Retrieving the 25 most recently added entries from all tables in a MySQL databas
Posted on
16th Feb 2014 07:03 pm by
admin
Hello,
The code below works great. It creates a table that shows the 25 most recently added tables to a MySQL database called "sitefeather."
Each one of these tables has the following structure:
Code: id INT(11) NOT NULL auto_increment, site VARCHAR(1000) NOT NULL, action1 BIGINT(9) NOT NULL, action2 BIGINT(9) NOT NULL, createddatetime TIMESTAMP DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY(id), UNIQUE (site)
I would like to echo a list of "site" and "CURRENT_TIMESTAMP" for the 25 most recently added rows, regardless of which table they are in. This may be tricky since the number of tables is variable. Someone advised me that I would have to use a query involving INFORMATION_SCHEMA.TABLES. How can I do this?
Thanks in advance,
John
Code: echo "<table class="samples">";
$index = mysql_query("select TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_SCHEMA='sitefeather' order by CREATE_TIME desc limit 25");
while ($row = mysql_fetch_array($index))
{
echo '<tr><td><a href="sitesearch.php?find='.urlencode($row['TABLE_NAME']).'&searching=yes&search=search">'.$row['TABLE_NAME'].'</a></td></tr>';
}
echo "</table>";
No comments posted yet
Your Answer:
Login to answer
309
19
Other forums
question about stripslashes and real_escape_string
im cleaning up an old app that I wrote fixing some of the vulernabilities from attacks.
I hav
Parse String
I need to parse the string below into three variables. How would I do that?
john + 10/20/2008
Sub-domains & calling unique content
Hello,
Is there a way use something similar to the $_GET function for a sub-domain? I to be a
include problem
I have my root folder as:
Code: $root = $_SERVER["SITE_HTMLROOT"]; // the server root<
mysql select with $_get ?
Hi, i have this code:
Code: // If char id is 0 and character dont exist do:
if ($_GET["id
Uploading files/images via forms
Hey all, I am building a database for work that will contain some minor data on plant species along
PHP onsubmit in the form not going to the fuction.
I have a form through ‘onsubmit’ calling a function validation(). But not going to the
I have a parse error in this query help..
Code: $query1="INSERT INTO `rating` (`item_name`, `rating`, `ip_address`, `date_rated`) VALUES
FROM_UNIXTIME($phpdate);
Hello,
I tried to use this :
$date = FROM_UNIXTIME($phpdate);
ANd I was t
whats wrong with my code please help!!!
this is the error
Warning: mysql_close(): supplied argument is not a valid MySQL-Link res