What are causes of a connection-timeout with fopen()?


Posted on 16th Feb 2014 07:03 pm by admin

Hello! Here is the situation: The server I host my website on just upgraded it's PHP build from 4.4.* to 5.2.4. Not just PHP was upgraded, MySQL, postGres, and (I think) Apache were upgraded as well. Before the upgrade, my site worked perfectly.

But now, whenever I access my site, it takes a long time to complete a request and all that is returned is "Warning: fopen(<THE_URL>) [function.fopen]: failed to open stream: Connection timed out in..."

I know where the error is -- it's in my templating class. I check the remote server's configuration and the directive "allow_url_fopen is enabled and safe_mode is disabled.

The strange thing is that my script works on my local server perfectly which is using PHP build 5.2.5. I looked for any differences between my local-server's PHPINFO() and my remote-server's PHPINFO() and, while I didn't find anything eye-catching yet, I noticed that virtual-directory-support is disabled on my remote-server and it is enabled on my local-server. Would that be what's causing the problem? If not, what are some potential causes for fopen() to behave this way?

No comments posted yet

Your Answer:

Login to answer
228 Like 12 Dislike
Previous forums Next forums
Other forums

Need help in log in and log out?
hi there all of u. i have recently created a site for someone. i have placed log in and log out and

pagination - need help on passing of search query.
Hi, i have been trying for days but couldn't get this sorted out. Would like some professional help

Optimize Code
Just started getting into the use of cookies. The following code will redirect users to a set URL s

$variable = $variable
Hello

Sorry if this is a really simple question but I have run out of ideas. Is there a reall

explode() function problem maybe
Hi I'm having trouble searching my database. When I type two words in the search field it only searc

Problem!
I have another problem, when i run this code i get this error "Parse error: syntax error, unexp

array ...
hi
Code: function formatCategories($categories, $parentId)
{
// $navCat stores all child

help with Get_
ok some how this is not working i am not sure what i am doing wrong here but what this does is when

Accessing Infotype data in dialog program
Hi All
In Dialog programs attributes I didn't see any logical database field. How can I access

Get keys and values from an array
Hellow,

I have an array $Data with keys and values. With a foreach I can display all the valu

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash