Using two $_POST Function / Switch () statements, second does not work.
Posted on
16th Feb 2014 07:03 pm by
admin
Hi all. I’m new to php and am having a problem getting $_POST Function / switch () to work. I am coding a registration form. I ask the user a Yes/No question. Depending on the answer I have an Include () bring in the coding for the next step of the registration process, which also has a Yes/No question. I am using submit buttons for the user to give me the answers.
The first $_POST Function / switch () works and will include () the proper coding. The second $_POST Function / switch () does not work.
Both are essentially the same coding with just the variable name changed.
This is the coding used:
<form action="register.php" method="post" name="regForm" id="regForm">
//
HTML in between, input user first name / last name
//
(This works)
// Asking if user is a real estate agent
<?php
$agent = " ";
if (!isset($_POST['agent']))
{
//If not isset -> set with dummy value
$_POST['agent'] = " ";
}
?>
<table align = "center" border="5" cellpadding="3" cellspacing="0">
<col width="430" >
<tr align = "center">
<td>
Are you a licensed Florida real estate agent?
// This is the submit buttons
<input type="submit" name="agent" value="No">
<input type="submit" name="agent" value="Yes">
</td>
</tr>
</table>
// Yes / No switch
<?php
$agent = $_POST['agent'];
switch( $agent ) {
case 'No':
include ("register_3.php");
break;
case 'Yes':
include ("register_2.php");
break;
}
?>
Once the above Yes/No is executed it brings in:
(This does not work)
// Asking if user want to sign up for foreclosure list
<?php
$forlst = " ";
if (!isset($_POST['forlst']))
{
//If not isset -> set with dummy value
$_POST['forlst'] = " ";
}
?>
<table align = "center" border="5" cellpadding="3" cellspacing="0">
<col width="430" >
<tr align = "center">
<td>
Would you like to receive our weekly foreclosure list (by email)
//This is the submit buttons
<input type="submit" name="forlst" value="No">
<input type="submit" name="forlst" value="Yes">
</td>
</tr>
</table>
// Yes / No switch
<?php
$forlst = $_POST['forlst'];
switch( $forlst ) {
case 'No':
include ("register_4.php");
break;
case 'Yes':
include ("register_4.php");
break;
}
?>
What am I doing wrong? Do I need to some how clear the POST before I use the function again? If so, how do I do it?
No comments posted yet
Your Answer:
Login to answer
273
18
Other forums
BI in Upstream Production operations
Appreciate if you can assist in the following areas:
1) Examples of life before and after BI i
exclude characters from counting?
Hello, I wanted to ask if you have a string like:
Code: $my_s='ASRGREGTGTR----REGREGRE+++RRRRRR..
Email Processor
I have a few questions so this post will be a larger one! Sorry, but I'm a bit of a PHP newbie so be
that old Malformed Headers problem again!!!!! HELP!!!!!!
I've read the http://www.phpfreaks.com/forums/index.php/topic,37442.0.html
I don't think my c
There was a problem with the request. (Code: 0)
Any Idea what could cause this? I get it randomly at best. But with both IE and FF. It derives from
Please Help my PHP Dating Function.
Hi everyone!
Well here is my code that displays this:
It works wonderful.
How to assign a textbox value to PHP variable??
Hi ! Can any one help me out as quickly as possible. As I m new to PHP.
Plz tell me how to assign
Problem with PHP code- simple contact form
Hi Folks,
I'm relativily new to PHP; I know HTML and CSS stuff but I have a problem- I have a co
PHP error on MySQL insert
I'm sure it's the simplest of issues, but I can't recall why this isn't working.
Code: [Selec
Undefined index: username HELP NEWBIE
I am trying a simple login/logout for my website. It works well with checking if the username exists