What are causes of a connection-timeout with fopen()?


Posted on 16th Feb 2014 07:03 pm by admin

Hello! Here is the situation: The server I host my website on just upgraded it's PHP build from 4.4.* to 5.2.4. Not just PHP was upgraded, MySQL, postGres, and (I think) Apache were upgraded as well. Before the upgrade, my site worked perfectly.

But now, whenever I access my site, it takes a long time to complete a request and all that is returned is "Warning: fopen(<THE_URL>) [function.fopen]: failed to open stream: Connection timed out in..."

Did you know?Explore Trending and Topic pages for more stories like this.
I know where the error is -- it's in my templating class. I check the remote server's configuration and the directive "allow_url_fopen is enabled and safe_mode is disabled.

The strange thing is that my script works on my local server perfectly which is using PHP build 5.2.5. I looked for any differences between my local-server's PHPINFO() and my remote-server's PHPINFO() and, while I didn't find anything eye-catching yet, I noticed that virtual-directory-support is disabled on my remote-server and it is enabled on my local-server. Would that be what's causing the problem? If not, what are some potential causes for fopen() to behave this way?
No comments posted yet

Your Answer:

Login to answer
228 Like 12 Dislike
Previous forums Next forums
Other forums

Multithreading design
Hi

I have come up with a Singleton class that manages a pool of database connections. Basical

login from external site
Hi my new experience begins, Now what i am trying to do is i make three pages, login.php logout.php

Final year project, please point me in the right direction
hi there for my final year project I'm aiming to build a php script shell to use as an expert system

dropdown box help - open php files to textarea
Hi, I am using tinymce to edit content located in several php files. The code I attached works but i

Strip Slashes Help
I've got a script that i've downloaded of the net to edit multiple fields from my sql database, and

Variable passed to each() is not an array or object
Hi,

This is a email a friend type of form, and it isn't working anymore.

<?

if else problem, help please
i have this script that i made only i try to also put in a if else for for some reason the script is

Include a php
Hello,

I'm trying to include a function that shows the recent searches.
Example I have <

Breaking results into week blocks
I have a set of dates (and times), which are returned from a mySQL query.

These usually span

Echo-ing MySQL content and Keep Formatting?
I have data in my MySQL such as:

QuoteBlah blah

Blah blah

etc
but when i ech

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash