Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216
41
Other forums
Entering Data Problem
Code: $result = mysql_query("SELECT * FROM flights");
while ($row = mysql_fetch_array($
Need help with a mail notify function
I was tasked with setting up a site that's been prewritten. The site is basically a form that captur
image upload, resize THEN submit form
Ok so I have a form that requires the user to upload an image, and then do something with that image
frames get header location..
i have two frames, one top, one bottom. how do i do a form on the bottom frame that gives me the ur
Trouble verifying database password
Thankyou to everyone who responded to my last post (I can't find the posting, it has been buried). <
Somebody hacked into my site and changed coding >>> URGENT HELP NEEDED <<<
I am not that much into programming , but somebody is hacking to my site and injecting some kind of
ME54/ME54N Conditional check for Release of PR
Hi Gurus,
My requirement is to put a check on the release of the PR with respect to the c
IS this code correct
The reason i ask is everything underneath it appears to be alink as well, tis blimmin annoying
IMAGE - SERVER SIDE scripting help...
How to receive pixel data of an image and buid a bitmap file on the server using the HTTP POST metho
error help - Dynamic Image
I've been working on making my site less cluttered in the directories and more secure lately. In an