PHP using IF to display error

Posted on 16th Feb 2014 07:03 pm by admin

i have a MySQL query and i want to display 1 thing only if the number of affected rows is >=1 and if not then display the error, here is what i have so far and nothing is being displayed ...

Code: if (mysql_num_rows() >= "1")
{
echo "Update OK!<br />";
}
else
{
die("Update failed: " . mysql_error());
}

Your Answer:

Login to answer

Other forums

please help
HTML Code:

Code: <span id="ctl00"><span>

Problem with shopcart code
Hello, I am having a bit of trouble being able to add a product to my shopcart. My mysql database i

$GPRMC and NMEA how to extract from report
Hi There,

Im a little bi lost and not sure where to start with this one, ive got a small gps

Update not working ... please help
Hi,

I am trying to update a row using an edit form by passing id of the row .. but it is not

Javascript or not?
How many people prefer javascript/ajax sites? How many prefer the good old fashion straight php sit

Grouping and sorting results
Please help with this query.

I have 2 tables in a database, countires and cities. states look

Alternate messaging
I have 4 strings in MySQL db1

$string1 : Hello
$string2 : Hi
$string3 : Great
$strin

How to secure my login data to my database?
Hi there,

It may be a stupid question but I don't know how to secure my login data to my data

Got A Free Server :(
So I was given a free server

http://shopping.yahoo.com/p:Compaq%20ProLiant%201500%20Server:1

Switch letters in message (basic cryptology)...
I am trying to switch letters around in a message for an application on my site (see here). The prob