$action = "insert"; //$action = $_GET['action'];


Posted on 16th Feb 2014 07:03 pm by admin

$action = "insert";
//$action = $_GET['action'];

why is this invalid type? I am just modifying code that is there and want the action = insert so it will run all the parts of the code for insert and nothing else...

No comments posted yet

Your Answer:

Login to answer
139 Like 22 Dislike
Previous forums Next forums
Other forums

whats wrong with my code please help!!!
this is the error


Warning: mysql_close(): supplied argument is not a valid MySQL-Link res

Session login issue
I'm wondering how to fix a problem I'm having with a session-based login system

Say I go to h

Sending CC Info by email
I am a little bit less knowledgable in the security area as most developers and I know I have a lot

Query issues
I probably have this setup wrong well I know I do because nothing is showing up now. What I want is

Progress bar tracking file downloads
Hey guys, was wondering if there was a way to track how far a file has been downloaded. I know there

rename the file
File.txt

Code: ***DOCUMENT***
..DN:
000044255
..CB:
..SN:
..PY:
2009
..E

PHP Game
hy i was wondering what's the best method in order to make some automatic updates in a php game
<

Two fgetcsv related questions ;D
First of im trying to get a file from a merchants server but the directory is protected, I know the

Include ("Absolute Path") of a file?
I'm not sure what I'm doing wrong. I am writing my php code in the same directory of the file that

browse folder only
hi,
is there a way i can browse or get the directory or folder only and not the file?
i just w

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash