help with variable


Posted on 16th Feb 2014 07:03 pm by admin

I've got a problem, i want to echo some images depending on the $id, however for me to get that id i have to extract it from a query. So i've done that, but i want to extract all id's (not just 1), so i can echo images for all them ids (not just echo the images based on 1 id), so I did a while() loop, however doesnt seem to work

My code:

Code: <?php
include "connect.php";
$user = "Peter";
$sql = mysql_query("select * from game_main where user = '$user'");

while($row = mysql_fetch_array($sql)){
$id = $row['id'];
}
//do i have to do foreach $id as something??

$views = mysql_num_rows(mysql_query("SELECT userip FROM game_views WHERE sub_id = '$id'"));
$sql3 = mysql_query("select monthstamp from game_monthlyfeatured where first = '$id'");
$num3 = mysql_num_rows($sql3);
$sql4 = mysql_query("select weekstamp from game_weeklyfeatured where first = '$id'");
$num4 = mysql_num_rows($sql4);
$sql5 = mysql_query("select daystamp from game_dailyfeatured where first = '$id'");
$num5 = mysql_num_rows($sql5);
$sql6 = mysql_query("select date from site_featured where id = '$id'");
$num6 = mysql_num_rows($sql6);
if($num3 == 1) {
?>
<img src="../images2/game/game_awards_1monthly.gif" width="20" height="20" />
<?php
}
if($num4 == 1) {
?>
<img src="../images2/game/game_awards_topweekly.gif" width="20" height="20" />
<?php
}
if($num5 == 1) {
?>
<img src="../images2/game/game_awards_topdaily.gif" width="20" height="20" />
<?php
}
if ($views > 1000) {
?>
<img src="../images2/game/game_awards_1000views.gif" width="20" height="20" />
<?php
}
if ($views > 25000) {
?>
<img src="../images2/game/game_awards_25000views.gif" width="20" height="20" />
<?php
}
if ($num6 > 0) {
?>
<img src="../images2/game/game_awards_modpick.png" width="16" height="16" />
<?php
}

?>
Hope someone can help, thanks

No comments posted yet

Your Answer:

Login to answer
140 Like 26 Dislike
Previous forums Next forums
Other forums

quick question
Hi ..

i have a question
how do i set a var so it displays via an echo
Code: $logo = '&a

Windows 7
Windows 7 default user account control worries experts. Corporate IT departments should be pleased w

why aint this working?
i have this code:

Code: $num = 250;
$count = ($num - $rcount);

echo $rc

Query output more than expected
$query=mysql_query("SELECT * FROM players, communities, divisions WHERE dob BETWEEN '{$start_da

count only commas outside parenteses
I have a sql table containing
id - query - query name
the first page contains a drop down men

A href problem under php
Hello...

I tried to explain the issue in an earlier post.. but was not clear enough....

Career Change into SAP
Hai
I am sajesh ,did my diploma in Mechatronics i have a 4 years of experience in

A WBS element with the name XXX already exists in version FREI_VERSION
Hi.
When I am trying to insert WBS element in a project, error occurs:

"A WBS eleme

fopen() security
As i understood the usage of fopen() for it to function correctly the Dir you write to has to be rw

Email Processor
I have a few questions so this post will be a larger one! Sorry, but I'm a bit of a PHP newbie so be

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash