Using two $_POST Function / Switch () statements, second does not work.

Posted on 16th Feb 2014 07:03 pm by admin

Hi all. I’m new to php and am having a problem getting $_POST Function / switch () to work. I am coding a registration form. I ask the user a Yes/No question. Depending on the answer I have an Include () bring in the coding for the next step of the registration process, which also has a Yes/No question. I am using submit buttons for the user to give me the answers.

The first $_POST Function / switch () works and will include () the proper coding. The second $_POST Function / switch () does not work.

Both are essentially the same coding with just the variable name changed.

This is the coding used:

<form action="register.php" method="post" name="regForm" id="regForm">
//
HTML in between, input user first name / last name
//
(This works)

// Asking if user is a real estate agent

<?php

$agent = " ";

if (!isset($_POST['agent']))
{
//If not isset -> set with dummy value
$_POST['agent'] = " ";
}

?>

<table align = "center" border="5" cellpadding="3" cellspacing="0">

<col width="430" >

<tr align = "center">

<td>

Are you a licensed Florida real estate agent?



// This is the submit buttons

<input type="submit" name="agent" value="No">&nbsp;&nbsp;

<input type="submit" name="agent" value="Yes">

</td>

</tr>

</table>

// Yes / No switch

<?php

$agent = $_POST['agent'];

switch( $agent ) {
case 'No':
include ("register_3.php");
break;
case 'Yes':
include ("register_2.php");
break;
}

?>

Once the above Yes/No is executed it brings in:

(This does not work)

// Asking if user want to sign up for foreclosure list

<?php

$forlst = " ";

if (!isset($_POST['forlst']))
{
//If not isset -> set with dummy value
$_POST['forlst'] = " ";
}

?>
<table align = "center" border="5" cellpadding="3" cellspacing="0">

<col width="430" >

<tr align = "center">

<td>

Would you like to receive our weekly foreclosure list (by email)



//This is the submit buttons

<input type="submit" name="forlst" value="No">&nbsp;&nbsp;

<input type="submit" name="forlst" value="Yes">

</td>

</tr>

</table>

// Yes / No switch

<?php

$forlst = $_POST['forlst'];

switch( $forlst ) {
case 'No':
include ("register_4.php");
break;
case 'Yes':
include ("register_4.php");
break;
}

?>

What am I doing wrong? Do I need to some how clear the POST before I use the function again? If so, how do I do it?

Your Answer:

Login to answer

Other forums

how to remove in php string display
My code is

$message="We're looking at developing our website.";

$body= "

text box alphanumeric caracters only
hi all!

I have search on google on how to enter in a test box only caracters A-Z,a-z,0-9 usi

Reading waves
Hi,

I am trying to find a way of finding the highs and lows on a graph line, the line points

Find current logon time
Hi,
in my sql script i want to query and find out the logon time of the current session.
<

Embedding flash object in Else statement
This is my first major project in PHP and I'm having some trouble embedding a flash object in an Els

Transform value 0 in no and 1 in yes help needed
Hello,
I have this in the table: "value" type int 0 to represent false and 1 to represe

Embed Video Problem
Hey, thanks for looking!

File to be embedded:

Code: <playlist version="1&q

Unable to display contents in Second Drop Down Box
Hi All,

What I am trying to do is 2 dependent drop down boxes and when user selects su

Script not running properly
Hello Everyone
This is a basic script for posting to a database. I'm not sure why it doesn't work

Using two $_POST Function / Switch () statements, second does not work.
Hi all. I’m new to php and am having a problem getting $_POST Function / switch () to work. I