Preventing blank or already entered values


Posted on 16th Feb 2014 07:03 pm by admin

Im trying to learn how to place a read file line by line and prevent duplicate entries and also BLANK entries, into my process php script,

using feof, I have failed many times and get so many errors such as syntax expecting . or , and so forth
this is my process.php
<?php
$File = "links.txt";
$Handle = fopen($File, 'a');
$Data = "".$_POST['ID'];
fwrite($Handle, $Data."n");
print "Data Addedn";
fclose($Handle);
?>


<?php
countLines("links.txt");
function countLines($filepath)
{
$handle = fopen( $filepath, "r" );
$count = 0;
while( fgets($handle) )
{
$count++;
}
fclose($handle);
return $count;
}

?>
<head>
<meta http-equiv="REFRESH" content="5;test1.php"></HEAD>

please wait... navigating back!



I got fed up and deleted all my work, to start from scratch,

if feof($_POST['ID'])
{
alert 'Already entered';
return;
}
that was just one of my attempts
also im unsure if putting in /n would make it look for /n or new line, if it looks for new line and every file has the new line marker would it always return as the data was already entered?

Thanks in advance for assistance/teaching

No comments posted yet

Your Answer:

Login to answer
241 Like 9 Dislike
Previous forums Next forums
Other forums

How to create a static html menu from a database
Hi,

I have built a small cms which allows me to create simple html pages and then upload them

Procedure with variable number of columns
Hi, I have a procedure that looks like this:

PROCEDURE PROC(p_cursor OUT sys_refcurso

Cursor statement failed with errors
Following statement failed with the errors.

cursor proj_cursor1 is (select projectID from

Problem with HTTP Caching...?
Hi there, im trying to implement caching. But it doesn't always work.
I post it here because ther

ImageCreate()
When I create an image and add text to it I want my text to be replaced with a PNG image, because th

whats wrong with my code please help!!!
this is the error


Warning: mysql_close(): supplied argument is not a valid MySQL-Link res

frame help
on the bottom frame is menu.html

Code: <body><form action='link.php' met

need help in dynamic select menu in php
hi i have created a dynamic select menu using php. i have a problem in that which is when the user s

need help about
i store the value of my select statement result to an array and stored it to a variable named $fname

Getting PHP to ammended the selected in option field
Hey Guys

thanks for everyones help so far. This site and its users are oozing awesomness.

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



 
© indyaspeak.com. All Rights Reserved.
Play Free Quiz and Win Cash