switch not getting value


Posted on 16th Feb 2014 07:03 pm by admin

what am i doing wrong?
i want to populate the country list according to the category
i want to switch in case CategoryID=1 and CatID2=2 in the country_list table

Did you know?Explore Trending and Topic pages for more stories like this.
then call on "alpha" to populate the dropdown list via ajax
the form:
Code: <!--
The following file was created by Iwo Kadziela at TECHROAM: http://www.techroam.com
This file uses MySql database and AJAX to create autopopulating dynamic select boxes.

<html>
<head>
<script src="request.js"></script>
<script type="text/javascript">

function getfirst(dd1)
{
clearSelect = document.getElementById('thirdbox');
clearSelect.options.length = 1;
//above code clears the third select box when re-clicking the first select box

var idx = dd1.selectedIndex;
var first = dd1[idx].value;
var par = document.forms["theform"];
var parelmts = par.elements;
var prezsel = parelmts["secondbox"];
if (first != "Select Something One")
{
Http.get({
url: "./alpha.php?alpha=" + first + "%",
callback: fillPrez,
cache: Http.Cache.Get
}, [prezsel]);
}
}

function getsecond(dd1)
{
var idx = dd1.selectedIndex;
var second = dd1[idx].text;
var par = document.forms["theform"];
var parelmts = par.elements;
var prezsel = parelmts["thirdbox"];
if (second != "Select Something Two")
{
Http.get({
url: "./beta.php?state=" + second,
callback: fillPrez,
cache: Http.Cache.Get
}, [prezsel]);
}
}

function fillPrez(xmlreply, prezelmt)
{
if (xmlreply.status == Http.Status.OK)
{
var prezresponse = xmlreply.responseText;
var prezar = prezresponse.split("|");
prezelmt.length = 1;
prezelmt.length = prezar.length;
for (o=1; o < prezar.length; o++)
{
prezelmt[o].text = prezar[o];
prezelmt[o].value = prezar[o];
}
}
else
{
alert("Cannot handle the AJAX call.");
}
}

function getthird(dd1,dd2) {
var idx = dd1.selectedIndex;
var third = dd1[idx].text;
if (third != "Select The Final")
{
Http.get({
url: "./final.php?state=" + dd2 + "&city=" + third,
callback: getit,
cache: Http.Cache.Get
});
}
}

function getit(xmlreply){
if (xmlreply.status == Http.Status.OK)
{
document.getElementById("final").innerHTML= xmlreply.responseText;
}
else
{
alert("Cannot handle the AJAX call.");
}
}
</script>
<style>
body {
width:800px;
margin: 0px auto;
text-align:center;
}
p {display:inline;margin:20px;}
div {clear:both;width:800px;border:1px solid #999;padding:20px;margin:20px 0px 20px 0px;}
</style>
</head>

<body>

<form name="theform">
<p>
<select name="firstbox" size="13" style="position: relative; width: 215px;" onChange="getfirst(this);">
<option value="">Select Something One</option>
<?php
do {
?>
<option value="<?php echo $row_RsCategories['CategoryID']?>"><?php echo $row_RsCategories['CategoryName']?></option>
<?php
} while ($row_RsCategories = mysql_fetch_assoc($RsCategories));
$rows = mysql_num_rows($RsCategories);
if($rows > 0) {
mysql_data_seek($RsCategories, 0);
$row_RsCategories = mysql_fetch_assoc($RsCategories);
}
?>
</select>
</p>
<p>
<select name="secondbox" size="13" style="position: relative; width: 215px;" onChange="getsecond(this);">
<option>Select Something Two</option>
</select>
</p>
<p>
<select id="thirdbox" name="thirdbox" size="13" style="position: relative; width: 215px;" onChange="getthird(this, document.theform.secondbox.options[document.theform.secondbox.selectedIndex].value);">
<option>Select The Final</option>
</select>
</p>
</form>
<center>THE FINAL CONTENT PULLED FROM DATABASE</center>
<div id="final"></div>
</body>
</html>
<?php
mysql_free_result($RsCategories);
?>

alpha.php
Code: </php
$dbconnection = mysql_connect ("localhost", "root", "") or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db ("international", $dbconnection) or die("Couldn't open database: ".mysql_error());
$alpha=$_GET['alpha'];
switch ($alpha)
{
case 1:
$result = mysql_query("SELECT CountryName from country_list WHERE CategoryID = '".$_GET['alpha']."'");
break;
case 2:
$result = mysql_query("SELECT CountryName from country_list WHERE CatID2 = '".$_GET['alpha']."'");
break;


while ($row = mysql_fetch_array($result)) {
echo "|" . $row['CountryName'];
}

?>
No comments posted yet

Your Answer:

Login to answer
97 Like 15 Dislike
Previous forums Next forums
Other forums

simple script won't work. Please help
I'm new to php, and I am having trouble displaying a simple script in my web browser. My php code ex

Output Buffering question
Hi all,

I've been trying to wrap my head around output buffering. So far I've found tons of

Help with Hyperlink
Hi,

What I am trying to do may be simple, I just can't get it to work. Ok...

I am usin

Lack of simpleXML Documentation
What is up with this.

Look at: http://www.php.net/manual/en/function.simplexml-load-file.php<

Taxonomy? Classification? Categorisation?
Not sure if there is a way around this classification problem
I have a supplier who produces

PHP and SMS
Hi all forum members. I am new here and am unsure what category shoild I post this in.
Moderator

php web service error
hey guys,
I'm working on a project requires the use of web services. I've been trying a few tutor

include problem
I have my root folder as:
Code: $root = $_SERVER["SITE_HTMLROOT"]; // the server root<

insert PHP code into function
Hi,
I'm having problems when trying following:

I have:
Code: [Select]createBar("Do

Images outside webroot
Im hopeing someone can help me with this because i cant figure it out.I have setup an ASP.NET websit

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash