pagination numbering pattern
Posted on
16th Feb 2014 07:03 pm by
admin
Hello,
I have following code which works great for pagination. but i have small issue now.
Now the output is coming like this
Quotemypage.php?page=2
I want it like this
Quotemypage.php/2
code-
Code: $numrows = 100;
//$numrows = $row['numrows'];
//echo "$row[numrows]";
// how many pages we have when using paging?
$maxPage = ceil($numrows/$rowsPerPage);
echo "$maxPage";
$self = 'mypage.php';
// creating 'previous' and 'next' link
// plus 'first page' and 'last page' link
// print 'previous' link only if we're not
// on page one
$Nav="";
If($pageNum > 1) {
$Nav .= "<a class='nav' href="$self?page=" . ($pageNum-1) . " "><< Prev</a>";
}
/*For($i = 1 ; $i <= $maxPage ; $i++) {
If($i == $pageNum) {
$Nav .= "<b>$i</b>";
}Else{
$Nav .= "<a class='nav' href="$self?page=" . $i . "">$i</a>";
}
}*/
If($i == $pageNum)
{
$Nav .= "<p class='page'>1</p>";
}
Else
{
$page1=$pageNum-1;
if($page1==0){}
else
{
$Nav .= "<p class='pagination'><a href="$self?page=" . $page1. "">$page1</a></p>";
}
$Nav .= "<p class='page'>$pageNum</p>";
$page2=$pageNum+1;
if($page2<=$maxPage)
{
$Nav .= "<p class='pagination'><a href="$self?page=" . $page2. "">$page2</a></p>";
}
else{
}
}
If($pageNum < $maxPage) {
$Nav .= "<a class='nav' href="$self?page=" . ($pageNum+1) . "">Next >></a>";
}
Echo "
" . $Nav;
/* for showing all rows
$Nav="";
If($pageNum > 1) {
$Nav .= "<a class='nav' href="$self?page=" . ($pageNum-1) . " "><< Prev</a>";
}
For($i = 1 ; $i <= $maxPage ; $i++) {
If($i == $pageNum) {
$Nav .= "<b>$i</b>";
}Else{
$Nav .= "<a class='nav' href="$self?page=" . $i . "">$i</a>";
}
}
If($pageNum < $maxPage) {
$Nav .= "<a class='nav' href="$self?page=" . ($pageNum+1) . "">Next >></a>";
}
Echo "
" . $Nav;
*/
/*$Nav="";
if ($pageNum > 1)
{
$page = $pageNum - 1;
$Nav = " <a href="$self?page=$page">|Prev|</a> ";
$Nav = " <a href="$self?page=1">|<<</a> ";
//echo "$first";
}
else
{
$Nav = ' |Prev| '; // we're on page one, don't enable 'previous' link
$Nav = ' |<< '; // nor 'first page' link
}
// print 'next' link only if we're not
// on the last page
echo "$pageNum";
if ($pageNum < $maxPage)
{
$page = $pageNum + 1;
$Nav = " <a href="$self?page=$page">|Next|</a> ";
$Nav = " <a href="$self?page=$maxPage">>>|</a> ";
}
else
{
$Nav = ' |Next| '; // we're on the last page, don't enable 'next' link
$Nav = ' >>| '; // nor 'last page' link
}
Echo "
" . $Nav;*/
can anyone please tell me how can i achieve that?
Thanks in advance.
No comments posted yet
Your Answer:
Login to answer
284
7
Other forums
max() problem
I have a while loop to get image names.
Code: $imagequery = mysql_query("SELECT * FROM ad_i
Strange PHP/mySQL error ... am I just tired?
Code: <?
## CONNECT TO DB FUNCTION!
function ConnectTo($db2con)
{
$hostNam
Need help making a script that moves data into acrhive table
Hi,
I'm kinda new to php/mysql
And i wrote a simple script to store sales lead for a b
BackButton Behaviour in AJAX
I have an ASPX Page AJAX Enabled!The page has a gridView and a DDL for filtering on it. The Gridview
help connecting a form to php and then emailing the form
Ok. So, I made a form, and I need help to where when submitted, I get an email with the submitted de
Big O & time complexity ???
can you help me how to calculate the Big O & time complexity for any algorithm and c++ program pleas
Email "$"
Hello!!
Any PHP guy with a bit of a knowledge in Flash ?
When I send a JPEG from flash
mysql UNION | warning mysql_fetch_array !!
Code: <?php
$i = 0;
$query1="SELECT * FROM `products` WHERE `div
article site help remaining text
Hi all hope you will be fine
I am creating a article site in this site i want to put some text on
Wierd if else problem
Hi guys,
this probably aint wierd for you, but it seems like php is playin up to me. may b i