listing help


Posted on 16th Feb 2014 07:03 pm by admin

Hi,

at first, great new design!!! I like it,

i got a problem,

I want to list some tekst, but there is a users, users can list they own texts, and all teksts, and find words in all texts and in own texts

somethings is weong in my php code because ist dont work

At first here is the form file:

Code: <div>
<form name="TextSearchForm" action="<?php print "list_txt_search.php";?>" method="post" target="main">

<div><select name="sn_text_year" style="text-align: center;">
<option selected="selected"> Year </option>
<option value="2009">2009</option>
<option value="2010">2010</option>
<option value="2011">2011</option>
</select>
</div>

<div><select name="sn_text_author" style="text-align: center;">
<option selected="selected"> choose </option>
<option value=""> all txt </option>
<option value="<?php print $UsrNrID;?>"> my txt </option>
</select>
</div>

<div><input type="text" name="TextSearch" size="30" /></div>
<div><input type="submit" name="SubmitTxtSerch" value="LIST" class="Button" /></div>

</form>
</div>

3 selection is there:
"sn_text_year" (which year is text wroten)
"sn_text_author" (who is the author of the text - this is a cookie whith name of the user)
"TextSearch" (if the user want to find some word in database)


Code: <?php
$TextSearch = $_POST['TextSearch'];
?>



<?php
// UsrIdentify
$query_user = mysql_query("SELECT * FROM `sn_users` WHERE `sn_users_username` = '".$_COOKIE['loggedin']."'");

if(!$query_user){
print mysql_error();
exit;
}

$RequestUsrID = mysql_fetch_array($query_user);


$UsrID = $RequestUsrID['sn_users_id']; // HERE I CAN TAKE THE USERS ID
?>



<?php

if ( $TextSearch == '' && $UsrID ) {
$QeryUsr = "SELECT * FROM `sn_text` WHERE `sn_text_godina` = '" . $_POST['sn_text_year'] . "' AND `sn_text_author` = '" . $UsrID . "' ORDER BY `sn_text_id` DESC";
}

if ( $TextSearch == '' && $UsrID == '' ) {
$QeryUsr = "SELECT * FROM `sn_text` WHERE `sn_text_year` = '".$_POST['sn_text_year']."' ORDER BY `sn_text_id` DESC";
}

if ( $TextSearch && $UsrID == '' ) {
$QeryUsr = "SELECT * FROM `sn_text` WHERE ucase(`area1`) LIKE '%".$TextSearch."%' OR lcase(`area1`) LIKE '%".$TextSearch."%' AND `sn_text_year` = '".$_POST['sn_text_year']."' ORDER BY `sn_text_id` DESC";
}

if ( $TextSearch && $UsrID ) {
$QeryUsr = "SELECT * FROM `sn_text` WHERE ucase(`area1`) LIKE '%".$TextSearch."%' OR lcase(`area1`) LIKE '%".$TextSearch."%' AND `sn_text_year` = '".$_POST['sn_text_year']."' AND `sn_text_author` = '" . $UsrID . "' ORDER BY `sn_text_id` DESC";




// Admin capacityes
$query_user = mysql_query( $QeryUsr );

if(!$query_user){
print mysql_error();
exit;
}

while($request = mysql_fetch_array($query_user)) {

// list
}
?>


As You see You can choose:

1. Only year of text wroten
2. No text search, but identify User
3. No text search, no User identification - mean ilst all text
4. Search text, and identify User (mean searching word only in Users texts)

So, something is wrong, because:
1. when I choose Year, and list all text - list only my texts
2 when I choose Year, and list my texts - list only my texts
3. when I choose Year, and list my texts, with searching text - list only my text without choose
4. when I choos Year, and list all text, with serching text - its work fine

I see its a complicated, I hope, that You can give mi a solution

thanx

No comments posted yet

Your Answer:

Login to answer
320 Like 27 Dislike
Previous forums Next forums
Other forums

Gantt Chart Tool
Does anyone know of a good free gantt chart creator tool

Thanks

Lining up columns nicely.
Hello everyone, I'm having problems with making columns line up properly. Here is my code:

Warning: mysql_num_rows() expects parameter 1
When i add quote at the end of this link
example:http://localhost/articlemania/category.php?cid=3

XML Grouping
I'm using xml_parse_into_struct to get all my elements, but now I need to group them. For example, h

Need help: how to catch acess of undefined class properties
Hello. I am learning OO with PHP and have hit a problem.
Some code runs as perfectly valid code,

I think i'm using the syntax incorrectly
Hi Everyone!

I'm new to this forum and a newbie with PHP - I'm glad I found this site - I hop

quick basic question, hopefully not dumb
I don't know how to search for this, so forgive me if it's been covered...

I often see an exa

FTP issues
Hi all,


I am currently facing some serious problems with a script and really need some ad

this code is not working????
it says this error.. Warning: Division by zero in ..

the variables are correct, so why is th

parse error
Parse error: syntax error, unexpected '[', expecting ')' in /Users/admin/Sites/phptest/array.php on

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash