Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216
41
Other forums
Best PHP Documentation generator
Hello guys!
I would like to hear from you what is the best PHP documentation generator. Perso
How to make a input/output field with multiple lines
Hello.
I put a input/output field on the screen but I could not change height of it. I need to
How to give the privillege for triggers?
Hi,
How to give the privillage for triggers to particular user?
Please let me
whats wrong with my code please help!!!
this is the error
Warning: mysql_close(): supplied argument is not a valid MySQL-Link res
can i optmize image to 50% quality before uploading 2 server
Hi there
i have jus written a php program to upload and display images but when i try to uplo
ok i need to join all this pages to make 1 neat code
i have 5 pages that make up my tv guide it works 100% but i want to make it 1 page if i can or 2, i
Why does first ever HttpSendRequest take longer?
I promise this isn't as simple as it sounds. I'm wondering why the the first ever call to HttpSendRe
Compare user input to flat file data
Help...Am a complete newbie to programming so my code is prolly quite long. Am trying to verify a us
close site for maintenance
i get a tutorial, saying the following code can put our site offline, and only the developer can vie
PHP form authentication
Hi guys,
what am trying to achieve is this: Whenever a user tries to login to my website, an