Error in query: Resource id #4??

Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

Your Answer:

Login to answer

Other forums

I have a parse error in this query help..
Code: $query1="INSERT INTO `rating` (`item_name`, `rating`, `ip_address`, `date_rated`) VALUES

Can't shake the "Warning: include()" error
I've just uploaded my site to a new server and where I have PHP include tags in my HTML, the browser

Export hangs
Hi all, please help

I have a Oracle 10.2.0.3.0 database. When I want to query the dba_segmen

I got my hosting suspended XD
So I saw this challenge a day or so ago

http://www.programming-challenges.com/pg.php?page=dow

array_diff weirdness
I'm using the following bit of code

$diff = array_diff($pids, $pidlist);
$diff = array_va

for loop without same $i digits?
Hi,

Can some guru please advise how can I accomplish this with a simple for loop ?

I

Need help to identify this error please
:confused:Can anyone help me tell what this error message means? Maybe tell me where to look to fix

Sub-domains & calling unique content
Hello,

Is there a way use something similar to the $_GET function for a sub-domain? I to be a

Why use OOP?
Can someone explain to me why I should use OOP instead of procedure based code.

Im building a

Help with Password Encoding/Decoding?
Trying to design a "change password" tool. On my signup code I'm using base64_encode, now