listing help
Posted on
16th Feb 2014 07:03 pm by
admin
Hi,
at first, great new design!!! I like it,
i got a problem,
I want to list some tekst, but there is a users, users can list they own texts, and all teksts, and find words in all texts and in own texts
somethings is weong in my php code because ist dont work
At first here is the form file:
Code: <div>
<form name="TextSearchForm" action="<?php print "list_txt_search.php";?>" method="post" target="main">
<div><select name="sn_text_year" style="text-align: center;">
<option selected="selected"> Year </option>
<option value="2009">2009</option>
<option value="2010">2010</option>
<option value="2011">2011</option>
</select>
</div>
<div><select name="sn_text_author" style="text-align: center;">
<option selected="selected"> choose </option>
<option value=""> all txt </option>
<option value="<?php print $UsrNrID;?>"> my txt </option>
</select>
</div>
<div><input type="text" name="TextSearch" size="30" /></div>
<div><input type="submit" name="SubmitTxtSerch" value="LIST" class="Button" /></div>
</form>
</div>
3 selection is there:
"sn_text_year" (which year is text wroten)
"sn_text_author" (who is the author of the text - this is a cookie whith name of the user)
"TextSearch" (if the user want to find some word in database)
Code: <?php
$TextSearch = $_POST['TextSearch'];
?>
<?php
// UsrIdentify
$query_user = mysql_query("SELECT * FROM `sn_users` WHERE `sn_users_username` = '".$_COOKIE['loggedin']."'");
if(!$query_user){
print mysql_error();
exit;
}
$RequestUsrID = mysql_fetch_array($query_user);
$UsrID = $RequestUsrID['sn_users_id']; // HERE I CAN TAKE THE USERS ID
?>
<?php
if ( $TextSearch == '' && $UsrID ) {
$QeryUsr = "SELECT * FROM `sn_text` WHERE `sn_text_godina` = '" . $_POST['sn_text_year'] . "' AND `sn_text_author` = '" . $UsrID . "' ORDER BY `sn_text_id` DESC";
}
if ( $TextSearch == '' && $UsrID == '' ) {
$QeryUsr = "SELECT * FROM `sn_text` WHERE `sn_text_year` = '".$_POST['sn_text_year']."' ORDER BY `sn_text_id` DESC";
}
if ( $TextSearch && $UsrID == '' ) {
$QeryUsr = "SELECT * FROM `sn_text` WHERE ucase(`area1`) LIKE '%".$TextSearch."%' OR lcase(`area1`) LIKE '%".$TextSearch."%' AND `sn_text_year` = '".$_POST['sn_text_year']."' ORDER BY `sn_text_id` DESC";
}
if ( $TextSearch && $UsrID ) {
$QeryUsr = "SELECT * FROM `sn_text` WHERE ucase(`area1`) LIKE '%".$TextSearch."%' OR lcase(`area1`) LIKE '%".$TextSearch."%' AND `sn_text_year` = '".$_POST['sn_text_year']."' AND `sn_text_author` = '" . $UsrID . "' ORDER BY `sn_text_id` DESC";
// Admin capacityes
$query_user = mysql_query( $QeryUsr );
if(!$query_user){
print mysql_error();
exit;
}
while($request = mysql_fetch_array($query_user)) {
// list
}
?>
As You see You can choose:
1. Only year of text wroten
2. No text search, but identify User
3. No text search, no User identification - mean ilst all text
4. Search text, and identify User (mean searching word only in Users texts)
So, something is wrong, because:
1. when I choose Year, and list all text - list only my texts
2 when I choose Year, and list my texts - list only my texts
3. when I choose Year, and list my texts, with searching text - list only my text without choose
4. when I choos Year, and list all text, with serching text - its work fine
I see its a complicated, I hope, that You can give mi a solution
thanx
No comments posted yet
Your Answer:
Login to answer
320
27
Other forums
in php, link returns to the line
When I add a link in a php page, the link word returns to the line (as a
would do)
Examp
frames get header location..
i have two frames, one top, one bottom. how do i do a form on the bottom frame that gives me the ur
session_destroy();
new to php
I have a simple login and am trying to write a logout.
I set a $_SESSION var to 1 i
Material xxx does not exist in plant xxx
Dear All,
I am working for a steel project which is repetitive manufacturing.
Line break?
Hi, I'm new to the forum and new to php. I'm not sure if I'm using the correct terminology so here i
Using CSS to format MySQL query
Hi,
If i want to have a news page on my site, which displays all records of a table in descen
Display search result
Hi!
I have a SQL database with information about albums and track (music).
This is wh
get url?
how do i get the url of the page i'm currently on, on my website.. i think its get header.. how do i
problem with php mysql query
Hi guy's...
I'm totally lost here..because don't have any idea how to make a query for grab r
Extract specific information from a PHP Multidimensional Array
Howdy! I've racked my brain over this for 24 hours now. I think it's time I asked for help. I'm lear