order by date not ID number help php

Posted on 16th Feb 2014 07:03 pm by admin

I am trying to orginize the following code to order by date not id number.
any help would be great

Code: [Select]<?php

// Status
// 1. inshop
// 2 in progress
// 3 pending
// 4 to be picked up
// 5 Done. Out of office.

$db = mysql_connect("x","x","x") or die("Couldn't connect");
mysql_select_db("x",$db) or die("Couldn't select database");
$query="SELECT * FROM `calls` WHERE `status` = '1' AND `priority` != 1";
$result=mysql_query($query);
$num=mysql_numrows($result);

print '<table width="100%" border="0">';
print "<tr><td><b>In Shop: $num
</b></td></tr>";
$i=0;
while ($n < $numa) {
$customer=mysql_result($result_customer,$n,"name");
$n++;
};
$id=mysql_result($result,$i,"id");
$date=mysql_result($result,$i,"date");
$time=mysql_result($result,$i,"time");
$customer=mysql_result($result,$i,"customer");
// $worksheetnum=mysql_result($result,$i,"worksheetnum");
// $worksheetnum =mysql_result($result2,$i,"($_POST['worksheetnum'])");
$worksheet=mysql_result($result,$i,"worksheet");
#Find customer name out of customer field
$query_customer="SELECT `name` FROM `customers` WHERE `id` = $customer";
$result_customer=mysql_query($query_customer);
$numa=mysql_numrows($result_customer);
$n=0;

while ($n < $numa) {
$customer=mysql_result($result_customer,$n,"name");
#end
//View Inshop

print '<FORM ACTION="GWS_online_lookup.php" method=post>';
print "<tr><td width=11%><input type="hidden" name="wo" value=$id><input type="submit" value="View"/>";
print "</td>";
print '<td align="left" width="29%">';
// print '<b><h3>';
print "$customer";
// print '</b></h3>';
print '</td><td width="24%">';
// print '<b><h3>';
print "$date";
// print '</b></h3>';
print '</td><td width="20%">';
// print '<b><h3>';
print "$time";
// print '</b></h3>';
print '<td width="16%">';
// print '<b><h3>';
print "WS $id";
// print '</b></h3>';
print '</td>';
print '</form>';
$n++;
};
// $i++;
// };
print "</table>";
$worksheetnum = trim(stripslashes($_POST['worksheetnum']));
$customerid = trim(stripslashes($_POST['customerid']));
$id = $_POST['wo'];
print $worksheetnum;
print "<input type="hidden" name="worksheetnum" value=$worksheetnum>";
print "<input type="hidden" name="customerid" value=$customerid>";
print "<input type="hidden" name="wo" value=$id>";

?>

Your Answer:

Login to answer

Other forums

User input in to variable
Hi all,

I'm sure this is very easy but I'm having another brain freeze!

At the end of

Material Issuing for receiving batch
Dear All experts in MM/ PP,

Material issuing from main stores to factory is currently usi

Big Problem!! Please help
Hi Guys,

Im making a website for a friend have encountered a really annoying problem. When ev

Cron Job and Output
I have php codes running under a cron job.
But everytime i output (echo) , it comes out as comple

Convert array to string and write to csv file
I am looking to write a MySQL query to a csv file.

At the minute I:

check for the orig

Server side $_SESSION
how does one keep the session completely server side. no cookies to the browser at all. i need this

Really need helps regarding Pagination with Sort
I need someone helps regarding pagination problem...i actually want to make my page limited to let s

Beginner question regarding Array's
Hi everyone, the page im working on has an array of variable at the top...

Code: $define_li

why isn't this PHP code working ???
it's suppose to find a name on the database.

<?php

$s = $_POST["lname&

How to make a input/output field with multiple lines
Hello.
I put a input/output field on the screen but I could not change height of it. I need to