Giving the below syntax error

Posted on 16th Feb 2014 07:03 pm by admin

Dear Experts,

I have used 2 buttons in gui status as display and cjhange.When the user will click display button the screen will dynamically change to non-editable mode.So I have written the following code.

loop at screen.
if screen-group1 = 'MOD'.
if flag = 'X'.
screen-active = 1.
else.
screen-active = 0.
endif.
modify screen.
endloop.
But it is throwing the below syntax error.

The type of "SCREEN" must be in the type or types of "SCREEN" compatible SEIN.

Kindly give some advice

Your Answer:

Login to answer

Other forums

multiple recipients + dbuser mail recall
Hello,

I am building a php login script.

When the user registers the script will send

Error: SQL Syntax; Line 1
Code:

<?php require "global_settings.php"; ?>
<title&g

Displaying Site Logo/Icon on a Title tag
really need some help out here. I want to insert a Logo/Icon just like the one close to the "PH

trim function issues
Hi guys, total noob here...

So I've been tinkering around with a html and am using php to em

Consuming MII WebService in Java WebDynpro
Hello,

We are facing a strange situation...

We define a transaction in MII to

$_FILES array
Ok,

I just started experimenting with PHP today. My goal right now is to have people be able

Displaying image pathname instead of image
Hello

Im trying to upload and then display images from a mysql database - Its only basic and

Sending an SMS Message with ASP.NET
Often times it may be a requirement for your web application to send an SMS message. Such examples w

Undefined index on my form
ok im getting Undefined index on this line.. print_r($_REQUEST['form']);

below is the full sc

Form validation with functions
Hi there

I am trying to make a very simple form validation function. I currently have the fol