Uploading Filetypes and placing them in seperate folders.


Posted on 16th Feb 2014 07:03 pm by admin

Hello,

first post , and asking for help im afraid. Very new to PHP, was making good progress I thought , but im stuck with this part. I have a uploading form that works perfectly and uploads everything to "uploads/images" . What Im trying to do is upload .txt or .rtf files to "uploads/text" and .jpg and .gif's to "uploads/images . I thought this wasnt going to be too difficult but im totally stuck and have spent hours trying to solve this. If anyone could help at all and show my what I'm doing wrong, Id be very very grateful!

Did you know?Explore Trending and Topic pages for more stories like this.
This is the code as it stands. Right now, it ALWAYS goes to "uploadfail.php" and the file does not upload. If I remove all the code relating to filetype then both the text and image files succesully upload and I go to "uploadsucess.php"


Code: <?
require('connection.php');

//my_sql_real..... makes it safe against mysql injection

$title = mysql_real_escape_string($_POST['title']);
$date = mysql_real_escape_string($_POST['date']);
$author = mysql_real_escape_string($_POST['author']);
$description = mysql_real_escape_string($_POST['description']);
$type = mysql_real_escape_string($_POST['type']);

$imgName = $_FILES['pic']['name'];
$imgTmp = $_FILES['pic']['tmp_name'];
$imgSize = $_FILES['pic']['size'];
$imgType = $_FILES['pic']['type'];

$maxFileSize = 200000;

if ($imgType == "image/jpeg" || $imgType == "image/gif" || $imgType == "application/rtf" || $imgType == "application/x-rtf" || $imgType == "text/richtext" || $imgType == "text/plain" ) {
$error = "";



} else {
$error = "type";

}

if ($imgType == "image/jpeg" || $imgType == "image/gif" ) {
$filetype = "image";
}

if ($imgType == "application/rtf" || $imgType == "application/x-rtf" || $imgType == "text/richtext" || $imgType == "text/plain" ) {
$filetype = "text";
} else {
$filetype = "other";

}



if ($imgSize > $maxFileSize) {
$error = "size";
}

if ($error == "" && $imgName != "" && $filetype == "image" ) {
$filePath = "uploads/images/".$imgName;
move_uploaded_file($imgTmp, $filePath);







if ($error == "" && $imgName != "" && $filetype == "text" ) {

$filePath = "uploads/text/".$imgName;
move_uploaded_file($imgTmp, $filePath);










//another securtiy measure sprintf
$query = sprintf("INSERT INTO gallery(title,date,author,type,description,path) VALUES ('%s' , '%s' ,'%s' ,'%s' ,'%s' ,'%s' )", $title,$date,$author,$type,$description,$filePath);

if (!mysql_query($query, $connect)) {
die();
} else {

header("Location: uploadsuccess.php");
}
}
} else {
header("Location: uploadfail.php");
}
?>
No comments posted yet

Your Answer:

Login to answer
271 Like 42 Dislike
Previous forums Next forums
Other forums

Form errors in an array
I'm processing a form and putting the errors in an array. empty($errors) doesn't seem to do the tric

PHP and XML image gallery variable issue
I'm trying to display the large image on the same page as the thumbnails, to do that I'm passing a v

Save User Inputs while javascript reloading!
hi..
i have written a PHP code in which i reload the page when user selects a value in dropdown..

foreach result into a single variable
Hi,

I have this code...

Code: [Select]foreach ($_POST['Interests'] as $interest =&

user validation always displaying invalid ? please help
Hello,

I have 2 accounts and there is a field in mysql called validated it can be either &quo

Mail from PHP form not always ending up in my inbox?
Hi guys,

I'm a real newbie to PHP and have managed to put together a simple mail form that se

Query failed issue with php script but works fine in mssql manager!
hi i have the script below which copies data from one table to another but will only insert new data

this code is strange !
Hi i got this code from the web.. It checks for live and dead socks
It is working perfectly on my

Warning: Cannot modify header information - headers already sent by (output sta
Warning: Cannot modify header information - headers already sent by (output started at /home/praylif

reorder sql query
ok so i have this very simple code:
Code: $query = "SELECT search_keywords, COUNT(search_key

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash