pageination not working right... coping images over 4 pages

Posted on 16th Feb 2014 07:03 pm by admin

Code: <?php //This code will obtain the required page number from the $_GET array. Note that if it is not present it will default to 1.
if (isset($_GET['pageno'])) {
$pageno = $_GET['pageno'];
} else {
$pageno = 1;
} // if
//This code will count how many rows will satisfy the current query.

$query ="SELECT * FROM `photos` WHERE `thumb_id` = '3'";
$result = mysql_query($query) or trigger_error("SQL", E_USER_ERROR);
$query_data = mysql_fetch_row($result);
$numrows = $query_data[0];

//This code uses the values in $rows_per_page and $numrows in order to identify the number of the last page.

$rows_per_page = 3;
$lastpage = ceil($numrows/$rows_per_page);

//This code checks that the value of $pageno is an integer between 1 and $lastpage.

$pageno = (int)$pageno;
if ($pageno > $lastpage) {
$pageno = $lastpage;
} // if
if ($pageno < 1) {
$pageno = 1;
} // if

//This code will construct the LIMIT clause for the sql SELECT statement.

$limit = 'LIMIT ' .($pageno - 1) * $rows_per_page .',' .$rows_per_page;

//Now we can issue the database qery and process the result.

$sql="SELECT * FROM `photos` WHERE `thumb_id` = '3'";
$res = mysql_query($sql) or die(mysql_error());


echo "<table>";
$i = 0;
while($row = mysql_fetch_assoc($res)){
$i++;
if ($i % 3 == 0)
echo '<tr>';

echo "<td> <img src="http://www.runningprofiles.com/members/include/myimages/thumbs/" . $row['picurl'] . "" /></a><br /> </td>";

if ($i % 3 == 0)
echo '</tr>';

if( $i == 9 ) break;
}
echo "</table>";
//... process contents of $result ...
//Finally we must construct the hyperlinks which will allow the user to select other pages. We will start with the links for any previous pages.

if ($pageno == 1) {
echo " FIRST PREV ";
} else {
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=1'>FIRST</a> ";
$prevpage = $pageno-1;
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$prevpage'>PREV</a> ";
} // if

//Next we inform the user of his current position in the sequence of available pages.

echo " ( Page $pageno of $lastpage ) ";

//This code will provide the links for any following pages.

if ($pageno == $lastpage) {
echo " NEXT LAST ";
} else {
$nextpage = $pageno+1;
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$nextpage'>NEXT</a> ";
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$lastpage'>LAST</a> ";
} // if



?>
Im alittle confused by my pageinated results... i only have 2 images... and for some reason its repeated these images over 11 pages... how comes?

Your Answer:

Login to answer

Other forums

Will this protect from mysql injection?
I do not want anything like DROP TABLE to work or any type of coding..

Heres my code.. is it

IP question
ive got 2 ip addresses both global from same user how would i detect if they are local to each other

When file included, REMOTE_ADDR is server's?
I have an index file that handles my site, basically index.php?page=ip will activate "require('

How to change Time Zone
HI
I want to change the time zone of the server to another country.How can do that?

Thanks

Required to login help
I'm trying to set up my site so users have to be logged into the forum to access the site.I've been

How can I uploading Transactional Data from Legacy to New SAP system
Hell Gurus,

I am overwhelmed with questions on how to migrate huge volume of Sales Orders

exclude characters from counting?
Hello, I wanted to ask if you have a string like:
Code: $my_s='ASRGREGTGTR----REGREGRE+++RRRRRR..

session variable problem
Session variable is not working in Fire fox i am getting null value but it is working fine in IE.

Error Messaging not working
I changed the way my form tells the user of an error. But I can't seem to get it to work properly.

Record count of entire database
Does anyone know if there is a way to obtain the number of records in each table of the database usi