Simple Scraper... Weird Output


Posted on 16th Feb 2014 07:03 pm by admin

Okay, maybe I just need a Blue Monster and some sleep, but....

I'm scraping a ringtone site just so that I can download all of the ringtones and add them to my personal library.

The website's code that I am targeting is:
Code: [Select]<tr><td><a href="/ringtone/527783/"><img src="/img/icon/ringt.jpg" border=0>Jackson 5 - Who's Loving You </a> </td><td align=center><a href="/ringtones/classical/" class=cat_link>Classical</a></td><td align=center><img src="/img/rating/star0.gif" border=0></td><td align="right" class=smgrey2>5 months ago</td><td align="center" class=smgrey2><span class="b">13895</span></td><td align="right"><span class="b"><a href="/profile/stambaugh01">stambaugh01</a></span></td></tr>

I would like for it to output the actual filename which in this case would be 527783. I would also like for it to output the title of the file.

There are about 50 or so listings per page, and would like for it to automatically go to the next page to scrape.

Here is my code:
Code: [Select]<?
$data = @file_get_contents("http://www.XXXXXXXXXXXX.com/ringtones/classical/");

preg_match_all('/href="/ringtone/.*?<img src="/img/icon/ringt.jpg" border=0>([^"]*).*?/"><img src="/img/icon/.*?border=0>([^"]*)</td><td align=center>/is',$data,$out);
// preg_match_all('/href="/ringtone/.*?<img src="/img/icon/ringt.jpg" border=0>([^"]*).*?/"><img src="/img/icon/.*?border=0>([^"]*)</td><td align=center>/is',$data,$out);
if ((isset($out[1]) && isset($out[2])) === FALSE) { // Let's do some error checking to see if there is data to insert into the database. If not let's end the script
break;
}
$d = array_combine($out[1], $out[2]);
// End Error Checking
foreach($d as $k=>$v){
echo $k . " --- " . $v . "
";
}
?>

The output is skipping and only outputting the title of every other row, but now directory name.

Thanks in advance for the help.

No comments posted yet

Your Answer:

Login to answer
231 Like 24 Dislike
Previous forums Next forums
Other forums

CHECH A STRING FOR ' " ' (DOUBLE QUOTES)
I am checking for delimiter (.!?) and if there is a " after a sentence then it should neglect a

getAlexaRank($url) function not working
I have made a function to get alexa rank
the site is here: http://mytestsite.rack111.com/1

mysql_real_escape_string making variable equal nothing
i post a form and i post the variable:
Code: $var = $_POST[variable];then i echo $var its what i

Get to know your fellow coder
I think it's time we got personal around here. There's a lot of code swapping and a few members kno

image upload, resize THEN submit form
Ok so I have a form that requires the user to upload an image, and then do something with that image

Running External Scripts
I am very new to PHP and am not even sure what I'm asking is possible. I have just installed mediaW

form variables from database help.
Hi all,

I would like to have a form that gives you options based on the results of an mysql q

Extracting URL pointer within XML tag
Hi.

I'm trying to extract text between two quotation marks in XML. For example, I want to ex

session variables not working anymore
hello,
i use sessions to handle authentication within my site. my host has been changing a lot of

PHP IMAGE UPLOAD SCRIPT
Hi for the last week i have been looking for scripts that will upload a photo to a certain folder wh

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash