Return X values where an ID number doesnt matter


Posted on 16th Feb 2014 07:03 pm by admin

Well as for subject heading, thats the best i could think of.

Currently im having a problem with a rather old piece of script i had written for a guestbook.
The guestbook itself relies completely on the `id` field of the table to show the posts.
Did you know?Explore Trending and Topic pages for more stories like this.
But if a post is deleted, then it screws up the pagination of the posts such that if you were to click "next page" the same results as the last page would show.

The query:
Line number On/Off | Expand/Contract$set = $numAllResults-$offset+1;SELECT * FROM `posts` WHERE `id` <= '$set' ORDER BY `id` DESC

This query works wonders if every entry in the table is only incremented by 1, but breaks when an entry of 'X' does not exist. ie. it skips post 'X' but also shows older posts based on the newest entry. As i know this isnt clear, let me clear it up with an example:
Line number On/Off | Expand/Contracttable - `posts``id`, `name`, `post`1,'Joe','Hi there'2,'Johanna','Love the guest book'3,'Jeff','Great stuff'4,'James','Could have more stuff'8,'John','Excellent!'9,'Joel','Not bad'

As you can see, there are 3 entries missing because they were deleted.
As it stands, there should be 2 pages in the guestbook because there are more than 5 entries.
However, the first page will show entries:
9,8,4,3,2.
The second page:
8,4,3,2,1

Now in this example, the problem isnt too huge, although when i have say 20 entries with half deleted, it will show the same posts for about 4 pages, and then change after the $set is lower than the older posts.

Yes i am posting my code, but, this was written over a year ago now, so i know i am breaking some of my own today's standards for programming Im just looking for a fix so that when items are deleted it will still show everything properly.

Line number On/Off | Expand/Contract<?phpinclude_once("include/connect.php");$guestbookconnect = connect();mysql_select_db("alexast_db",$guestbookconnect);$offset = $_GET['p'];if(!$_GET['p']){$offset = 0;}if($offset < 0){print "<script>window.location = 'guestbook.php';</script>";}$results = 5; //display number of results per page.$currentresults = 0; $getAllPostsSQL = "SELECT * FROM `posts` ORDER BY `id` DESC";$getAllPostsQuery = mysql_query($getAllPostsSQL, $guestbookconnect) or die(mysql_error($guestbookconnect));$numAllResults = mysql_num_rows($getAllPostsQuery); $set = $numAllResults-$offset+1;$getPostsSQL = "SELECT * FROM `posts` WHERE `id` <= '$set' ORDER BY `id` DESC";$getPostsQuery = mysql_query($getPostsSQL, $guestbookconnect) or die(mysql_error($guestbookconnect));$numResults = mysql_num_rows($getPostsQuery); while($getPostsResult = mysql_fetch_assoc($getPostsQuery)){$currentresults++; if($currentresults <= $results){?> <div class="guestbook_frame"> <div class="guestbook_box1"> <div id="style_name"><?php print $getPostsResult['name']; ?></div> </div> <div class="guestbook_box2"> <div id="style_date"><?php print $getPostsResult['date']; ?></div> </div> <div class="guestbook_box3"> </div> <div class="guestbook_box4"> <div id="style_content"><?php print $getPostsResult['content']; ?></div> </div> </div><?php }}mysql_close($guestbookconnect);?>
No comments posted yet

Your Answer:

Login to answer
188 Like 47 Dislike
Previous forums Next forums
Other forums

Echoing If Function?
A script I am using has If statements in the comments form to basically tell the form what to do. Cu

redirect standard error and assert (how to?)
How do you redirect standard error and assert?

---

(Why? I am creating an web app and

PHP form help required
Hi all! Apologies in advance for having to message the forum for help. I know you must get a lot of

This is driving me nuts!
This insert query looks to be alright, however I get this error:

QuoteYou have an error in yo

PHP - MySQL Fail
My PHP code will only execute the first part of my code...

Code: <?php

sessio

PHP error. Need help urgently
Hi,

I am programming a php site and have a problem that i just cant find out how to fix. When

ImageCreate()
When I create an image and add text to it I want my text to be replaced with a PNG image, because th

finding key position of specified value in multi-dimensional array
Code: $openedfile = fopen($tfc_file4, "r");
$rc = 1;
while(!feof($openedfile))
{<

Unable to retreve the values from Mysql Query
Hi,

Here is the php code that I have, Query is running properly in phpmyadmin and is resu

listcube issue
Hi
I have a virtual cube ZREMOTE. I use Tcode "listcube" to retrieve contents. I use of the

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash