Using two $_POST Function / Switch () statements, second does not work.


Posted on 16th Feb 2014 07:03 pm by admin

Hi all. I’m new to php and am having a problem getting $_POST Function / switch () to work. I am coding a registration form. I ask the user a Yes/No question. Depending on the answer I have an Include () bring in the coding for the next step of the registration process, which also has a Yes/No question. I am using submit buttons for the user to give me the answers.

The first $_POST Function / switch () works and will include () the proper coding. The second $_POST Function / switch () does not work.

Did you know?Explore Trending and Topic pages for more stories like this.
Both are essentially the same coding with just the variable name changed.

This is the coding used:

<form action="register.php" method="post" name="regForm" id="regForm">
//
HTML in between, input user first name / last name
//
(This works)

// Asking if user is a real estate agent

<?php

$agent = " ";

if (!isset($_POST['agent']))
{
//If not isset -> set with dummy value
$_POST['agent'] = " ";
}

?>

<table align = "center" border="5" cellpadding="3" cellspacing="0">

<col width="430" >

<tr align = "center">

<td>

Are you a licensed Florida real estate agent?



// This is the submit buttons

<input type="submit" name="agent" value="No">&nbsp;&nbsp;

<input type="submit" name="agent" value="Yes">

</td>

</tr>

</table>

// Yes / No switch

<?php

$agent = $_POST['agent'];

switch( $agent ) {
case 'No':
include ("register_3.php");
break;
case 'Yes':
include ("register_2.php");
break;
}

?>

Once the above Yes/No is executed it brings in:

(This does not work)

// Asking if user want to sign up for foreclosure list

<?php

$forlst = " ";

if (!isset($_POST['forlst']))
{
//If not isset -> set with dummy value
$_POST['forlst'] = " ";
}

?>
<table align = "center" border="5" cellpadding="3" cellspacing="0">

<col width="430" >

<tr align = "center">

<td>

Would you like to receive our weekly foreclosure list (by email)



//This is the submit buttons

<input type="submit" name="forlst" value="No">&nbsp;&nbsp;

<input type="submit" name="forlst" value="Yes">

</td>

</tr>

</table>

// Yes / No switch

<?php

$forlst = $_POST['forlst'];

switch( $forlst ) {
case 'No':
include ("register_4.php");
break;
case 'Yes':
include ("register_4.php");
break;
}

?>

What am I doing wrong? Do I need to some how clear the POST before I use the function again? If so, how do I do it?
No comments posted yet

Your Answer:

Login to answer
273 Like 18 Dislike
Previous forums Next forums
Other forums

Why doesn't this work? (SSH2)
This is my script:

Code: <?php
$connection = ssh2_connect('213.251.167.109', 22);

Dealing with code in db query
I am dealing with C code and I need to make sure it is encoded some how to ensure its integrity and

PHP & Images [Resize, Crop, Save]
Hey! Well I have a little dilema, hoping I could find some guidance.

I have a CMS and on the

Do not allow posting of whitespace
Currently the script below works if the user does not type a name/message, but if i create a whitesp

Querying info from one table based on info in another
Hi, I am currently trying to make a part for my user driven website where one user can subscribe to

How do i use vars in an array
Hiya peeps!

How do I use a var in an array. You will see $id but it isnt working.


MYSQL gen help
This is my Mysql gen. can anyone tell me why this echos

MID(networkset.networkid, 3, 3) AS &q

Using unserialize()
Hi there.

I have some data in my database that is serialized.

e.g.

a:2:{i:0

reading partial code from external site
Hi,

I am trying to write a script for my website to get an article from an external website.

mysql UPDATE request not working and driving me crazy!!!
Hi,

I have been stuck on this for ages.

Quite simply I am trying to update my database

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash