help with variable


Posted on 16th Feb 2014 07:03 pm by admin

I've got a problem, i want to echo some images depending on the $id, however for me to get that id i have to extract it from a query. So i've done that, but i want to extract all id's (not just 1), so i can echo images for all them ids (not just echo the images based on 1 id), so I did a while() loop, however doesnt seem to work

My code:

Code: <?php
include "connect.php";
$user = "Peter";
$sql = mysql_query("select * from game_main where user = '$user'");

while($row = mysql_fetch_array($sql)){
$id = $row['id'];
}
//do i have to do foreach $id as something??

$views = mysql_num_rows(mysql_query("SELECT userip FROM game_views WHERE sub_id = '$id'"));
$sql3 = mysql_query("select monthstamp from game_monthlyfeatured where first = '$id'");
$num3 = mysql_num_rows($sql3);
$sql4 = mysql_query("select weekstamp from game_weeklyfeatured where first = '$id'");
$num4 = mysql_num_rows($sql4);
$sql5 = mysql_query("select daystamp from game_dailyfeatured where first = '$id'");
$num5 = mysql_num_rows($sql5);
$sql6 = mysql_query("select date from site_featured where id = '$id'");
$num6 = mysql_num_rows($sql6);
if($num3 == 1) {
?>
<img src="../images2/game/game_awards_1monthly.gif" width="20" height="20" />
<?php
}
if($num4 == 1) {
?>
<img src="../images2/game/game_awards_topweekly.gif" width="20" height="20" />
<?php
}
if($num5 == 1) {
?>
<img src="../images2/game/game_awards_topdaily.gif" width="20" height="20" />
<?php
}
if ($views > 1000) {
?>
<img src="../images2/game/game_awards_1000views.gif" width="20" height="20" />
<?php
}
if ($views > 25000) {
?>
<img src="../images2/game/game_awards_25000views.gif" width="20" height="20" />
<?php
}
if ($num6 > 0) {
?>
<img src="../images2/game/game_awards_modpick.png" width="16" height="16" />
<?php
}

?>
Hope someone can help, thanks

No comments posted yet

Your Answer:

Login to answer
140 Like 26 Dislike
Previous forums Next forums
Other forums

Need help: how to catch acess of undefined class properties
Hello. I am learning OO with PHP and have hit a problem.
Some code runs as perfectly valid code,

Request-URI Too Large
I have created a simple submit form for a mysql database that puts a piece of code into database.<

parse error
Parse error: syntax error, unexpected '[', expecting ')' in /Users/admin/Sites/phptest/array.php on

Take info from one coloum and move to another
Hi all,

I have this:
Code: [Select]$array = "SELECT stock_id FROM stocks WHERE stock_

Insert to MySQL inside foreach
Hey.
I am parsing some html, and putting inside an html db.
I need to create a randomized inte

Object Interfaces
EDIT: Never mind, I just updated to php 5.

Hey all,

I'm currently experimenting with p

search function
HI guys,

if anyone could point us in the right direction of how to do this, or provide some t

str_replace help
I am thinking str_replace is my only option to filter outputs from my database to convert them to sa

insert mysql embeded videos as blobs?
Using TinyMCE my client will be able to embed images and flash videos into large columns of text whi

checkbox update
I am having a brain fart right now and i cant remember how to do this. if anyone could help that wou

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash