php is not recognized as an internal or external command


Posted on 16th Feb 2014 07:03 pm by admin

Hello,

I am trying to bake the code in CakePHP through my console.
I have changed my Path in Environment Variables but still I am getting this error in console "php is not recognized as an internal or external command". I have tried it to set as C:wampphp and C:wampbinphp (as I have php directory under bin folder of www).

How can I solve this problem?

Please suggest.

No comments posted yet

Your Answer:

Login to answer
79 Like 11 Dislike
Previous forums Next forums
Other forums

Printing a webpage
I use this to print the webpage: o

Bar charts using Graphical Framework.
I am using Graphical Frameworks(GFW) to create a chart Graphic . There is no problem with the data d

Hit counter updating once per IP - IP HIT COUNTER
I have a hit counter, for the amount of views on a tutorial.
It'll do the query and then do..

Pspell with my own dictionary
Hello!
I've tested two cases using pspell functions.
1)
Code: $dictionary_link = pspell_new

PHP referral database. I would like this form to email the referrer.
Okay, Hello I've been trolling for years. This the first time I've ever asked for php help. Normally

How to login with SAPCPIC userid
I have changed the Password for SAPCPIC in Development Server for 000,001 and 100 client.
But w

php + mysql count consecutive data
I have a database of values and I want to work out how to display them if the values match a consecu

get multiple rows
Hi I want to get multiple rows from a db

I am using this for the db query
Code: public

Weird MySQL error, why am I recieving this?
PHP Code:


<?php require "global_settings.php"; ?>
<titl

Newb advice
Hi all,

I'm a flash front end designer and I've taken on a project that needs some back end p

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash