num_rows($query);
$id = $results['id'];

echo "welcome <font color='lightblue'>$username</font>,
&nbsp; &nbsp; &nbsp;<a href='./profile.php?id=$userID '>Profile</a> - <a href='./logout.php'>Logout</a>";

} else {

$final_report = "-";
if(isset($_POST['login'])){
$username= trim($_POST['username']);
$password = trim($_POST['password']);
if($username == NULL OR $password == NULL){
$final_report = "Please complete all the fields below..";
}else{
$check_user_data = mysql_query("SELECT * FROM `members` WHERE `username` = '$username'") or die(mysql_error());
if(mysql_num_rows($check_user_data) == 0){
$final_report = "This username does not exist..";
}else{
$get_user_data = mysql_fetch_array($check_user_data);
if($get_user_data['password'] == $password){

$start_idsess = $_SESSION['username'] = "".$get_user_data['username']."";
$start_passsess = $_SESSION['password'] = "".$get_user_data['password']."";
?>
<?php
}}}}
?>
<font color="white">
<form action="" method="post">
<table width="312" align="center">
<tr>
<?php echo "<font color='white' size='1'>$final_report </font>"; ?><td width="120"><font color="white">Username:</font></td>
<td width="180"><input type="text" name="username" size="30" maxlength="25" STYLE="font-size: xx-small;"></td>
</tr>
<tr>
<td><font color="white">Password:</font></td>
<td><input type="password" name="password" size="30" maxlength="25" STYLE="font-size: xx-small;"></td>
</tr>
<tr>
<td>&nbsp;</td>
<td><input type="submit" name="login" value="Login" STYLE="font-size: xx-small;"></td>
</tr>
</table>
</font>
</form>
<?php
}
?>

No comments posted yet

Your Answer:

Login to answer
144 Like 50 Dislike
Previous forums Next forums
Other forums

Pls help with PHP
Pls can anyone direct me on how to create a user account for a customer. For example i want know if

get the country of visitor and display content based on that
Hello all,

I have seen that Google analytics can tell you where a visitor is coming from and

Sequre login with cookies.
I want to build secure login with cookies. I just want your ideas about this, your suggestions. What

radio button reamains checked
Hello i'm trying to keep the state off my radio buttons so it shows which ones where clicked after t

Form a inline view based on the results of the previous query?
Hi Experts,
Can we form a inline view on the results of a previous query (another inline view)?

Change Sort Order to Display Newest File First
Hi Guys,

I have a page that sorts the contents (PDFs) of a directory and displays them on the

why preg_match_all does not return the number of matches
My regex looks like

X[^x{4e00}-x{9fa5}]*Y

(where X and Y are two Chinese characters)

Undefined index on my form
ok im getting Undefined index on this line.. print_r($_REQUEST['form']);

below is the full sc

Cursor statement failed with errors
Following statement failed with the errors.

cursor proj_cursor1 is (select projectID from

styling a RadioButtonList
HiI need to have a radio button and close to it, its lable, then a space then another set of those.

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash