Using two $_POST Function / Switch () statements, second does not work.

Posted on 16th Feb 2014 07:03 pm by admin

Hi all. I’m new to php and am having a problem getting $_POST Function / switch () to work. I am coding a registration form. I ask the user a Yes/No question. Depending on the answer I have an Include () bring in the coding for the next step of the registration process, which also has a Yes/No question. I am using submit buttons for the user to give me the answers.

The first $_POST Function / switch () works and will include () the proper coding. The second $_POST Function / switch () does not work.

Both are essentially the same coding with just the variable name changed.

This is the coding used:

<form action="register.php" method="post" name="regForm" id="regForm">
//
HTML in between, input user first name / last name
//
(This works)

// Asking if user is a real estate agent

<?php

$agent = " ";

if (!isset($_POST['agent']))
{
//If not isset -> set with dummy value
$_POST['agent'] = " ";
}

?>

<table align = "center" border="5" cellpadding="3" cellspacing="0">

<col width="430" >

<tr align = "center">

<td>

Are you a licensed Florida real estate agent?



// This is the submit buttons

<input type="submit" name="agent" value="No">&nbsp;&nbsp;

<input type="submit" name="agent" value="Yes">

</td>

</tr>

</table>

// Yes / No switch

<?php

$agent = $_POST['agent'];

switch( $agent ) {
case 'No':
include ("register_3.php");
break;
case 'Yes':
include ("register_2.php");
break;
}

?>

Once the above Yes/No is executed it brings in:

(This does not work)

// Asking if user want to sign up for foreclosure list

<?php

$forlst = " ";

if (!isset($_POST['forlst']))
{
//If not isset -> set with dummy value
$_POST['forlst'] = " ";
}

?>
<table align = "center" border="5" cellpadding="3" cellspacing="0">

<col width="430" >

<tr align = "center">

<td>

Would you like to receive our weekly foreclosure list (by email)



//This is the submit buttons

<input type="submit" name="forlst" value="No">&nbsp;&nbsp;

<input type="submit" name="forlst" value="Yes">

</td>

</tr>

</table>

// Yes / No switch

<?php

$forlst = $_POST['forlst'];

switch( $forlst ) {
case 'No':
include ("register_4.php");
break;
case 'Yes':
include ("register_4.php");
break;
}

?>

What am I doing wrong? Do I need to some how clear the POST before I use the function again? If so, how do I do it?

Your Answer:

Login to answer

Other forums

Entering Data Problem
Code: $result = mysql_query("SELECT * FROM flights");
while ($row = mysql_fetch_array($

Running External Scripts
I am very new to PHP and am not even sure what I'm asking is possible. I have just installed mediaW

Uploading/Downloading files stored in MySQL database
Hey all,

This problem just came up in my website and I'm having a hard time figuring out what

Problems with adding a link to one position in a 'foreach' loop, please help
Hello!

Iam pretty new to programming and I wanna create a table with users from an array. It

present value of sequence?
Hi

Please help me to find out the present value of sequence?

Thanks

How to get exact 3 moths post date from today date using javascript
How to get exact 3 moths post date from today date using javascript
Please help

Posting Serialized Data Not Working
I am trying to send an object from one PHP file to another using POST. I serialize the object and th

need help in php variable
i have a php variable on one page
Code: [Select]$lastId = mysql_insert_id($db);
echo $lastId;<

Confused with Loop
guys, i got confused with Looping...this is the case

I have 3 stocks, let say "Stock A&q

To add a field on the screen XK02.
Hi All,

How to add an additional field in the vendor change control screen XK02.
The