need help in update query
Posted on
16th Feb 2014 07:03 pm by
admin
hi
i have a dynamic form. i need help in how can i use update query when values from dynamic form get pass to php file.
currently when i press submit it displays this and does not update fields
Code: UPDATE contacts SET name='Array', im='Array' WHERE userid='1'
this my code for dynamic form
Code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript" src="lib/jquery-1.4.min(Production).js"></script>
<script>
var id = 0;
function addFormField() {
//document.getElementById("id").value;
id++;
$("#divTxt").append(
"<p id='row" + id + "'><label>Relation <select name='relation[]' id='relation" + id + "'><option value='brother'>Brother</option><option value='sister'>Sister</option><option value='father'>Father</option><option value='mother'>Mother</option></select> <input type='text' name='name[]' /> <a href='#' onClick='removeFormField("#row" + id + ""); return false;'>Remove</a></p>"
);
}
function removeFormField(id) {
$(id).remove();
}
</script>
</head>
<body>
<form action="addDynamicFields.php" method="post" id="form1">
<label>Relation</label>
<select name="relation[]" id="relation0">
<option value="brother">Brother</option>
<option value="sister">Sister</option>
<option value="mother">Mother</option>
<option value="father">Father</option>
<option value="daughter">Daughter</option>
<option value="son">Son</option>
</select>
<input type="text" name="name[]" />
<div id="divTxt"></div>
<p><input type="submit" value="Submit" name="submit">
<!-- <input type="reset" value="Reset" name="reset"> --></p>
</form>
<p><a href="#" onClick="addFormField(); return false;">Add</a></p>
</body>
</html>
this is my php file
Code: <?php
$screenname = $_POST['relation'];
$name = $_POST['name'];
$connect = mysql_connect("localhost","user","pass");
mysql_select_db("test");
for($i=1; $i<count($screenname); $i++) {
//$imscreenname = $_POST['screenname'][$i];
//$imname = $_POST['name'][$i];
//echo $imscreename;
//$imscreenname = $screenname[$i];
$screennamesave = "UPDATE contacts SET name='$screenname', im='$name' WHERE userid='1'" or die(mysql_error());
$result = mysql_query($screennamesave);
echo $screennamesave;
}
?>
No comments posted yet
Your Answer:
Login to answer
170 
40 
Other forums
Displaying pictures
i have worked my way through storing images in directory and storing the location in mySQL db.Now i
Error In Syntax
I got this error:
Code: Parse error: syntax error, unexpected '>' in /home/bucket/publ
array_diff weirdness
I'm using the following bit of code
$diff = array_diff($pids, $pidlist);
$diff = array_va
PHP template help
Ok, I don't know if anyone can help me but I am using PHP templates to make a site. I am a newbie an
Send current URL in URL with a $_GET variable problem.
Hello community,
I have created a function that gets the current variable of a page, example:
Career Change into SAP
Hai
I am sajesh ,did my diploma in Mechatronics i have a 4 years of experience in
Output Buffering question
Hi all,
I've been trying to wrap my head around output buffering. So far I've found tons of
SOAP Issue
Hi,
I am facing some understanding problem with SOAP basic.kindly recommend some SOAP expert.
Alterar a hora do servidor
Se alguém souber, ajude-me a adicionar 6 horas, obrigado
<tr>
&
Using cURL to PUT
Can somebody help with the correct php code to make a cURL PUT request. Here is a sample of code bel
