$get problem

Posted on 16th Feb 2014 07:03 pm by admin

Hi Guys ...

can you please tell me what i am doing wrong here
Code: <?php

$ShowBookmark = "False";
include 'Include/Header.php';

if (Get_QString('Post') == "True") {
GetGuide();
} else {
Show_Form();

}


function Show_Form() {
$thedate = date('l dS F Y');
echo '<div class="hd2"><font color=#666666><strong><center>Tv Guide</center></strong></font></div>';
echo '
<center><font face="Verdana" size="2" color="blue"><u>' .$thedate. '</center></u></font>';
echo '<font face="Verdana" color="red" size="2"><a href="Tvguide.php?channel=sabc1">Sabc 1</font></a>';
echo '<font face="Verdana" color="red" size="2"><a href="Tvguide.php?channel=sabc2">Sabc 2</font></a>';
echo '<font face="Verdana" color="red" size="2"><a href="Tvguide.php?channel=sabc3">Sabc 3</font></a>';
echo '<font face="Verdana" color="red" size="2"><a href="Tvguide.php?channel=Mnet">Mnet</font></a>';
echo '<font face="Verdana" color="red" size="2"><a href="Tvguide.php?channel=ETV">Etv</font></a>';

}


function GetGuide() {
if($_GET['channel'] == "sabc1"){
$getMyDataFrom = $Table[1];
}
if($_GET['channel'] == "sabc2"){
$getMyDataFrom = $Table[2];
}
if($_GET['channel'] == "sab3"){
$getMyDataFrom = $Table[3];
}

if($_GET['channel'] == "Mnet"){
$getMyDataFrom = $Table[4];
}
if($_GET['channel'] == "ETV"){
$getMyDataFrom = $Table[5];
}

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