help with variable


Posted on 16th Feb 2014 07:03 pm by admin

I've got a problem, i want to echo some images depending on the $id, however for me to get that id i have to extract it from a query. So i've done that, but i want to extract all id's (not just 1), so i can echo images for all them ids (not just echo the images based on 1 id), so I did a while() loop, however doesnt seem to work

My code:

Did you know?Explore Trending and Topic pages for more stories like this.
Code: <?php
include "connect.php";
$user = "Peter";
$sql = mysql_query("select * from game_main where user = '$user'");

while($row = mysql_fetch_array($sql)){
$id = $row['id'];
}
//do i have to do foreach $id as something??

$views = mysql_num_rows(mysql_query("SELECT userip FROM game_views WHERE sub_id = '$id'"));
$sql3 = mysql_query("select monthstamp from game_monthlyfeatured where first = '$id'");
$num3 = mysql_num_rows($sql3);
$sql4 = mysql_query("select weekstamp from game_weeklyfeatured where first = '$id'");
$num4 = mysql_num_rows($sql4);
$sql5 = mysql_query("select daystamp from game_dailyfeatured where first = '$id'");
$num5 = mysql_num_rows($sql5);
$sql6 = mysql_query("select date from site_featured where id = '$id'");
$num6 = mysql_num_rows($sql6);
if($num3 == 1) {
?>
<img src="../images2/game/game_awards_1monthly.gif" width="20" height="20" />
<?php
}
if($num4 == 1) {
?>
<img src="../images2/game/game_awards_topweekly.gif" width="20" height="20" />
<?php
}
if($num5 == 1) {
?>
<img src="../images2/game/game_awards_topdaily.gif" width="20" height="20" />
<?php
}
if ($views > 1000) {
?>
<img src="../images2/game/game_awards_1000views.gif" width="20" height="20" />
<?php
}
if ($views > 25000) {
?>
<img src="../images2/game/game_awards_25000views.gif" width="20" height="20" />
<?php
}
if ($num6 > 0) {
?>
<img src="../images2/game/game_awards_modpick.png" width="16" height="16" />
<?php
}

?>
Hope someone can help, thanks
No comments posted yet

Your Answer:

Login to answer
140 Like 26 Dislike
Previous forums Next forums
Other forums

PHP SUBMIT
Code: <input name="doLogin" type="image" src="images/loginsubmit.jpg

php/mysql auto logout after 2 hour and reset password
Hi all,

This I hope will make sense. I've the following code which when a user logins in, cr

Target costs on Process orders not calculating
Hi All,

We have released standard costs for all the materials. We have also done Goods r

Post, not working, please help
The error is:
Method Not Allowed
The requested method POST is not allowed for the URL /student

double and single quotes in text fields acting up... help please
Single quotes, when entered into a text field, create an sql error upon Submit. It seems to create t

mysql UPDATE request not working and driving me crazy!!!
Hi,

I have been stuck on this for ages.

Quite simply I am trying to update my database

Customizing message/behavior
Hi,I'm using the ASP.NET membership/authorization controls in my application. Some parts of my appli

Populate drop down list from table??
Lets say for arguments sake that i have a table which contains the numbers 1 to 10.
How can i get

Problem in back link
I have page where i have given javascript back link but when i click on it browser give a message

problems with search form numerical "between" sending by php
I am trying to display the results of a search, on a sql database, on a web page. I set up html &quo

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash