$action = "insert"; //$action = $_GET['action'];


Posted on 16th Feb 2014 07:03 pm by admin

$action = "insert";
//$action = $_GET['action'];

why is this invalid type? I am just modifying code that is there and want the action = insert so it will run all the parts of the code for insert and nothing else...

No comments posted yet

Your Answer:

Login to answer
139 Like 22 Dislike
Previous forums Next forums
Other forums

Strange PHP/mySQL error ... am I just tired?
Code: <?

## CONNECT TO DB FUNCTION!
function ConnectTo($db2con)
{
$hostNam

update the selected existing records of database
Hi frndz,
I am new to php and get stuck....

Edit.php > Update.php > Updatea

Deleting Partners on the Customer Master.
Does SAP handle removing the Partner from Open Sales Orders when a Partner is deleted in the Custome

php/mysql auto logout after 2 hour and reset password
Hi all,

This I hope will make sense. I've the following code which when a user logins in, cr

Call db table from any PHP file
Hi,

I want to be able to call a database table that will be setup in another file called init

Calling a Procedure with IN & OUT Parameters
Hello,

I usually call my procedures using the following way

declare variable e

Help With editting and deleting form
Hallo !!

So look at this image :

http://img194.imageshack.us/img194/8272/snapshot5f.pn

Finding digits in variable containing text, and IDing them
$romanstock = "http://www.remoteprice.com/data.asp?storeid=123&itemcode=456&typ

want a code for uploading and downloading
i m trying to upload and download to my site..i need upload and download code ...i use a code for up

.htpasswd Registration Form
Hi,
I wanted to make an htpasswd registration form.
I found this code on the internet but have

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash