same querie, or a new one??
Posted on
16th Feb 2014 07:03 pm by
admin
Hi guys,
I'm still working on this drop down list. I've got the actual drop down list to work (call all the "pname"s from the table, and I've even found how to print the result once you press submit.... However...
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What I need for this to do is once pname has been selected and submitted, I want the information linked to the pname in other tables to also display...
SO the question is: Do i add the other information I need into the original query, or will it be easier to do another one?? And if the latter, how and where??
Thanks
Gem
Code: <?php
$conn = mysql_connect("CNX") or trigger_error("SQL", E_USER_ERROR);
$db = mysql_select_db('bssql',$conn) or trigger_error("SQL", E_USER_ERROR);
$sql="SELECT pname FROM pname ORDER BY pname";
$result=mysql_query($sql);
$options="";
while ($row=mysql_fetch_array($result)) {
$id=$row["pname"];
$thing=$row["pname"];
$options.="<OPTION VALUE="$id">".$thing.'</option>';
}
?>
<html>
<body>
<FORM action="<?php echo $_SERVER['PHP_SELF']; ?>" method="get">
<SELECT NAME=pname>
<OPTION VALUE=0>Choose
<?=$options?>
</SELECT>
<input type="submit" name="submit" value="submit">
</FORM>
<?php
if(isset($_GET['submit'])){
print stripslashes($_GET['pname']);
}
?>
Logic question
im wondering what's the best method to do the above list:
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