Problem with variable declaration in switch statement

Posted on 16th Feb 2014 07:03 pm by admin

Hello, I am having some trouble assigning a value to a variable inside a switch statement. What I am trying to do here is trip an error if the user has already added an item in the shopping cart. The While and Foreach loops work perfectly fine. The problem is that the value of variable $error does not get passed outside of the case. As a result, I cannot get the error message to display. I really need to get this to work and any help is appreciated. The code looks something like this:

Code: switch ($action) {
case 'add' :
{
if ($_SESSION['CartID'] == "")
{

$query = 'INSERT INTO ShopCart( UserID )VALUES("' . $UserID . '")';
mysql_query($query, $db) or die(mysql_error($db));

$Shop = 'SELECT ShopCartID FROM ShopCart WHERE UserID = "' . $UserID . '" ORDER BY ShopCartID ASC LIMIT 1';
$Cart = mysql_query($Shop);
$ShopCart = mysql_fetch_row($Cart);
$_SESSION['CartID'] = $ShopCart[0];
}
$query = 'SELECT ProductID FROM ShopCartLine WHERE ShopCartID = "' . $_SESSION['CartID'] . '"';
$result=mysql_query($query, $db) or die(mysql_error($db));

//$row = mysql_fetch_row( $result );
while($var = mysql_fetch_array($result))
{
foreach ($var as $i) {
if ($i == $ProductID) {
$error = 1; //TRIP THE ERROR HERE!
echo "<script type='text/javascript'>window.top.location='http://amarcy2.db-class.ids.uic.edu/shopcart.php';</script>";
}
}
}
}


The code being used to display the error message is as follows:

Code:
if ($error == 1) {
echo '<p>You already have this item in your basket!</p>';
}

Your Answer:

Login to answer

Other forums

Echoing a Variable from a Object
How do I get a variable from the new User Class to echo out in this clasS?

class MyApp
{

ALV sum various columns problem
Hi all,
I'm doing a report on ABAP for a timesheet of the current month. The output i want is s

Need help to modify php ELSE code
I'm trying to find a way to have the php code display a message if there is no inventory listed in t

Renaming array keys
The issue: renaming array keys inside a foreach loop.

I'm trying to build a pie chart image w

Links not updating
I'm trying to fuel a simple navigation system for a news section. It works fine when it comes to ret

ereg_replace()
Basically what i need to do is

$title = "This Suck's"

$striped = ereg_repl

Target costs on Process orders not calculating
Hi All,

We have released standard costs for all the materials. We have also done Goods r

mysql UNION | warning mysql_fetch_array !!
Code: <?php
$i = 0;
$query1="SELECT * FROM `products` WHERE `div

PHP & Images [Resize, Crop, Save]
Hey! Well I have a little dilema, hoping I could find some guidance.

I have a CMS and on the

links using header()
Hi All

I'm not sure where to ask for help on this but I hope someone can offer some. I'm at