Variable uses and placement
Posted on
16th Feb 2014 07:03 pm by
admin
I'm new to PL/SQL and am trying to learn about variable valid uses/placement (any pointers to any docs is appreciated...)
All of the docs I've looked only mention declaration and assignment not valid placement.
When I use an input parameter to a cursor placement matters . I just don't understand why...
example... using the value "SCOTT" as an input parm to the c10 cursor replaces the "str_in" variable correctly and works...
1 declare
2 cursor c10(str_in IN varchar2) is
3 select username
4 from dba_users where username=str_in ;
5 begin
6 for r_c10 in c10('SCOTT') loop
7 dbms_output.put_line(r_c10.username);
8 end loop;
9* end;
SQL> /
SCOTT
PL/SQL procedure successfully completed.
However, when trying to replace another "word" it won't resolve the reference...
example... attempting to replace the from table_name as an input parm, no go...
1 declare
2 cursor c10(str_in IN varchar2) is
3 select username
4 from str_in where username='SCOTT' ;
5 begin
6 for r_c10 in c10('DBA_USERS') loop
7 dbms_output.put_line(r_c10.username);
8 end loop;
9* end;
SQL> /
from str_in where username='SCOTT' ;
*
ERROR at line 4:
ORA-06550: line 4, column 6:
PL/SQL: ORA-00942: table or view does not exist
ORA-06550: line 3, column 1:
PL/SQL: SQL Statement ignored
ORA-06550: line 7, column 26:
PLS-00364: loop index variable 'R_C10' use is invalid
ORA-06550: line 7, column 5:
PL/SQL: Statement ignored
Why can't it resolve the string ?
Any help is appreciated
dumb newbie...
No comments posted yet
Your Answer:
Login to answer
344
49
Other forums
Why is my row count 0?
Here's the MySQL query i'm running. It basically pulls data from 2 tables based on some data passed.
How can use this array as a key?
Say I have this array for example:
print_r($array);
Prints:
Code: [Select]Array
2 things: enter doesn't work in IE & empty form
i have this search form that works well except for 2 things.
1) on IE when i hit enter instea
upload image name with extension using php
hi frds..
<input id="file1" type="file" name="file[]" &a
Else statement screws up all css
Does anyone know what goes wrong in the process with this php code?
This code seems to be causing
Creating a custom API
I'm creating a site, and I need to create a basic API. Unfortunately I have no idea where to start.
New to Arrays
Hi I am new to PHP (a week and a half now) and I am just beginning to read about arrays. I understan
Displaying image pathname instead of image
Hello
Im trying to upload and then display images from a mysql database - Its only basic and
try catch error
I have been trying try catch but, I can't get it to work. The code opens a non existing file called
Ajax Error since Upgrading to 3.5
Ever since upgrading my site to .NET 3.5 (I needed LINQ), I've been getting this annoying error on o