User input in to variable

Posted on 16th Feb 2014 07:03 pm by admin

Hi all,

I'm sure this is very easy but I'm having another brain freeze!

At the end of the code I have echoed 3 bits of info to screen $ip, $_POST['ssid'] and $ssid_id".

I would like to put $_POST['ssid'] into a variable, is this possible?

Jamie

Code: <?php
//run site query
require("confwifi.php") ;
{
$ext_site = $_POST['site'];

$extract = mysql_query ("SELECT * FROM site WHERE site='$ext_site'");
$numrows = mysql_num_rows ($extract);

while ($row = mysql_fetch_assoc($extract))
{
$id = $row['id'];
$site = $row['site'];
$ip = $row['ip'];
}

}

?>

<?php
//run site query
require("confwifi.php") ;
{
$ext_ssid = $_POST['ssid_name'];

$extract = mysql_query ("SELECT * FROM ssid WHERE ssid_name='$ext_ssid'");
$numrows = mysql_num_rows ($extract);

while ($row = mysql_fetch_assoc($extract))
{
$ssid_id = $row['ssid_id'];
$ssid_name = $row['ssid_name'];

}

}

?>


<form name="form1" method="POST" action="wifichange.php"><div>

<select name="site">
<option value="0" selected>(please select:)</option>
<option name="site">Llandaf</option>
<option name="site">Cyncoed</option>
<option name="site">Howard Gardens</option>
<option name="site">Colchester Avenue</option>
</select>


<select name="ssid_name">
<option value="0" selected>(please select:)</option>
<option name="ssid_name">Guest</option>
<option name="ssid_name">Conferences</option>
</select>
</form>
<p><input type="text" name="ssid"></div></P>

<div><input type="submit" value="submit"></div>
</form>




<?php echo "$ip"; ?><p></p>

<?php echo $_POST['ssid'];; ?><p></p>

<?php echo "$ssid_id"; ?><p></p>

<?php

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