Dynamic Array using glob?

Posted on 16th Feb 2014 07:03 pm by admin

Is there an easier way to do this?

I am trying to get create a dyamic array based on files within the folder.

Code: foreach (glob("*.jpg") as $filename) {
$items = array("title" => $filename)
}

$output = '<?xml version="1.0" encoding="ISO-8859-1"?>';
$output .= '<rss version="2.0">';
$output .= "<channel>";
$output .= "<title>" . $channel["title"] . "</title>";
$output .= "<description>" . $channel["description"] . "</description>";
$output .= "<link>" . $channel["link"] . "</link>";
$output .= "<copyright>" . $channel["copyright"] . "</copyright>";

foreach ($items as $item) {
$output .= "<item>";
$output .= "<title>" . $item["title"] . "</title>";
$output .= "</item>";
}
$output .= "</channel>";
$output .= "</rss>";

header("Content-Type: application/rss+xml; charset=ISO-8859-1");
echo $output;
?>

Your Answer:

Login to answer

Other forums

Target costs on Process orders not calculating
Hi All,

We have released standard costs for all the materials. We have also done Goods r

Function
How can I make this function that once you click the link in the code it takes you to a new page wit

how do i make new line after *
First check this page here. and you see my report. Im pulling form a mysql db. I want to beable to m

matching numbers inside ( )
I know I can match numbers by just [0-9]+, so I thought matching numbers inside ( ) would be somethi

mysql UNION | warning mysql_fetch_array !!
Code: <?php
$i = 0;
$query1="SELECT * FROM `products` WHERE `div

Help with email validation please...
Hi,
Please could you help.
I have a register.php login page where users register, the detail

Cant display mysql data
Hey all,

I am learning php and my first goal is to create a simple CMS. At the moment I am st

HTML form problem
Ive made a form to that i want to send to my email via PHP. but when it send only the name's etc sen

mysql_real_escape_string
Let me preface this that I am very much a PHP noob, but I have some SQL training (not necessarily My

why isn't this PHP code working ???
it's suppose to find a name on the database.

<?php

$s = $_POST["lname&