help with variable


Posted on 16th Feb 2014 07:03 pm by admin

I've got a problem, i want to echo some images depending on the $id, however for me to get that id i have to extract it from a query. So i've done that, but i want to extract all id's (not just 1), so i can echo images for all them ids (not just echo the images based on 1 id), so I did a while() loop, however doesnt seem to work

My code:

Code: <?php
include "connect.php";
$user = "Peter";
$sql = mysql_query("select * from game_main where user = '$user'");

while($row = mysql_fetch_array($sql)){
$id = $row['id'];
}
//do i have to do foreach $id as something??

$views = mysql_num_rows(mysql_query("SELECT userip FROM game_views WHERE sub_id = '$id'"));
$sql3 = mysql_query("select monthstamp from game_monthlyfeatured where first = '$id'");
$num3 = mysql_num_rows($sql3);
$sql4 = mysql_query("select weekstamp from game_weeklyfeatured where first = '$id'");
$num4 = mysql_num_rows($sql4);
$sql5 = mysql_query("select daystamp from game_dailyfeatured where first = '$id'");
$num5 = mysql_num_rows($sql5);
$sql6 = mysql_query("select date from site_featured where id = '$id'");
$num6 = mysql_num_rows($sql6);
if($num3 == 1) {
?>
<img src="../images2/game/game_awards_1monthly.gif" width="20" height="20" />
<?php
}
if($num4 == 1) {
?>
<img src="../images2/game/game_awards_topweekly.gif" width="20" height="20" />
<?php
}
if($num5 == 1) {
?>
<img src="../images2/game/game_awards_topdaily.gif" width="20" height="20" />
<?php
}
if ($views > 1000) {
?>
<img src="../images2/game/game_awards_1000views.gif" width="20" height="20" />
<?php
}
if ($views > 25000) {
?>
<img src="../images2/game/game_awards_25000views.gif" width="20" height="20" />
<?php
}
if ($num6 > 0) {
?>
<img src="../images2/game/game_awards_modpick.png" width="16" height="16" />
<?php
}

?>
Hope someone can help, thanks

No comments posted yet

Your Answer:

Login to answer
140 Like 26 Dislike
Previous forums Next forums
Other forums

New Login Script
Hi all, i attempted to create a whole new login script witch isnt working for some reason i dont kno

Error in SQL Syntax HELP!!!
I have this page:

Code: <?php

session_start();

//connect to server and s

LSB (PHP 5.3) problem with static value!
hello,

i'm having a problem. static::$text variable gets lost at some point. can someone plea

Option box to change variable
Hello, i need help by making a script!

I need to write a file with option box, so a dropdown

Preg_match question
I want to use preg_match to make sure a string is always 6 characters long and only contains 0-9 and

Multi Level Array Problem
hi all,

For example I have array like below:

$temp = array(array('north america', 'us'

How to use Substr
I want to check for the word CATEGORY: inside a string which can be CATEGORY: ITEM
and remove the

Why doesn't this work? (SSH2)
This is my script:

Code: <?php
$connection = ssh2_connect('213.251.167.109', 22);

my two tables
table1 : col1 = topicid , col2 = topic

table2 : col1 = sentid, col2 = sentence

Cod

Formatting echo from database
So I have a database that stores First and last names, then echos them back to a website, as of now

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash