Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216
41
Other forums
records between 2 dates
Hello all,
I have a date tracked table which contains effective_start_date and effective
Why use interfaces in PHP (OOP)
I am learning OOP in PHP and its been a pretty good learning experience so far. What I didn't unders
Need help in Generating Combinations
Need help generating all possible combination of names in an array
Lets say i have the follow
Check premium expire
Hi,
I am making a simple file hosting site and want to check if users premium subscriptions h
shift numbers with paging
Hi
How would i be able to display 10 numbers 1 2 3 4 5 6 7 8 9 10
and when I click next
FAGL_FC_TRANSLATION FAS52 New GL ECC 6.0
Hello,
The new program for Translating GL Balances (FAS 52) gives the option to use diffe
i want run some web server under the ip sharer
hello i want run some web server under the ip sharer
my ip is floating ip but it doesnt matter
How to validate from 2 possible answers
Hi
I hope somebody can help me with what will probably be really simple, I'm pulling my hair
Contents of variable not echoing
Hey guys, hopefully this is an easy one...
In this line, the variables are not echoing out. T
Last character removed
I have created a string from an array. I have inserted commas from my form values. I am trying to re