Multiple submit forms inside a mysql array page


Posted on 16th Feb 2014 07:03 pm by admin

Hi all,

Im having trouble to get the beneath script to work the thing i can't seem to get workin is the following.

The page requests the data from a mysql table using mysql array so there are mutliple row's every row has 3 data
colloms 1 id (auto increment) 2 Module name 3 status. after every row the is a submit button so you can submit data from that row (basilcy a on and off button) when i have more than 1 row it doesnt work.
With 1 row it works but have to press the submitt buton twice.

Any help will be appreciated

Regards Djunity


<div class="content">

<br />
<a href="?page=view">Module overzicht</a> <br />
<br / >
<p><a href="?page=add" class="button"><span class="ui-icon ui-icon-plusthick">&nbsp;</span>Module toevoegen </a></p>

<table id="myTable" class="tablesorter" style="width: 100%;" border="0" cellpadding="0" cellspacing="1" > <thead>
<tr>
<td height="25px" width="120"><b>&nbsp;Module naam:</b></td>
<td height="25px" width="60"><b>&nbsp;Status:</b></td>
<td height="25px"width="70"><b>&nbsp;Actie:</b></td>


</tr>
</thead>
<?
// get results from database
$result = mysql_query("SELECT * FROM Wefact_Modules ORDER BY id")
or die(mysql_error());
while($row = mysql_fetch_array( $result )) {


$form = $row['module'];
$id = $row['id'];



?>
<tbody>


<form method="post" name="form" action="?page=view">
<input type="hidden" name="id" value="<?php echo $id; ?>"/>
<input type="hidden" name="action2" value="action">
<tr class="hover">
<td height="35px"><? echo $row['module']; ?></td>
<td height="35px"><? if ($row['status'] == 1) {
echo "<font color='#00FF00'>Online</font>";
}else if ($row['status'] == 0){
echo "<font color='#FF0000'>Offline</font>"; } ?></td>
<td height="35px">
<? if ($row['status'] == 1) { ?>
<input type="hidden" name="status" value="0" /><a href="javascript: document.form.submit();" class="button"><span class="ui-icon ui-icon-minusthick">&nbsp;</span>Offline</a> <?
}else if ($row['status'] == 0){ ?>
<input type="hidden" name="status" value="1" /><a href="javascript: document.form.submit();" class="button"><span class="ui-icon ui-icon-plusthick">&nbsp;</span>Online</a> <? } ?>&nbsp;</td>
</form>

</tbody>
<? } ?>

<?
$status = $_POST['status'];

if($_REQUEST['action2'] == 'action') {

$sql = "UPDATE Wefact_Modules SET status='$status' WHERE id='$id'";
$result = mysql_query($sql);

} ?>

</table>


</td>
</tr>
</table>
</div>
</body>
</html>

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