Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216
41
Other forums
php problem?
I don't think I'm stupid, but maybe I am.
I am working on a sit for a friend I am try to put
Not "Just Another" MMORPG - text based.
Hello,
I've been learning MySQL and PHP for the last 2-3 years.
Though, I've had long paus
natcasesort works on one server but not on another
Hi
I have a problem that I was hoping that someone can help me with.
I'm trying to use
PHP url branch??
Functionally, using PHP, I'm doing a test of login input submitted by a user via an html form in a f
Getting number of affected rows in SQLPLUS..
Hi everyone,
I have a shell script where i am invoking sqlplus, running a query and saving t
Update Database
Hi All,
I have a problem with this:
Code: [Select]<?php
session_start();
scandir clients directory
hi,
how can i scandir the clients directory? i need a script that when i click a button it will u
mails going in spam??
The mails I sent to folks in my database using mail(function) are going in spam??
Any idea ho
Unidentified index error in a simple form
I have been trying to make an HTML form that is handled by a PHP script. So far my attempts to get i
getting rid of quotes in strings
sick of trying to deal with them in multiple ways (entering in and taking from database, echoing, ec