retrieving images from mysql database using php

Posted on 16th Feb 2014 07:03 pm by admin

So I've been trying to figure out how to store images in a mysql database, and as far as i can tell the images are stored but getting them out seems to be the problem.

when i try to go to the page on my webhost it says that

"Can not select the database: Access denied for user 'testimg'@'localhost' to database 'testImages'"

and when i goto show.php?id=1 on my local mamp install it gives me all kinds of weird symbols

ÿÀ�
â„¢
Ì
�

ÿÄ�È���

�����������
�







����������
�

�!1AQaq"2‘¡±BR#Ábr‚’Ñ¢Â3CS$á²Òsƒ“%ðñc£Ã4â³T56Dt”E&Ód¤´ÄUu•7

�

��
!1AQaqð‘¡"2±ÁÑáñBRÂbr‚¢â#3ÿÚ�
��?�Ü/é -è

i've checked everything in the code a million times and searched google and this forum for anything that can help me but i haven't been able to find something that has helped me understand what exactly is going on and why


heres the upload form

<form enctype="multipart/form-data" action="insert.php" method="post" name="changer">
<input name="MAX_FILE_SIZE" value="1500000" type="hidden">
<input name="image" accept="image/jpeg" type="file">
<input value="Submit" type="submit">
</form>


this is my insert.php that processes the image after its submitted


<?php

include './database.php';


$link = mysql_connect($host, $username, $password);
if (!$link) {
die('Could not connect: ' . mysql_error());
}

mysql_select_db ($database);


if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) {

$tmpName = $_FILES['image']['tmp_name'];

$fp = fopen($tmpName, 'r');
$data = fread($fp, filesize($tmpName));

$data = addslashes($data);
fclose($fp);

$query = "INSERT INTO tbl_images ";
$query .= "(image) VALUES ('$data')";
$results = mysql_query($query, $link);

print "Thank you, your file has been uploaded.";

}else{
print "No image selected/uploaded";
}

mysql_close($link);
?>

and heres the show.php that displays the image using the id

<?php

include './database.php';

@mysql_connect($host, $username, $password) or die("Can not connect to database: ".mysql_error());

@mysql_select_db($database) or die("Can not select the database: ".mysql_error());

$id = $_GET['id'];

if(!isset($id) || empty($id)){
die("Please select your image!");
}else{

$query = mysql_query("SELECT image FROM tbl_images WHERE id='".$id."'");
$row = mysql_fetch_assoc($query);
$content = $row['image'];

header("Content-type: image/jpg");
echo $content;

}

?>

Your Answer:

Login to answer

Other forums

WS-Security PL/SQL Forms
Oracle Database 10g Enterprise Edition Release 10.2.0.2.0 - Prod
PL/SQL Release 10.2.0.2.0 - P

Unidentified index error in a simple form
I have been trying to make an HTML form that is handled by a PHP script. So far my attempts to get i

Need help with some php code :)
Hey! I'm quite new to this whole thing, so please don't fire me with shait on this one =D

I'm

Must be a string? Huh, what? HELP?
with the following script, I get
Fatal error: Property name must be a string in /home/content/e/

Form File Upload
I've read through tons of resources and tutorials and as far as I can tell, my code is accurate, but

PHP and Javascript
Hello Everyone,

I have a page that needs a javascript code to be written between PHP code but

Creating a db with a query
Hello everyone.
I'm having troubles creating a db with a query.
I'm reading a book called PHP

Login page problems
I developed a website a few months ago and I am now having an issue with logging into it. The place

Remove directories not empty
hi,
i have an array that contains some names (1,4,6,56...). Every integer is a name of a folder.<

Problem with HTTP Caching...?
Hi there, im trying to implement caching. But it doesn't always work.
I post it here because ther