$action = "insert"; //$action = $_GET['action'];


Posted on 16th Feb 2014 07:03 pm by admin

$action = "insert";
//$action = $_GET['action'];

why is this invalid type? I am just modifying code that is there and want the action = insert so it will run all the parts of the code for insert and nothing else...

No comments posted yet

Your Answer:

Login to answer
139 Like 22 Dislike
Previous forums Next forums
Other forums

how do I show what a user have selected from a checkbox?
From my code below, how would i show which check boxes have been checked and which radio buttons sel

WM transfer order: confirm different batch than proposed by system
Hi folks,

following scenario: we have a full WM with mixed batch numbers allowed in stora

user data not transferring to new page
I'm a PHP learner. After an index.php page, the user goes to a login.php page. Both pages seem to

A Few Questions
Hi, I want to ask a few questions that I can't seem to find..

1) I'm creating a "shortcu

empty() error
Why does

Code: empty($USER_ID = $_SESSION["USER_ID"])
create this error...

default SAP userid
hi,, I just like to know if it is ok to use the default SAP user id (SAP*)?

problem with array - multilingual page
this is my test page :
Code: <?php
if(isset($_GET['lang'])) {
if($_GET['la

Ten Operator Syntax
Hi Guys,

I can't figure out why i am getting a parse error with this basic ten op code:

Program with calculate Meteorologic measurements
Hello I'm a beginner and I want to make a program with calculate Meteorologic measurements:
ba

CHECH A STRING FOR ' " ' (DOUBLE QUOTES)
I am checking for delimiter (.!?) and if there is a " after a sentence then it should neglect a

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash