Regular expression tips or resources

Posted on 16th Feb 2014 07:03 pm by admin

Hello! I'm having some issues implementing the appropriate regex patter to eliminate unwanted characters from a string.

Here is a sample string:
Code: String str = "test-hello. me please3, _dog[ -()"; What I need to do is create a regex that will take out all non word characters except for spaces AND strings of type "test-hello" - in other words any string that has word or digit characters followed by a "-" (hyphen) followed by more word or digit characters - this is what is giving me trouble.

What I have right now which is perfect except for the "test-hello" type strings is:
Code: Pattern replace = Pattern.compile("([^\w ])");Matcher matcher = replace.matcher(str);str = matcher.replaceAll(""); The above code removes all non word or digit characters except for spaces but it will obviously still remove the "-" in "test-hello".

I'm not looking for the whole answer of course but any tips or resources I can be pointed to would be greatly appreciated. I'm not familiar with the regex syntax in Java as I am in say PHP.

Thank you!

Your Answer:

Login to answer

Other forums

How to generate a text file using php...?
Hi,
Can anyone give me code to generate a text file using php


Thanks in advance

Oracle Connectivity
Hi Every One,

Can we access SAP from oracle database.If it possible then please spec

tag inside php...
hi


Code: <?php
echo "<td width="$columnWidth%" align=&

Date help - fetch dates for Mondays between xxx and yyy?
Does anyone know the best way to do this? I have two dates, say:

2010-01-26 and 2010-05-30

how do i make a string??
hey guys,
can someone please tell me how to put data from the glob function into a string

why preg_match_all does not return the number of matches
My regex looks like

X[^x{4e00}-x{9fa5}]*Y

(where X and Y are two Chinese characters)

Storing user data help?
Hey Guys,

I'm not use if this question is to broad but I can always give you more informatio

show random images
hey guys

can someone please suggest a way in which the following code can be edited so it onl

login page does not execute a else statement
I've created a login page using sessions.
When an incorrect user name or password is entered then

mysql query with single quotes in a variable
$sitedetails = "INSERT INTO vars (address, sitename, description, ownername, theme) VALUES ('$u