php forms and database navigatio


Posted on 16th Feb 2014 07:03 pm by admin

Hello,
I'm new to php and i'd like to post the following.
I have written code to get records from a DB and i need one record at a time to be filled in a form i created. Then the next record should be displayed after the user hits the "press any ket button". It does not work

Did you know?Explore Trending and Topic pages for more stories like this.
PLEASE HELP !

code is following

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"


<?php

$labels = array( "user_name" => "User Name", "create_date" => "Creation Date", "password" => "Password",
"last_name" => "Last Name",
"first_name" => "First Name",
"street" => "Street",
"city" => "City",
"state" => "State",
"zip" => "Zip",
"email" => "Email",
"phone" => "Phone",
"fax" => "Fax");

$submit = "Press any key";
include("dbstuff.inc");
$cxn = mysqli_connect($host,$user,$passwd,$databname);
if (!cxn) {
printf("Can't connect to localhost. Errorcode: %dn", mysqli_connect_errno ());
}
else { echo "connection successful !";
}
/* or die ("could not connect to server");*/
$query = "SELECT * FROM customer ";
$result = mysqli_query ($cxn,$query) or die ("could not execute query");
/*$customer = mysqli_fetch_assoc($result);*/

?>

<html>
<head><title>Customer Record</title>
<style type='text/css'>

/*div {background-color:#b0c4de}*/
body {color:blue}
body {background-color:#b0c4de}

<!--
#form {margin: 1.5em 0 0 0;
padding: 15;
}
#field {padding-bottom: 1em;}
label {
font-weight: bold;
float: left;
width: 10%;
margin-right: 1em;
text-align: right;
}
-->
</style>

</head>
<body>
<h3> Customer Details</h3>

<?php
/* Loop that displays the form fields */
/* print_r ($customer);*/


while ($customer = mysqli_fetch_array($result, MYSQLI_ASSOC)) {

echo "<form action = '$_SERVER[PHP_SELF]' method = 'POST'>
<div id='form'>";

foreach($labels as $field => $label)
{
echo "<div id='field'><label for='$field'>$label</label>

<input id='$field' name='$field' type='text'
size='50%' maxlength='65' value = {$customer[$field]} />

</div>n";

} /* foreach*/
echo "<input style='margin-left: 33%' type='submit' value='$submit' />n";

} /*while*/
/*echo "</div>n";*/


/* free result set */
mysqli_free_result($result);
/* close connection */
mysqli_close($cxn);

?>
</form></body></html>
No comments posted yet

Your Answer:

Login to answer
262 Like 7 Dislike
Previous forums Next forums
Other forums

parse error
On my local machine I keep getting parse error for my footer. When I put it online, it doesn't show

Php Mysql Page Loading Notice
Hi all,

I was wondering if there is a way (Sure there is) of showing a message or an image wh

Pagination
Hi All,

I think I'm finally getting somewhere with pagination!

I can now submit a quer

How to return to a previous page after running a PHP script
I'm having a bit of a melt down here because I think this should be really easy but can't work it ou

Multi image upload
I have a gallery to build and want to build a dynamic upload form to allow for $var number of fields

Handling text changed in text box control using Ajax
I need to create a web form with a text box control. When someone types text into the textbox I nee

Problem displaying "scraped" XML data
I'm basicly having trouble displaying XML data scraped from an URL using cURL.

What the code

value not going in data base
hello friends....
i am having a working javascript....when i am selecting any

PHP error (line 38) my website
Hello everyone, I'm new on this
and I got a web site thats got a error not showing the photos on<

links using header()
Hi All

I'm not sure where to ask for help on this but I hope someone can offer some. I'm at

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash