Error in query: Resource id #4??

Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

Your Answer:

Login to answer

Other forums

Google Map
I have done Google Map Integration for one my project. But for that we need the "latitude and l

Insert Failing.
Hey,
I am making a Sign up page for a website, but the insert query into the Database does not se

Embedding flash object in Else statement
This is my first major project in PHP and I'm having some trouble embedding a flash object in an Els

Query output more than expected
$query=mysql_query("SELECT * FROM players, communities, divisions WHERE dob BETWEEN '{$start_da

Just a white page
Okay so, my website, when I click SignUp on it it takes me to /join.php but its a complete white pag

Give me all your tricks for minimizing jar file size

Hi, I'm coming close to releasing my J2ME game... I am kicking up against the 64k size barrier w

Problem Dereferencing
With these types and tables:

CREATE TYPE MANAGER AS OBJECT (
MGR_ID INTEGER,

php/mysql problem
Hey all,

Problem: im trying to setup a shop where people can use a drop-down list to select t

Interpret Order
Hello all,

I'm wondering if I have this:

Code: $switch = array(
'one' =>

Files in current folder. Should be an easy fix.
Never mind. I've asked about this before and just found my answer. Anyway to delete this?