SQL Query/echo not working
Posted on
16th Feb 2014 07:03 pm by
admin
Hey all,
I'm trying to run (what I thought) was a simple operation and it isn't working. I haven't coded anything in about 2 years, and I'm self taught at that so I know I've got quite a few gaps in my knowledge base.
Did you know?Explore Trending and Topic pages for more stories like this.
Here's what is running right now:
Code: <?php
$con = mysql_connect("localhost","adminaccount","adminpassword");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("mornin14_idiot2009", $con);
$id = $_GET['id'];
$query = "SELECT * FROM idiot WHERE index = '15'"; //I want this to say WHERE index = $id, but I'm testing this with just a #
$result = mysql_query($query);
$numrows = mysql_num_rows($result);
for ($x=0; $x<$numrows; $x++){
$result_row = mysql_fetch_row($result);
echo $result_row[0];
echo "<br />";
echo $result_row[1];
echo "<br />";
echo $result_row[3];
echo "<br />";
echo $result_row[5];
echo "<br />";
}
?>
Now it should only be returning one row since I'm checking for a specific index #.
When I just do a basic select * from idiot and omit the where clause, it works fine and dumps the whole table in the for loop. But if I try a specific where, it falls apart. Any help would be greatly appreciated.
No comments posted yet
Your Answer:
Login to answer
196
44
Other forums
losing variables between php brackets
Hi
have got this code:
Code: $id=mysql_result($result,0,"itemid");
$title=mys
! = ''
In the following 'IF' statement if v_ompcat = PU for example then Oracle equates that 'IF' statement
str_replace help
Hey there,
I'm a PHP newb, I'm having troubles with the str_replace function. I want to clean
Giving the below syntax error
Dear Experts,
I have used 2 buttons in gui status as display and cjhange.When the user wi
Update not working ... please help
Hi,
I am trying to update a row using an edit form by passing id of the row .. but it is not
j1inmis Ouput layout changes
Hi,
Can anybody tell how can j1inmis output layout can be changed so that vendor names ge
user validation always displaying invalid ? please help
Hello,
I have 2 accounts and there is a field in mysql called validated it can be either &quo
Email with Attachments in PHP
Hi Friends
How to send email in PHP with attachment.
I know simple mail can be sent with
please help me in this update statment
hi every one
if I have table and this data in it
id name
10
mysql_real_escape_string making variable equal nothing
i post a form and i post the variable:
Code: $var = $_POST[variable];then i echo $var its what i