Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
what is wrong with this
Code: [Select]<?php
if ($_SERVER['HTTP_REFERER'])
{
Mysql error message
help me find out what this error message means:
"Duplicate entry '0' for key 'PRIMARY'&q
user administration
Dear @all,
what I have to do to set the user defaults for new users. At the moment I woul
Confusing Functions
So, I've been reading up on Functions and I like them! However, I need some help using variables in
Using Curl_multi for processing multiple URLs
Hi,
I am at a loss as to how to implement this. I would like to be able to automatically assi
why is it over writing
Code: $filepaths[] = $_FILES['new_image'];
foreach ($filepaths as $filepath)
{
$imagename =
Delete all from a table
I can not get the following code to work. If I run the sql statement in the db it will delete all t
Need to write a cookie with a url var
Not sure if its possible, but I need to write a cookie with a url.
So this would write 2232 a
Strange
I recently noticed some odd HTML appear in some of the websites I host. Not all of them are run on a
echo $rows help
Hi all,
Hopefully something simple that I don't know!
I have this:
Code: [Selec
