Error in query: Resource id #4??


Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Did you know?Explore Trending and Topic pages for more stories like this.
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out
No comments posted yet

Your Answer:

Login to answer
216 Like 41 Dislike
Previous forums Next forums
Other forums

Problem with HTML form
Hello,

I made a HTML form with some fields and check box.
Everything works fine except whe

Help with syntax
Hi all!

The $bridge variable is not getting passed while it is contained in the line below:

uploading video files into mysql in php
hi,
I have the video files which i have to upload into mysql db. along with creating thumbnails f

More pug propaganda.
http://www.youtube.com/watch?v=8Kkrmubsgf8

The commercial is definitely worth watching pug aw

Email Form Syntax Issue
I need the TO: in email to display To: CEO instead of To: abc@mail.com

How to alter the scri

Strange PHP/mySQL error ... am I just tired?
Code: <?

## CONNECT TO DB FUNCTION!
function ConnectTo($db2con)
{
$hostNam

Perplexing problem showing a .jpg
Please disregard..........I figured it out

Print 'a' to 'z' via for loop
A very simple problem..
How Can I print a to z NOT a to y ?
It is a part of a code where
<

how to put the 0-100 numbers into 1.txt and 100-200 into 2.txt ?
how to put the 0-100 numbers into 1.txt and 100-200 into 2.txt and so on 200-300 into file 3.txt ?

Backflush
I am looking for a report in SAP that would give me a list of all parts that are populated with a ba

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash