Error in query: Resource id #4??

Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

Your Answer:

Login to answer

Other forums

Change log of Cost centre change in Plant maintenance order
Hi,
How to view Change log of Cost centre in Plant maintenance order. Not visible thru 'Docume

Comparing Values
Hi
I'm reading data from a database and this seems to work OK.

Each system has an associat

Issue Parsing XML into table
Hello all,

Im a bit new to php and new to phpfreaks. But thanks in advance for the help!
<

Variable Clash
In the past I've had variables clash. For example:

Code: <?php
$c = 5;
$ca

Help with translating C code into assembler code
Hi im doing a project that moves a robot around a maze avoiding walls and need some help with conver

mySQL and PHP search
Hello,
I am trying to code a project and ran into a brick wall with one of my pages. I am pretty

Reditecting pages based on logic
Newbie here, apologies in advance!

I am trying to use the header function to forward one of a

what are '%S%', '%E%'
for example when i see Code: [Select]printf("Hello %srn", $name);
what does %s means

Hom to make one url to open together with another url
I have a chat, which i want to be opened, as soon as the users login to the site. As it is now, when

I think i'm using the syntax incorrectly
Hi Everyone!

I'm new to this forum and a newbie with PHP - I'm glad I found this site - I hop