Error in query: Resource id #4??

Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

Your Answer:

Login to answer

Other forums

couldn't connect to your database
Hello I am new to php mysql

Actually i have read A tutorial on nettuts
"http://net.tu

A Few Questions
Hi, I want to ask a few questions that I can't seem to find..

1) I'm creating a "shortcu

Unexpected T_Variable ?
Hi all,
I dont really know what I am doing!! I know I'm doing something wrong, and I know its on

upload image name with extension using php
hi frds..

<input id="file1" type="file" name="file[]" &a

question about n
I was looking at some of the things you could do with php and one of the things I have tried is n.<

C++ Http request?
Code: string Response = "LOGIN_UNSUCCESSFUL"; System.Net.WebRequest request = Sy

Displaying data from database into a 2 dimensional table
Good day!

I'm a beginner in PHP and I'm not expecting a full coding for this qestion. I'm jus

Consuming third party Payment Gateway API from Procedure.
Hi All,

First of all i would like to thank all the people of the oracle forum for providi

IF Statement & Two Tables With Different Echoes
I'm retrieving two tables in a single query using UNION ALL, like so:

Code: $query = "SE

uploading video files into mysql in php
hi,
I have the video files which i have to upload into mysql db. along with creating thumbnails f