PHP using IF to display error

Posted on 16th Feb 2014 07:03 pm by admin

i have a MySQL query and i want to display 1 thing only if the number of affected rows is >=1 and if not then display the error, here is what i have so far and nothing is being displayed ...

Code: if (mysql_num_rows() >= "1")
{
echo "Update OK!<br />";
}
else
{
die("Update failed: " . mysql_error());
}

Your Answer:

Login to answer

Other forums

mySQL and PHP search
Hello,
I am trying to code a project and ran into a brick wall with one of my pages. I am pretty

difference between datetimes
($row['totime']-$row['fromtime'])/60

this is giving me 0

example of totime and fromtim

Getting Subdomain Name With PHP?
I want to grab the subdomain name with PHP so I can generate database queries.

for example my

Passing JS to PHP
So I have the following
Code: <?php
getdetails(?><script type="text/

Email logic not working
I would like to send an email using the php email() function then if it does execute i.e sends i wou

Help on code output
My CODE:

Code: [Select] echo "<phone>".$line["phone"].&qu

trim function issues
Hi guys, total noob here...

So I've been tinkering around with a html and am using php to em

RFQ Configuration - can you make PLANT field an optional field in ME42
Is there a way to make the plant field on an RFQ optional in change mode (ME42)?

Page doesn't expand for content
Hi. I've been testing a query I made. It's here http://lapr1.6te.net/inquerito.php
The page doesn

quick question
Hi ..

i have a question
how do i set a var so it displays via an echo
Code: $logo = '&a