Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216
41
Other forums
Help with PHP Calendar code...
Hello, I'm new to this forum and I'm glad I found it.
I wrote this code for a PHP calendar as an
search function
HI guys,
if anyone could point us in the right direction of how to do this, or provide some t
registration form
first time posting. did some searches but didnt find exactly what i am looking for. dont flame cause
There was a problem with the request. (Code: 0)
Any Idea what could cause this? I get it randomly at best. But with both IE and FF. It derives from
Problem Dereferencing
With these types and tables:
CREATE TYPE MANAGER AS OBJECT (
MGR_ID INTEGER,
Bit manipulation program with binary operations
My homework is to create a program to scan in and add binary numbers and print them like so
Cron Job and Output
I have php codes running under a cron job.
But everytime i output (echo) , it comes out as comple
HTML Viewer HIDE scrollbar
How can I disable scrollbars in a HTML Viewer control? I can't hide them. Even i have enough space b
PHP & MS Access - Line Break
Hey Guys!
I'm pulling records from an MS Access database and listing them using PHP and I'm r
How to ask a regex question?
Hi, I thought I'd share some of my insight after seeing too many bad questions that either get ignor