Turning Data into URLs?
Posted on
16th Feb 2014 07:03 pm by
admin
This may seem very basic to you, but I'm having a hard time figuring out how to do this since I don't even know what the proper term for it is:
Background info:
Animals Table - animalid, name, photo, achievementname, price, resale, levelid, description
Achievement Table - achievementid, achievementname, photo, xprequired, rewardname, description
Levels Table - levelsid, name, xprequired, description
Rewards Table - rewardid, rewardname, desciption
What I want to do is have my animals.php page pull up the MySQL Animals Table (already done) and have all the animal's achievementsid values link to a new page detailing that specific achievement (achievement.php). In turn, that achievement page would show the rewardid value that would link to a page detailing that specific reward (reward.php)
Example:
Animals.php shows a table with:
1-Horse--horse.png-Yee Haw!-1,000$-250$-1-A horse is a horse of course!
I want Yee Haw! to display as a link that would open up a php page that would show information relating to that specific achievement, ignoring all other achievements.
This would work in the same vein as this website: http://farmville.aweblog.net/almanac/animals/all-animals
I assume in being correct that I would have to call the result of that value into a variable that would be passed on as a cookie to another php file but I have not idea where or how to start on that.
My loop looks like this (shortened due to repetition):
while($row = mysql_fetch_array($result)){
echo "<tr>";
echo "<td>" .$row['idAnimal']. "</td>";
echo "<td><img src='".$url.$row['photoAnimal']."' height='50px' width='50px'></td>";
echo "<td>" .$row['nameAnimal']. "</td>";
echo "<td>" .$row['nameCategory']. "</td>";
echo "</tr>";
}
Assuming I wanted each animal name to link to a detailed animal page, what would I do? Can anyone give me some pointers or point me to a good resource for this kind of information? Googling is pointless as I don't know what terms I should be using...
Thanks
No comments posted yet
Your Answer:
Login to answer
54
6
Other forums
Querying info from one table based on info in another
Hi, I am currently trying to make a part for my user driven website where one user can subscribe to
Unable to display contents in Second Drop Down Box
Hi All,
What I am trying to do is 2 dependent drop down boxes and when user selects su
Load file in PHP
I have 2 files. The first is a PHP generated XML file that's dependent by 2 inputs. The second is a
Undefined offset when using a flat file with pipe symbols
Hi, I've got a flat file/text file which I'm currently using as a member database for my site (not a
quick question
Hi ..
i have a question
how do i set a var so it displays via an echo
Code: $logo = '&a
How can I Compare two xml documents?
Hi all,
I am doing a POC for my project and I am using XE database 10g version.
dropdown menu
Hello everbody,
I am php newbie.
I need to develop a program that once click the drop do
get url?
how do i get the url of the page i'm currently on, on my website.. i think its get header.. how do i
Different actions for different parts of a string
<?php
function dosomething($string, $else = '') {
if (empty($else))
$string
how do i display data on a page from mysql
1 - do i use this code at the top of each of my page i wish to only alow access if there as been a s