pageination not working right... coping images over 4 pages

Posted on 16th Feb 2014 07:03 pm by admin

Code: <?php //This code will obtain the required page number from the $_GET array. Note that if it is not present it will default to 1.
if (isset($_GET['pageno'])) {
$pageno = $_GET['pageno'];
} else {
$pageno = 1;
} // if
//This code will count how many rows will satisfy the current query.

$query ="SELECT * FROM `photos` WHERE `thumb_id` = '3'";
$result = mysql_query($query) or trigger_error("SQL", E_USER_ERROR);
$query_data = mysql_fetch_row($result);
$numrows = $query_data[0];

//This code uses the values in $rows_per_page and $numrows in order to identify the number of the last page.

$rows_per_page = 3;
$lastpage = ceil($numrows/$rows_per_page);

//This code checks that the value of $pageno is an integer between 1 and $lastpage.

$pageno = (int)$pageno;
if ($pageno > $lastpage) {
$pageno = $lastpage;
} // if
if ($pageno < 1) {
$pageno = 1;
} // if

//This code will construct the LIMIT clause for the sql SELECT statement.

$limit = 'LIMIT ' .($pageno - 1) * $rows_per_page .',' .$rows_per_page;

//Now we can issue the database qery and process the result.

$sql="SELECT * FROM `photos` WHERE `thumb_id` = '3'";
$res = mysql_query($sql) or die(mysql_error());


echo "<table>";
$i = 0;
while($row = mysql_fetch_assoc($res)){
$i++;
if ($i % 3 == 0)
echo '<tr>';

echo "<td> <img src="http://www.runningprofiles.com/members/include/myimages/thumbs/" . $row['picurl'] . "" /></a><br /> </td>";

if ($i % 3 == 0)
echo '</tr>';

if( $i == 9 ) break;
}
echo "</table>";
//... process contents of $result ...
//Finally we must construct the hyperlinks which will allow the user to select other pages. We will start with the links for any previous pages.

if ($pageno == 1) {
echo " FIRST PREV ";
} else {
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=1'>FIRST</a> ";
$prevpage = $pageno-1;
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$prevpage'>PREV</a> ";
} // if

//Next we inform the user of his current position in the sequence of available pages.

echo " ( Page $pageno of $lastpage ) ";

//This code will provide the links for any following pages.

if ($pageno == $lastpage) {
echo " NEXT LAST ";
} else {
$nextpage = $pageno+1;
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$nextpage'>NEXT</a> ";
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$lastpage'>LAST</a> ";
} // if



?>
Im alittle confused by my pageinated results... i only have 2 images... and for some reason its repeated these images over 11 pages... how comes?

Your Answer:

Login to answer

Other forums

please hep to get values from a table row
can anyone tel me how I can select and get data from one row by pressing an Edit button in that row

How can I uploading Transactional Data from Legacy to New SAP system
Hell Gurus,

I am overwhelmed with questions on how to migrate huge volume of Sales Orders

PHP Search Issue
Hi, I am using the following code to search and return flights from a database. The user searches by

Php navigation
I have four buttons on a php page.
If i click a button it will redirect to different php pages.

tag inside php...
hi


Code: <?php
echo "<td width="$columnWidth%" align=&

Any meaningful project for a new C++ programmer?
I want to do some meaningful program, so I can help myself to learn

Assume I know the fol

need help with php get
i have a option box that gets filled with dates, but how do i get once the option value has been cli

Captcha problem users just refresh and it will let them auto submit again
Users will just re submit and not have to enter the new captcha.. ? Lol but if i refresh the page, t

Spaghetti Code
So.

I've pretty much reached the point where I have so many isset s on one page that I can't

Error in SQL Syntax HELP!!!
I have this page:

Code: <?php

session_start();

//connect to server and s