PHP switch function help


Posted on 16th Feb 2014 07:03 pm by admin

Hi, I am trying to create a search function for a directory website. On the search function on html page I have a dropdown menu. From this you can select one OF 3 options - shoes, handbags, shoes and handbags. I have a php process form page where it takes this infor before runninng a query in the sql database.

My question is that I would like the one option to have multiple values - when user clicks shoes, the query will search for a field containing shoes (this bit is fine) but also I want it to select another field to search for a value - this field will depend upon the what option the user picked in the question. The problem being, that unless i rename the fields in the table from lets say, Sbrand to Shoes and Hbrand to handbags i'm not sure how to action

Did you know?Explore Trending and Topic pages for more stories like this.
What I need is that if value on option was shoe then I need it linked to pick from Sbrand Now I think that I can use a switch function but the current issue is that I must have it in the wrong place as when I tried it as per below code, it appears that the search is looking for a field called the option value so the switch is not working. Perhaps I need to move the switch function from the php process page to the html page but I’m not sure

Any help much appreciated

HTML code………… this works on a method=”get”

<select name="type">
<option value="none">-- Please Select --</option>
<option value="Shoes">Shoes</option>
<option value="Handbags">Handbags</option>
<option value="Shoes and Handbags">Shoes and Handbags</option>
</select>



Here’s the PHP code

$search_type=$db->escapeString($_GET['type']);
switch ($type){
case "Shoes":
echo "Sbrand";
break;
case "Handbags":
echo "Hbrand";
break;
case "Shoes and Handbags":
echo "SHbrand";
break;
}



$result=$db->query("SELECT Sbrand, Hbrand, SHbrand, SB, Retailer, Address, Town, County, Postcode, Postcode_code, Phone, Website FROM database WHERE SB LIKE 'type' AND $search_type LIKE '%$searchterm%'");




Any help much appreciated as i am new to this
No comments posted yet

Your Answer:

Login to answer
308 Like 52 Dislike
Previous forums Next forums
Other forums

$variable = $variable
Hello

Sorry if this is a really simple question but I have run out of ideas. Is there a reall

Question about GD library
I am trying to make an image that shows a random quote from my database.


However I want t

Whats wrong with my query?
I am trying to get this query to show the appropriate ticked vehicle roof height, unless no boxs are

Database/Table Collation
What is the Database, and table collations used for? i don't understand what there used for since co

My XSRF Prevention code isn't working
First of all, thanks for the generous help you guys have given me in the past on this forum.
Seco

How to generate a text file using php...?
Hi,
Can anyone give me code to generate a text file using php


Thanks in advance

Printing issues with xMII 11.5
For some reason, we have one report (and only one) that is giving us fits when trying to print. The

TabControl Inside ListView Not Editing
Hello everybodyI have a ListView on my page. Inside the ListView I put a TabControl, cuz I want to p

Grouping and sorting results
Please help with this query.

I have 2 tables in a database, countires and cities. states look

How to show next and prev records
Hi all,

Sorry if this is simple, i'm very new to php, well, any programming language actually

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash