PHP using IF to display error

Posted on 16th Feb 2014 07:03 pm by admin

i have a MySQL query and i want to display 1 thing only if the number of affected rows is >=1 and if not then display the error, here is what i have so far and nothing is being displayed ...

Code: if (mysql_num_rows() >= "1")
{
echo "Update OK!<br />";
}
else
{
die("Update failed: " . mysql_error());
}

Your Answer:

Login to answer

Other forums

contact form - output to page and email
I have the following in my controller:

$message['name'] = htmlentities(strip_tags(trim($_POST

Shuffle Array
Hi,

I am writing a script for a game that needs players to randomly be assigned a target (ano

Save User Inputs while javascript reloading!
hi..
i have written a PHP code in which i reload the page when user selects a value in dropdown..

sapgui f4 help last search
I know this has to be simople. One user (maybe more) does not have the "last search saved" from the

problem in program for counting no of chars using pointers
Hi all, I was trying to make a program which counts number of chars in a string using concpt of poin

Simple PHP/Java Help..
Hi,
I'm trying to build a little program to do with calculating postage. Unfortunately i haven't

PHP5/Zend 2.0 - Resources
PHP5 Snapshots
http://snaps.php.net/

ZEND 2.0 Feature Overview and Design (PDF File

session variables not working anymore
hello,
i use sessions to handle authentication within my site. my host has been changing a lot of

Easy administration on MySQL databases
My website is database driven and I am very tired of manually making queries to my tables in order t

Oracle Text CTX_DOC.snippet slow
I have a table (FILE_TABLE) that contains a blob column (ft_file) and I have created the following O