Error in query: Resource id #4??


Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

No comments posted yet

Your Answer:

Login to answer
216 Like 41 Dislike
Previous forums Next forums
Other forums

Sending UDP Raw socket
I truly need help on this. I am trying to write a test program that simulate a network environment

Chat Box in PHP
I was thinking in doing a Chat Box in PHP. For that I would use a form with two fields, Nick and Mes

Creating web pages by php
Hello again,
I was just wondering us there a way to use a php script to create a new web page. I

All possible combinations of String in PL/SQL
Hi All,

Could you please explain the logic of getting all possible combinations of String

Trouble with a select list
Hello All!
I was wondering if any of you guys could help me with a small problem I'm having!

Just a white page
Okay so, my website, when I click SignUp on it it takes me to /join.php but its a complete white pag

Echo-ing MySQL content and Keep Formatting?
I have data in my MySQL such as:

QuoteBlah blah

Blah blah

etc
but when i ech

IMAGE - SERVER SIDE scripting help...
How to receive pixel data of an image and buid a bitmap file on the server using the HTTP POST metho

query based on 2 conditions
I want to select if the doc_type is either s OR f but this doesn't work:

Code: [Select]$query

turning an array into a string then poping it into a db
Hi im just wondering how you get a requested array into a single string then pop it into the db so f

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash