user validation always displaying invalid ? please help
Posted on
16th Feb 2014 07:03 pm by
admin
Hello,
I have 2 accounts and there is a field in mysql called validated it can be either "true" or "false"
I tried writing a code so when the user logs in if the user is validated meaning
$username = $_POST['username'];
$validated = true
$validation = a mysql query that selects validated from members where username = $username
$validated == $validation
and I have to accounts made
1 account username is "google" its validation is set to false
2nd account username is "jaydesigns" its validation is set to true
but when I login both come up as not validated
here is the page code:
Code: <?
include_once"config.php";
$final_report = "Please complete all the fields below..";
if(isset($_POST['login'])){
$username= trim($_POST['username']);
$password = trim($_POST['password']);
if($username == NULL OR $password == NULL){
$final_report = "Please complete all the fields below..";
}else{
$check_user_data = mysql_query("SELECT * FROM `members` WHERE `username` = '$username'") or die(mysql_error());
if(mysql_num_rows($check_user_data) == 0){
$final_report = "This username does not exist..";
}else{
$get_user_data = mysql_fetch_array($check_user_data);
if($get_user_data['password'] == $password){
$start_idsess = $_SESSION['username'] = "".$get_user_data['username']."";
$start_passsess = $_SESSION['password'] = "".$get_user_data['password']."";
$validation = mysql_query("SELECT validated FROM `members` WHERE `username` = '$username'") or die(mysql_error());
$validated = "true";
if($validation == $validated) {
$final_report ="You are now logged in $start_idsess ";
} else {
$final_report ="Your account is not validated $start_idsess,
Please Activate your account from the email you recieved from us.
If you did not recieve an email click <a href='./activate-send.php'>here</a> to resend the email
You will be logged out Now";
session_unset('username');
session_unset('password');
}
?>
<meta http-equiv="Refresh" content="0; URL=./members.php">
<?php
}}}}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Funky Vision Membership Script</title>
</head>
<body><form action="" method="post">
<table width="312" align="center">
<tr><td colspan='2'><?php echo "$final_report" ?></td></tr><tr>
<tr>
<td width="120">Username:</td>
<td width="180"><input type="text" name="username" size="30" maxlength="25"></td>
</tr>
<tr>
<td>Password:</td>
<td><input type="password" name="password" size="30" maxlength="25"></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="login" value="Login" /></td>
</tr>
</table>
</form>
</body>
</html>
No comments posted yet
Your Answer:
Login to answer
209
12
Other forums
Email logic not working
I would like to send an email using the php email() function then if it does execute i.e sends i wou
Tournament Brackets (Double Elimination)?
Is making a double elimination tournament style bracket system capable of being done in php?
How to limit the calls to an API
Hello, in my simple script I call an api which effectively involves me getting an xml file.
H
small inaccuracies
I have this code to convert fractional base 10 into base 2:
while($num > 0)
Where is my php.ini???
Hi
First off - apologies - i'm not a coder so this may sound very amateur.
I'm having
Count
Getting the same count everytime
Code:
$visitquery = mysql_query("SELECT COUNT(*) FR
How can use this array as a key?
Say I have this array for example:
print_r($array);
Prints:
Code: [Select]Array
Date/Time and Checkbox
Hi Everyone,
I am trying to figure out how to insert the current date and tim
PHP Mysql Staff Induction System
Hi there, I'm pretty new to PHP and Mysql so could really do with being pointed in the right directi
Just a white page
Okay so, my website, when I click SignUp on it it takes me to /join.php but its a complete white pag