Cannot Display Array from Select Statement + Login question


Posted on 16th Feb 2014 07:03 pm by admin

Hi,
I'm new to PHP but so far so goog. I was assigend a project and I'm very close to completion.

I have a site that logs you in, sets a cookie, and then what I would like to do is depending on the user loging in, certain records from a table are selected and displayed

I have the following code:

Code: // Connects to your Database
mysql_connect("localhost", "root", "escrma") or die(mysql_error());
mysql_select_db("rma_portal") or die(mysql_error());

//Set Login Variable with the UserID
$login = $_COOKIE['ID_my_site'];

echo "This is it set to $login

";

// Collects data from "users" table
$data = mysql_query("SELECT *
FROM users, cust_info
WHERE cust_info.Cust_ID = '.$login'")
or die(mysql_error());

// puts the "users" info into the $info array
$info = mysql_fetch_assoc($data);

//Test Print of Login ID passed value
echo $data; WORKS Resource id #3
echo $info["Cust_Name"]; DOES NOT WORK
echo "$Cust_Name"; DOES NOT WORK

echo "$login

"; WORKS
echo $info["Cust_Company"]; DOES NOT WORK


1 Question is why I can echo the $login but then I canot pull anything from the query?
Table users
Cust_ID, Username, Password
Table cust_info
Cust_ID, Cust_Name, Cust_Company, Cust_Phone.....

2 I don't know if using the Cookie variable to use the login is a good idea. What would be the best way to pass the username to next page so I can use it in the SELECT ststement. Should I use a _SESSION global?

Thanks in advance

No comments posted yet

Your Answer:

Login to answer
263 Like 20 Dislike
Previous forums Next forums
Other forums

Form errors in an array
I'm processing a form and putting the errors in an array. empty($errors) doesn't seem to do the tric

Help with PHP Calendar code...
Hello, I'm new to this forum and I'm glad I found it.
I wrote this code for a PHP calendar as an

Auto install
Hi I have a directory lets say "apps" that I then have more folders ie "email",

Php mysql - select?
Hi i have this code:
Code: $iteminfo = mysql_query("SELECT desc FROM wc_items WHERE itemid =

disabling a button server-side then re-enabling client-side breaks button postback
I have a tabbed container and a button (not in the container) on a page. If the first tab is selecte

PHP submit form script causing blank page
Im trying to submit a form using this script, however nothing shows up on the page, does anyone know

Linking with Foreign Keys
I have been getting an erro when I try and link:

create table Faculty_Specialty (I_Name v

Stopped working!
So I had to change some stuff, none of it major. Stuff like the extension_dir and such. BEFORE I did

PHP webpage & array print issue
I have this code running, and it works perfectly … however, see my bottom bit about what I see

How to assign a textbox value to PHP variable??
Hi ! Can any one help me out as quickly as possible. As I m new to PHP.
Plz tell me how to assign

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash