What are causes of a connection-timeout with fopen()?
Posted on
16th Feb 2014 07:03 pm by
admin
Hello! Here is the situation: The server I host my website on just upgraded it's PHP build from 4.4.* to 5.2.4. Not just PHP was upgraded, MySQL, postGres, and (I think) Apache were upgraded as well. Before the upgrade, my site worked perfectly.
But now, whenever I access my site, it takes a long time to complete a request and all that is returned is "Warning: fopen(<THE_URL>) [function.fopen]: failed to open stream: Connection timed out in..."
Did you know?Explore Trending and Topic pages for more stories like this.
I know where the error is -- it's in my templating class. I check the remote server's configuration and the directive "allow_url_fopen is enabled and safe_mode is disabled.
The strange thing is that my script works on my local server perfectly which is using PHP build 5.2.5. I looked for any differences between my local-server's PHPINFO() and my remote-server's PHPINFO() and, while I didn't find anything eye-catching yet, I noticed that virtual-directory-support is disabled on my remote-server and it is enabled on my local-server. Would that be what's causing the problem? If not, what are some potential causes for fopen() to behave this way?
No comments posted yet
Your Answer:
Login to answer
228
12
Other forums
WORDPRESS - Multiple Loops Only Going to One Post?
I have various pages with multiple loops and i need them to be individual to all other categories.
Undefined variables
hi
----------------------------------------------------------------------------------------------
Where do I put CRON code
So I've figured out alot about how to automatically run a php function. I can't figure out where to
CHECH A STRING FOR ' " ' (DOUBLE QUOTES)
I am checking for delimiter (.!?) and if there is a " after a sentence then it should neglect a
how to get sn motherboard
Hello.
I want to get serial number motherboard, cpu and else hardware.
Can You show me sam
quick question
Hi ..
i have a question
how do i set a var so it displays via an echo
Code: $logo = '&a
removing space from the end of a variable
i have a variable $image which contains the following url "http://tiles.xbox.com/tiles/oo/P5/0m
str_replace help
Hey there,
I'm a PHP newb, I'm having troubles with the str_replace function. I want to clean
upload control not working with update panel
Hi,
I am working with Asp.Net FileUpload control with ajax update panel,
if i use the
php web service error
hey guys,
I'm working on a project requires the use of web services. I've been trying a few tutor