same querie, or a new one??


Posted on 16th Feb 2014 07:03 pm by admin

Hi guys,

I'm still working on this drop down list. I've got the actual drop down list to work (call all the "pname"s from the table, and I've even found how to print the result once you press submit.... However...

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What I need for this to do is once pname has been selected and submitted, I want the information linked to the pname in other tables to also display...

SO the question is: Do i add the other information I need into the original query, or will it be easier to do another one?? And if the latter, how and where??

Thanks

Gem

Code: <?php

$conn = mysql_connect("CNX") or trigger_error("SQL", E_USER_ERROR);
$db = mysql_select_db('bssql',$conn) or trigger_error("SQL", E_USER_ERROR);

$sql="SELECT pname FROM pname ORDER BY pname";
$result=mysql_query($sql);

$options="";

while ($row=mysql_fetch_array($result)) {

$id=$row["pname"];
$thing=$row["pname"];
$options.="<OPTION VALUE="$id">".$thing.'</option>';
}


?>


<html>
<body>

<FORM action="<?php echo $_SERVER['PHP_SELF']; ?>" method="get">
<SELECT NAME=pname>
<OPTION VALUE=0>Choose
<?=$options?>
</SELECT>
<input type="submit" name="submit" value="submit">
</FORM>

<?php

if(isset($_GET['submit'])){
print stripslashes($_GET['pname']);

}
?>
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