Turning Data into URLs?


Posted on 16th Feb 2014 07:03 pm by admin

This may seem very basic to you, but I'm having a hard time figuring out how to do this since I don't even know what the proper term for it is:

Background info:
Animals Table - animalid, name, photo, achievementname, price, resale, levelid, description
Achievement Table - achievementid, achievementname, photo, xprequired, rewardname, description
Levels Table - levelsid, name, xprequired, description
Rewards Table - rewardid, rewardname, desciption

What I want to do is have my animals.php page pull up the MySQL Animals Table (already done) and have all the animal's achievementsid values link to a new page detailing that specific achievement (achievement.php). In turn, that achievement page would show the rewardid value that would link to a page detailing that specific reward (reward.php)

Example:
Animals.php shows a table with:
1-Horse--horse.png-Yee Haw!-1,000$-250$-1-A horse is a horse of course!

I want Yee Haw! to display as a link that would open up a php page that would show information relating to that specific achievement, ignoring all other achievements.

This would work in the same vein as this website: http://farmville.aweblog.net/almanac/animals/all-animals

I assume in being correct that I would have to call the result of that value into a variable that would be passed on as a cookie to another php file but I have not idea where or how to start on that.

My loop looks like this (shortened due to repetition):
while($row = mysql_fetch_array($result)){
echo "<tr>";
echo "<td>" .$row['idAnimal']. "</td>";
echo "<td><img src='".$url.$row['photoAnimal']."' height='50px' width='50px'></td>";
echo "<td>" .$row['nameAnimal']. "</td>";
echo "<td>" .$row['nameCategory']. "</td>";
echo "</tr>";
}


Assuming I wanted each animal name to link to a detailed animal page, what would I do? Can anyone give me some pointers or point me to a good resource for this kind of information? Googling is pointless as I don't know what terms I should be using...
Thanks

No comments posted yet

Your Answer:

Login to answer
54 Like 6 Dislike
Previous forums Next forums
Other forums

Querying info from one table based on info in another
Hi, I am currently trying to make a part for my user driven website where one user can subscribe to

Unable to display contents in Second Drop Down Box
Hi All,

What I am trying to do is 2 dependent drop down boxes and when user selects su

Load file in PHP
I have 2 files. The first is a PHP generated XML file that's dependent by 2 inputs. The second is a

Undefined offset when using a flat file with pipe symbols
Hi, I've got a flat file/text file which I'm currently using as a member database for my site (not a

quick question
Hi ..

i have a question
how do i set a var so it displays via an echo
Code: $logo = '&a

How can I Compare two xml documents?
Hi all,

I am doing a POC for my project and I am using XE database 10g version.

dropdown menu
Hello everbody,

I am php newbie.
I need to develop a program that once click the drop do

get url?
how do i get the url of the page i'm currently on, on my website.. i think its get header.. how do i

Different actions for different parts of a string
<?php
function dosomething($string, $else = '') {
if (empty($else))
$string

how do i display data on a page from mysql
1 - do i use this code at the top of each of my page i wish to only alow access if there as been a s

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash