[RESOLVED] Socket/Port remains open after app crashes
Posted on
16th Feb 2014 07:03 pm by
admin
I'm having this problem with a networked app in vb.net.
If the program exits normally the port closes fine, however, if it crashes sometimes it remains open and I am unable to close it. The next time I run the program it is unable to open the port because it is already in use. Here's the exception:
10048: Only one usage of each socket address (protocol/network address/port) is normally permittedAny ideas on how I can reclaim this port, or how I can close it?
Did you know?Explore Trending and Topic pages for more stories like this.
I tried using the reuse address socket option
Code: SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReuseAddress, 1) but that just opens the port again and does not close the old one. see this netstat output:
TCP PCISERVER:14000 PCISERVER.cpwpci.cpwgroup.net:0 LISTENING 4320
[System]
TCP PCISERVER:14000 PCISERVER.cpwpci.cpwgroup.net:0 LISTENING 5808
[System]
TCP PCISERVER:14001 PCISERVER.cpwpci.cpwgroup.net:0 LISTENING 5808
[System]
TCP PCISERVER:14001 PCISERVER.cpwpci.cpwgroup.net:0 LISTENING 4320
[System]
As you can see once the program exits the ports remain opened by the System process.
I don't know of a way to stop them from listening besides a restart.
No comments posted yet
Your Answer:
Login to answer
87
27
Other forums
Open/Close Links in Php
Hello, Hoping someone can inform me how I can get PHP to automatically open a set of links in a new
code help - pagination
Hi all, I have this code, basically a user logs into my site and they get this page.
The pro
help with mysql_error()
Hi,
I am trying to insert data into a table, but I am not able to insert it. I wanted to see
php - xml what is the best way to do this.
IN essence I want to have a script calling the info from the database.. I have no problem thus far,
uploading video files into mysql in php
hi,
I have the video files which i have to upload into mysql db. along with creating thumbnails f
difference between datetimes
($row['totime']-$row['fromtime'])/60
this is giving me 0
example of totime and fromtim
cURL error
So here is my code... I got it off of here... http://www.youtube.com/watch?v=XcgQUsorF_8
Because
Need help with PHP/MySQL drop down menu
I need help on how I can implement a drop down menu which queries mysql database and output the avai
How to show more than 1 users with this code...
Hello,
i have a table that shows users only if I, as Administrator, want to be shown. But its sho
newbie question about multiple queries
hi everyone,
I'm sorry to ask such a basic question, but I'm young and trying to learn php on my