PHP using IF to display error
i have a MySQL query and i want to display 1 thing only if the number of affected rows is >=1
help me fix these syntax errors...
I keep getting multiple syntax errors on this script like this one:
Parse error: syntax error
Form a inline view based on the results of the previous query?
Hi Experts,
Can we form a inline view on the results of a previous query (another inline view)?
CURL XML Request [From C to PHP]
Hi,
I need some help converting this into something that will work with PHP.
Code: #
shift numbers with paging
Hi
How would i be able to display 10 numbers 1 2 3 4 5 6 7 8 9 10
and when I click next
form variables from database help.
Hi all,
I would like to have a form that gives you options based on the results of an mysql q
isset undefined variable
Hi all,
Hope someone can point out the obvious. I've a log in script, if you dont enter a use
JSON SORT WITH PHP
I have two products that I want to sort by say "Id:17, value: xxx" using php
The page w
How to add an image/C++ OpenGL?
Hi,
I have been trying to look online for this and, so far, I haven't found anything usef
I need help on this PHP code
Hi everybody, I made some kind of mistake while editing the code below. As you see, at the 3 row my
